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Short diameter of double cycloid given perimeter Solution

STEP 0: Pre-Calculation Summary
Formula Used
diameter = 4*(Perimeter/16)
d = 4*(P/16)
This formula uses 1 Variables
Variables Used
Perimeter - The perimeter of a figure is the total distance around the edge of the figure. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Perimeter: 20 Meter --> 20 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
d = 4*(P/16) --> 4*(20/16)
Evaluating ... ...
d = 5
STEP 3: Convert Result to Output's Unit
5 Meter --> No Conversion Required
FINAL ANSWER
5 Meter <-- Diameter
(Calculation completed in 00.000 seconds)

11 Other formulas that you can solve using the same Inputs

Diagonal of a Rectangle when breadth and perimeter are given
diagonal = sqrt((2*(Breadth)^2)-(Perimeter*Breadth)+((Perimeter)^2/4)) Go
Diagonal of a Rectangle when length and perimeter are given
diagonal = sqrt((2*(Length)^2)-(Perimeter*Length)+((Perimeter)^2/4)) Go
Area of a Rectangle when breadth and perimeter are given
area = (Perimeter*(Breadth/2))-(Breadth)^2 Go
Area of rectangle when perimeter and breadth are given
area = (Perimeter*Breadth-2*(Breadth)^2)/2 Go
Area of a Rectangle when length and perimeter are given
area = (Perimeter*(Length/2))-(Length)^2 Go
Area of rectangle when perimeter and length are given
area = (Perimeter*Length-2*(Length)^2)/2 Go
Length of rectangle when perimeter and breadth are given
length = (Perimeter-2*Breadth)/2 Go
Breadth of rectangle when perimeter and length are given
breadth = (Perimeter-2*Length)/2 Go
Diagonal of a Square when perimeter is given
diagonal = (Perimeter/4)*sqrt(2) Go
Side of a Kite when other side and perimeter are given
side_a = (Perimeter/2)-Side B Go
Area of a Square when perimeter is given
area = (1/16)*(Perimeter)^2 Go

11 Other formulas that calculate the same Output

Circle Diameter when Maximum Permissible Eccentricity for Spiral Columns is Given
diameter = (Maximum permissible eccentricity-0.14*Overall depth of column)/(0.43*Area ratio of cross sectional area to gross area*Force ratio of strengths of reinforcements) Go
Circle Diameter when Axial Load for Spiral Columns is Given
diameter = moment/(0.12*Total area*Yield strength of reinforcing steel) Go
Diameter of Roller or Rocker for milled surface when Allowable Stress is Given for d < 635 mm
diameter = 33.33*Allowable Bearing Stresses on Pins/(yield strength of steel-13) Go
Diameter of a Rod Circular Fin when area of cross-section is Given
diameter = sqrt((Cross sectional area*4)/pi) Go
Diameter of a circle when area is given
diameter = 2*sqrt(Area of Circle/pi) Go
Diameter bisecting chords of slope m to the parabola y2 = 4ax
diameter = (2*x coordinate of focus of parabola)/Slope of Line Go
Diameter of a circle when circumference is given
diameter = Circumference of Circle/pi Go
Diameter of a Nugget
diameter = 6*(Thickness)^1/2 Go
Diameter of a circular cylinder of maximum convex surface area in a given circular cone
diameter = Radius of cone Go
Diameter of a circle when radius is given
diameter = 2*Radius Go
Diameter of Sphere
diameter = 2*Radius Go

Short diameter of double cycloid given perimeter Formula

diameter = 4*(Perimeter/16)
d = 4*(P/16)

What is a double cycloid?

In geometry, a cycloid is the curve traced by a point on a circle as it rolls along a straight line without slipping. A cycloid is a specific form of trochoid and is an example of a roulette, a curve generated by a curve rolling on another curve. The cycloid, with the cusps pointing upward, is the curve of fastest descent under constant gravity (the brachistochrone curve). It is also the form of a curve for which the period of an object in simple harmonic motion (rolling up and down repetitively) along the curve does not depend on the object's starting position (the tautochrone curve), double cycloid is a cycloid mirrored at its straight side. The double cycloid looks like a mix of ellipse and pointed oval, but it has no vertices.

How to Calculate Short diameter of double cycloid given perimeter?

Short diameter of double cycloid given perimeter calculator uses diameter = 4*(Perimeter/16) to calculate the Diameter, The Short diameter of double cycloid given perimeter formula is defined as measure of distance of the short points of double cycloid , where a = radius of double cycloid , c = base length of double cycloid. Diameter and is denoted by d symbol.

How to calculate Short diameter of double cycloid given perimeter using this online calculator? To use this online calculator for Short diameter of double cycloid given perimeter, enter Perimeter (P) and hit the calculate button. Here is how the Short diameter of double cycloid given perimeter calculation can be explained with given input values -> 5 = 4*(20/16).

FAQ

What is Short diameter of double cycloid given perimeter?
The Short diameter of double cycloid given perimeter formula is defined as measure of distance of the short points of double cycloid , where a = radius of double cycloid , c = base length of double cycloid and is represented as d = 4*(P/16) or diameter = 4*(Perimeter/16). The perimeter of a figure is the total distance around the edge of the figure.
How to calculate Short diameter of double cycloid given perimeter?
The Short diameter of double cycloid given perimeter formula is defined as measure of distance of the short points of double cycloid , where a = radius of double cycloid , c = base length of double cycloid is calculated using diameter = 4*(Perimeter/16). To calculate Short diameter of double cycloid given perimeter, you need Perimeter (P). With our tool, you need to enter the respective value for Perimeter and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Diameter?
In this formula, Diameter uses Perimeter. We can use 11 other way(s) to calculate the same, which is/are as follows -
  • diameter = Circumference of Circle/pi
  • diameter = 2*sqrt(Area of Circle/pi)
  • diameter = 2*Radius
  • diameter = Radius of cone
  • diameter = 6*(Thickness)^1/2
  • diameter = sqrt((Cross sectional area*4)/pi)
  • diameter = 2*Radius
  • diameter = (Maximum permissible eccentricity-0.14*Overall depth of column)/(0.43*Area ratio of cross sectional area to gross area*Force ratio of strengths of reinforcements)
  • diameter = moment/(0.12*Total area*Yield strength of reinforcing steel)
  • diameter = (2*x coordinate of focus of parabola)/Slope of Line
  • diameter = 33.33*Allowable Bearing Stresses on Pins/(yield strength of steel-13)
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