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Resistivity Using Load Current (2-phase 4-wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
resistivity = Area Of 2-Φ 4-wire system*Line Losses/(2*(Current Of 2-Φ 4-wire system^2)*Length)
ρ = a7*W/(2*(C7^2)*l)
This formula uses 4 Variables
Variables Used
Area Of 2-Φ 4-wire system - The Area Of 2-Φ 4-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Current Of 2-Φ 4-wire system - Current Of 2-Φ 4-wire system the time rate of flow of charge through a cross-sectional area. (Measured in Ampere)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Area Of 2-Φ 4-wire system: 7 Square Meter --> 7 Square Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Current Of 2-Φ 4-wire system: 8 Ampere --> 8 Ampere No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ρ = a7*W/(2*(C7^2)*l) --> 7*0.6/(2*(8^2)*3)
Evaluating ... ...
ρ = 0.0109375
STEP 3: Convert Result to Output's Unit
0.0109375 Ohm Meter --> No Conversion Required
FINAL ANSWER
0.0109375 Ohm Meter <-- Resistivity
(Calculation completed in 00.031 seconds)

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11 Other formulas that calculate the same Output

Resistivity Using Volume Of Conductor Material (DC 3-wire)
resistivity = Volume*Line Losses*(Max voltage^2)/((0.3125)*(Power Transmitted^2)*(Length^2)) Go
Resistivity Using K(Two-Wire One Conductor Earthed)
resistivity = Constant*Line Losses*(Max voltage^2)/(4*(Power Transmitted^2)*(Length^2)) Go
Resistivity Using Volume(Two-Wire One Conductor Earthed)
resistivity = Volume*Line Losses*(Max voltage^2)/(4*(Power Transmitted^2)*(Length^2)) Go
Resistivity Using Constant(DC 3-wire)
resistivity = Constant*Line Losses*(Max voltage^2)/((Power Transmitted^2)*(Length^2)) Go
Resistivity Using Line Losses(Two-Wire Mid-point Earthed)
resistivity = (Max voltage^2)*Line Losses*2*Area/((Power Transmitted^2)*Length) Go
Resistivity Using Line Losses(DC 3-wire)
resistivity = (Line Losses*Area Of 3-wire DC system)/(2*Length*(Current Of 3-wire DC system^2)) Go
Resistivity Using Area Of X-section(Two-Wire One Conductor Earthed)
resistivity = (Line Losses*Area Of 2-wire system)/(2*Length*(Current Of 2-wire DC system^2)) Go
Resistivity of the material
resistivity = (2*[Mass-e])/(Number of free charge particles per unit volume*[Charge-e]^2*Relaxation time) Go
Resistivity Using Line Losses(Two-Wire One Conductor Earthed)
resistivity = (Line Losses*Area)/(2*Length*(Current Of 2-wire DC system^2)) Go
Resistivity
resistivity = Resistance*Cross sectional area/Length Go
Resistivity Using Resistance(Two-Wire One Conductor Earthed)
resistivity = Resistance*Area/Length Go

Resistivity Using Load Current (2-phase 4-wire US) Formula

resistivity = Area Of 2-Φ 4-wire system*Line Losses/(2*(Current Of 2-Φ 4-wire system^2)*Length)
ρ = a7*W/(2*(C7^2)*l)

What is the value of maximum voltage in 2-phase 4-wire underground system?

The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Resistivity Using Load Current (2-phase 4-wire US)?

Resistivity Using Load Current (2-phase 4-wire US) calculator uses resistivity = Area Of 2-Φ 4-wire system*Line Losses/(2*(Current Of 2-Φ 4-wire system^2)*Length) to calculate the Resistivity, The Resistivity Using Load Current (2-phase 4-wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity and is denoted by ρ symbol.

How to calculate Resistivity Using Load Current (2-phase 4-wire US) using this online calculator? To use this online calculator for Resistivity Using Load Current (2-phase 4-wire US), enter Area Of 2-Φ 4-wire system (a7), Line Losses (W), Current Of 2-Φ 4-wire system (C7) and Length (l) and hit the calculate button. Here is how the Resistivity Using Load Current (2-phase 4-wire US) calculation can be explained with given input values -> 0.010938 = 7*0.6/(2*(8^2)*3).

FAQ

What is Resistivity Using Load Current (2-phase 4-wire US)?
The Resistivity Using Load Current (2-phase 4-wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = a7*W/(2*(C7^2)*l) or resistivity = Area Of 2-Φ 4-wire system*Line Losses/(2*(Current Of 2-Φ 4-wire system^2)*Length). The Area Of 2-Φ 4-wire system is the amount of two-dimensional space taken up by an object, Line Losses is defined as the losses that are produced in the line, Current Of 2-Φ 4-wire system the time rate of flow of charge through a cross-sectional area and Length is the measurement or extent of something from end to end.
How to calculate Resistivity Using Load Current (2-phase 4-wire US)?
The Resistivity Using Load Current (2-phase 4-wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using resistivity = Area Of 2-Φ 4-wire system*Line Losses/(2*(Current Of 2-Φ 4-wire system^2)*Length). To calculate Resistivity Using Load Current (2-phase 4-wire US), you need Area Of 2-Φ 4-wire system (a7), Line Losses (W), Current Of 2-Φ 4-wire system (C7) and Length (l). With our tool, you need to enter the respective value for Area Of 2-Φ 4-wire system, Line Losses, Current Of 2-Φ 4-wire system and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Resistivity?
In this formula, Resistivity uses Area Of 2-Φ 4-wire system, Line Losses, Current Of 2-Φ 4-wire system and Length. We can use 11 other way(s) to calculate the same, which is/are as follows -
  • resistivity = (2*[Mass-e])/(Number of free charge particles per unit volume*[Charge-e]^2*Relaxation time)
  • resistivity = Resistance*Cross sectional area/Length
  • resistivity = Resistance*Area/Length
  • resistivity = (Line Losses*Area)/(2*Length*(Current Of 2-wire DC system^2))
  • resistivity = Volume*Line Losses*(Max voltage^2)/(4*(Power Transmitted^2)*(Length^2))
  • resistivity = Constant*Line Losses*(Max voltage^2)/(4*(Power Transmitted^2)*(Length^2))
  • resistivity = (Line Losses*Area Of 2-wire system)/(2*Length*(Current Of 2-wire DC system^2))
  • resistivity = (Max voltage^2)*Line Losses*2*Area/((Power Transmitted^2)*Length)
  • resistivity = (Line Losses*Area Of 3-wire DC system)/(2*Length*(Current Of 3-wire DC system^2))
  • resistivity = Volume*Line Losses*(Max voltage^2)/((0.3125)*(Power Transmitted^2)*(Length^2))
  • resistivity = Constant*Line Losses*(Max voltage^2)/((Power Transmitted^2)*(Length^2))
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