Sum of first n odd natural numbers Calculator

Category	Math ↺
Math	Sequence and Series ↺
Sequence-And-Series	General Series ↺

✖value of n is the index value of position n in a series or a sequence.ⓘ value of n [n]

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✖Sum of First n terms denoted the sum of first n terms occuring in a progression like Arithematic Progression, Geometric Progression, Harmonic Progression.ⓘ Sum of first n odd natural numbers [S_n]

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Mridul Sharma

Indian Institute of Information Technology (IIIT), Bhopal

Mridul Sharma has created this Calculator and 100+ more calculators!

Mridul Sharma

Indian Institute of Information Technology (IIIT), Bhopal

Mridul Sharma has verified this Calculator and 200+ more calculators!

< 11 Other formulas that you can solve using the same Inputs

Sum of last n terms in a finite AP with first term, total terms given

Sum of last n terms=(value of n*(2*First term+Common difference*(2*total terms-value of n-1)))/2 GO

Sum of squares of first n even numbers

Sum of squares of first n even numbers=(2*value of n*(value of n+1)*(2*value of n+1))/3 GO

Sum of Squares first n odd numbers

Sum of squares first n odd numbers=(value of n*(2*value of n+1)*(2*value of n-1))/3 GO

Sum of last n terms in a finite AP with last term given

Sum of last n terms=((value of n*(2*Last term+Common difference*(1-value of n)))/2) GO

Sum of first n terms in a finite GP

Sum of First n terms=(First term*((Common Ratio^value of n)-1))/(Common Ratio-1) GO

Sum of squares of first n natural numbers

Sum of First n terms=(value of n*(value of n+1)*(2*value of n+1))/6 GO

nth term from end in a finite GP

Nth term=First term*(Common Ratio^(total terms-value of n)) GO

Sum of cubes of first n natural numbers

Sum of First n terms=((value of n*(value of n+1))^2)/4 GO

Sum of first n natural numbers

Sum of First n terms=(value of n*(value of n+1))/2 GO

Nth term of GP

Nth term=First term*(Common Ratio^(value of n-1)) GO

nth term from the end of finite GP when last term and common ratio is given

Nth term=Last term/(Common Ratio^(value of n-1)) GO

< 10 Other formulas that calculate the same Output

Sum of first n terms of AGP

Sum of First n terms=((First term-(First term+(total terms-1)*Common difference)*(Common Ratio^total terms))/(1-Common Ratio))+(Common difference*Common Ratio*(1-Common Ratio^(total terms-1))/(1-Common Ratio)^2) GO

Sum of first n terms in an AP when common difference is given

Sum of First n terms=(total terms/2)*(2*First term+(total terms-1)*Common difference) GO

Sum of first n terms where r>1

Sum of First n terms=First term*(((Common Ratio^total terms)-1)/(Common Ratio-1)) GO

Sum of first n terms in a finite GP

Sum of First n terms=(First term*((Common Ratio^value of n)-1))/(Common Ratio-1) GO

Sum of squares of first n natural numbers

Sum of First n terms=(value of n*(value of n+1)*(2*value of n+1))/6 GO

Sum of first n terms in an AP when last term is given

Sum of First n terms=(total terms/2)*(First term+Last term) GO

Sum of cubes of first n natural numbers

Sum of First n terms=((value of n*(value of n+1))^2)/4 GO

Sum of first n natural numbers

Sum of First n terms=(value of n*(value of n+1))/2 GO

Sum infinite GP when r is less than one

Sum of First n terms=First term/(1-Common Ratio) GO

Sum of first n even natural numbers

Sum of First n terms=(value of n*(value of n+1)) GO

Sum of first n odd natural numbers Formula

Sum of First n terms=(value of n)^2
S<sub>n</sub>=(n)^2

More formulas

Sum of first n natural numbers GO

Sum of squares of first n natural numbers GO

Sum of cubes of first n natural numbers GO

Sum of Squares first n odd numbers GO

Sum of squares of first n even numbers GO

Sum of first n even natural numbers GO

Sum of cubes of first n even numbers GO

Sum of n natural numbers taken power of 4(four) GO

What does the odd natural numbers mean?

Odd natural numbers simply means the natural numbers which are odd(i.e natural numbers which are not divisible by 2). Example - odd natural numbers are 1,3,5,7,9,11 and so on.

How to Calculate Sum of first n odd natural numbers?

Sum of first n odd natural numbers calculator uses Sum of First n terms=(value of n)^2 to calculate the Sum of First n terms, Sum of first n odd natural numbers can be calculated by using the formula n^2 . Sum of first 4 odd natural numbers (1,3,5,7) is 16. Sum of First n terms and is denoted by S_n symbol.

How to calculate Sum of first n odd natural numbers using this online calculator? To use this online calculator for Sum of first n odd natural numbers, enter value of n (n) and hit the calculate button. Here is how the Sum of first n odd natural numbers calculation can be explained with given input values -> 1 = (1)^2.

FAQ

What is Sum of first n odd natural numbers?

Sum of first n odd natural numbers can be calculated by using the formula n^2 . Sum of first 4 odd natural numbers (1,3,5,7) is 16 and is represented as S_n=(n)^2 or Sum of First n terms=(value of n)^2. value of n is the index value of position n in a series or a sequence.

How to calculate Sum of first n odd natural numbers?

Sum of first n odd natural numbers can be calculated by using the formula n^2 . Sum of first 4 odd natural numbers (1,3,5,7) is 16 is calculated using Sum of First n terms=(value of n)^2. To calculate Sum of first n odd natural numbers, you need value of n (n). With our tool, you need to enter the respective value for value of n and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Sum of First n terms?

In this formula, Sum of First n terms uses value of n. We can use 10 other way(s) to calculate the same, which is/are as follows -

Sum of First n terms=(total terms/2)*(2*First term+(total terms-1)*Common difference)
Sum of First n terms=(total terms/2)*(First term+Last term)
Sum of First n terms=(First term*((Common Ratio^value of n)-1))/(Common Ratio-1)
Sum of First n terms=First term/(1-Common Ratio)
Sum of First n terms=(value of n*(value of n+1))/2
Sum of First n terms=(value of n*(value of n+1)*(2*value of n+1))/6
Sum of First n terms=((value of n*(value of n+1))^2)/4
Sum of First n terms=First term*(((Common Ratio^total terms)-1)/(Common Ratio-1))
Sum of First n terms=((First term-(First term+(total terms-1)*Common difference)*(Common Ratio^total terms))/(1-Common Ratio))+(Common difference*Common Ratio*(1-Common Ratio^(total terms-1))/(1-Common Ratio)^2)
Sum of First n terms=(value of n*(value of n+1))

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