Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US) Calculator

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume Of Conductor [V]			+10% -10%
✖Line Losses is defined as the losses that are produced in the line.ⓘ Line Losses [P_line]			+10% -10%
✖Current underground DC is defined as the current flowing through the overhead ac supply wire.ⓘ Current underground DC [C₁]			+10% -10%
✖Length of Wire DC is the measurement or extent of something from end to end.ⓘ Length of Wire DC [l]			+10% -10%

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US) [ρ]

⎘ Copy

👎

Formula

✖

Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US)

Formula

`"ρ" = ("V"*"P"_{"line"}/(4*("C"_{"1"}^2)*("l"^2)))`

Example

`"0.056966Ω*m"=("35m³"*"0.6W"/(4*(("3A")^2)*(("3.2m")^2)))`

Calculator

LaTeX

Reset

👍

Download Power System Formula PDF PDF Image

Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Resistivity = (Volume Of Conductor*Line Losses/(4*(Current underground DC^2)*(Length of Wire DC^2)))
ρ = (V*P_line/(4*(C₁^2)*(l^2)))
This formula uses 5 Variables

Variables Used

Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Current underground DC - (Measured in Ampere) - Current underground DC is defined as the current flowing through the overhead ac supply wire.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.

STEP 1: Convert Input(s) to Base Unit

Volume Of Conductor: 35 Cubic Meter --> 35 Cubic Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Current underground DC: 3 Ampere --> 3 Ampere No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ρ = (V*P_line/(4*(C₁^2)*(l^2))) --> (35*0.6/(4*(3^2)*(3.2^2)))

Evaluating ... ...

ρ = 0.0569661458333333

STEP 3: Convert Result to Output's Unit

0.0569661458333333 Ohm Meter --> No Conversion Required

FINAL ANSWER

0.0569661458333333 ≈ 0.056966 Ohm Meter <-- Resistivity

(Calculation completed in 00.020 seconds)

You are here -

Home » Engineering » Electrical » Power System » Underground DC Supply » 2-Wire Mid-Point Earthed System » Power & Resistivity » Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US)

Credits

Created by Urvi Rathod

Vishwakarma Government Engineering College (VGEC), Ahmedabad

Urvi Rathod has created this Calculator and 1500+ more calculators!

Verified by Kethavath Srinath

Osmania University (OU), Hyderabad

Kethavath Srinath has verified this Calculator and 1200+ more calculators!

< 5 Power & Resistivity Calculators

Power Transmitted using Area of X-Section (2-Wire Mid-Point Earthed DC US)

Go Power Transmitted = sqrt(Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*Resistivity*Length of Wire DC))

Power Transmitted using Volume of Conductor Material (2-Wire Mid-Point DC US)

Go Power Transmitted = sqrt(Volume Of Conductor*Line Losses*(Maximum Voltage^2)/(4*Resistivity*(Length of Wire DC^2)))

Resistivity using Area of X-Section (2-wire Mid-point earthed DC US)

Go Resistivity = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*(Power Transmitted^2)*Length of Wire DC)

Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US)

Go Resistivity = (Volume Of Conductor*Line Losses/(4*(Current underground DC^2)*(Length of Wire DC^2)))

Power Transmitted using Load Current (2-Wire Mid-Point DC US)

Go Power Transmitted = Current underground DC*Maximum Voltage

Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US) Formula

Resistivity = (Volume Of Conductor*Line Losses/(4*(Current underground DC^2)*(Length of Wire DC^2)))
ρ = (V*P_line/(4*(C₁^2)*(l^2)))

Does resistivity change with length?

Resistivity is an intrinsic property of any material. It stays the same, no matter how long or thick your conductor is. Temperature coefficient*original resistivity*change in temperature. So there is no change with length in resistivity but resistance changes in direct proportion with length of the conductor.

How to Calculate Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US)?

Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US) calculator uses Resistivity = (Volume Of Conductor*Line Losses/(4*(Current underground DC^2)*(Length of Wire DC^2))) to calculate the Resistivity, The Resistivity using Volume of Conductor Material (2-wire Mid-point DC US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to calculate Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US) using this online calculator? To use this online calculator for Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US), enter Volume Of Conductor (V), Line Losses (P_line), Current underground DC (C₁) & Length of Wire DC (l) and hit the calculate button. Here is how the Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US) calculation can be explained with given input values -> 0.056966 = (35*0.6/(4*(3^2)*(3.2^2))).

FAQ

What is Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US)?

The Resistivity using Volume of Conductor Material (2-wire Mid-point DC US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = (V*P_line/(4*(C₁^2)*(l^2))) or Resistivity = (Volume Of Conductor*Line Losses/(4*(Current underground DC^2)*(Length of Wire DC^2))). Volume Of Conductor the 3-dimensional space enclosed by a conductor material, Line Losses is defined as the losses that are produced in the line, Current underground DC is defined as the current flowing through the overhead ac supply wire & Length of Wire DC is the measurement or extent of something from end to end.

How to calculate Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US)?

The Resistivity using Volume of Conductor Material (2-wire Mid-point DC US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using Resistivity = (Volume Of Conductor*Line Losses/(4*(Current underground DC^2)*(Length of Wire DC^2))). To calculate Resistivity using Volume of Conductor Material (2-Wire Mid-Point DC US), you need Volume Of Conductor (V), Line Losses (P_line), Current underground DC (C₁) & Length of Wire DC (l). With our tool, you need to enter the respective value for Volume Of Conductor, Line Losses, Current underground DC & Length of Wire DC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Resistivity?

In this formula, Resistivity uses Volume Of Conductor, Line Losses, Current underground DC & Length of Wire DC. We can use 1 other way(s) to calculate the same, which is/are as follows -

Resistivity = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*(Power Transmitted^2)*Length of Wire DC)

Home

FREE PDFs

🔍 Search