Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 Calculator

✖Sin (A-B)/2 is the value of the trigonometric sine function of angle A minus angle B whole by 2 of the triangle.ⓘ Sin (A-B)/2 [sin_(A-B)/2]			+10% -10%
✖Sin (A+B)/2 is the value of the trigonometric sine function of angle A plus angle B whole by 2 of the triangle.ⓘ Sin (A+B)/2 [sin_(A+B)/2]			+10% -10%
✖Cot C/2 is the value of the trigonometric cotangent function of angle C by 2.ⓘ Cot C/2 [cot_(C/2)]			+10% -10%

✖Tan (A-B)/2 is the value of the trigonometric tangent function of angle A minus angle B whole by 2 of the triangle.ⓘ Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 [tan_(A-B)/2]

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Formula

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Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2

Formula

`"tan"_{"(A-B)/2"} = ("sin"_{"(A-B)/2"}/"sin"_{"(A+B)/2"})*"cot"_{"(C/2)"}`

Example

`"-0.093333"=("-0.08"/"0.6")*"0.7"`

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Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 Solution

STEP 0: Pre-Calculation Summary

Formula Used

Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Cot C/2
tan_(A-B)/2 = (sin_(A-B)/2/sin_(A+B)/2)*cot_(C/2)
This formula uses 4 Variables

Variables Used

Tan (A-B)/2 - Tan (A-B)/2 is the value of the trigonometric tangent function of angle A minus angle B whole by 2 of the triangle.
Sin (A-B)/2 - Sin (A-B)/2 is the value of the trigonometric sine function of angle A minus angle B whole by 2 of the triangle.
Sin (A+B)/2 - Sin (A+B)/2 is the value of the trigonometric sine function of angle A plus angle B whole by 2 of the triangle.
Cot C/2 - Cot C/2 is the value of the trigonometric cotangent function of angle C by 2.

STEP 1: Convert Input(s) to Base Unit

Sin (A-B)/2: -0.08 --> No Conversion Required
Sin (A+B)/2: 0.6 --> No Conversion Required
Cot C/2: 0.7 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

tan_(A-B)/2 = (sin_(A-B)/2/sin_(A+B)/2)*cot_(C/2) --> ((-0.08)/0.6)*0.7

Evaluating ... ...

tan_(A-B)/2 = -0.0933333333333333

STEP 3: Convert Result to Output's Unit

-0.0933333333333333 --> No Conversion Required

FINAL ANSWER

-0.0933333333333333 ≈ -0.093333 <-- Tan (A-B)/2

(Calculation completed in 00.004 seconds)

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Home » Math » Geometry » 2D Geometry » Triangle » Tangent Rule or Napier's Analogy » Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2

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< 10+ Tangent Rule or Napier's Analogy Calculators

Cot (A-B)/2 given Tan C/2

Go Cot (A-B)/2 = ((Side A of Triangle+Side B of Triangle)/(Side A of Triangle-Side B of Triangle))*Tan (C/2)

Cot (C-A)/2 given Tan B/2

Go Cot (C-A)/2 = ((Side C of Triangle+Side A of Triangle)/(Side C of Triangle-Side A of Triangle))*Tan (B/2)

Cot (B-C)/2 given Tan A/2

Go Cot (B-C)/2 = ((Side B of Triangle+Side C of Triangle)/(Side B of Triangle-Side C of Triangle))*Tan (A/2)

Tan (A-B)/2 given Cot C/2

Go Tan (A-B)/2 = ((Side A of Triangle-Side B of Triangle)/(Side A of Triangle+Side B of Triangle))*Cot C/2

Tan (C-A)/2 given Cot B/2

Go Tan (C-A)/2 = ((Side C of Triangle-Side A of Triangle)/(Side C of Triangle+Side A of Triangle))*Cot B/2

Tan (B-C)/2 given Cot A/2

Go Tan (B-C)/2 = ((Side B of Triangle-Side C of Triangle)/(Side B of Triangle+Side C of Triangle))*Cot A/2

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2

Go Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Tan (C/2)

Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2

Go Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Tan (C/2)

Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Cot C/2

Go Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Cot C/2

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2

Go Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Cot C/2

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 Formula

Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Cot C/2
tan_(A-B)/2 = (sin_(A-B)/2/sin_(A+B)/2)*cot_(C/2)

What is a Triangle?

The Triangle is the type of polygon, which have three sides and three vertices. This is a two-dimensional figure with three straight sides. A triangle is considered a 3-sided polygon. The sum of all the three angles of a triangle is equal to 180°. The triangle is contained in a single plane. Based on its sides and angle measurement, the triangle has six types.

What is Napier's analogy?

Formulas giving the tangent of half the sum or difference of two of the angles or sides of a spherical triangle in terms of the sides of the triangle.

How to Calculate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2?

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 calculator uses Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Cot C/2 to calculate the Tan (A-B)/2, The Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 formula is defined as the value of Tan (A-B)/2 using the values of the Sin (A+B)/2, Sin (A-B)/2 and Cot C/2 of the triangle. Tan (A-B)/2 is denoted by tan_(A-B)/2 symbol.

How to calculate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 using this online calculator? To use this online calculator for Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2, enter Sin (A-B)/2 (sin_(A-B)/2), Sin (A+B)/2 (sin_(A+B)/2) & Cot C/2 (cot_(C/2)) and hit the calculate button. Here is how the Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 calculation can be explained with given input values -> -0.093333 = ((-0.08)/0.6)*0.7.

FAQ

What is Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2?

The Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 formula is defined as the value of Tan (A-B)/2 using the values of the Sin (A+B)/2, Sin (A-B)/2 and Cot C/2 of the triangle and is represented as tan_(A-B)/2 = (sin_(A-B)/2/sin_(A+B)/2)*cot_(C/2) or Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Cot C/2. Sin (A-B)/2 is the value of the trigonometric sine function of angle A minus angle B whole by 2 of the triangle, Sin (A+B)/2 is the value of the trigonometric sine function of angle A plus angle B whole by 2 of the triangle & Cot C/2 is the value of the trigonometric cotangent function of angle C by 2.

How to calculate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2?

The Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2 formula is defined as the value of Tan (A-B)/2 using the values of the Sin (A+B)/2, Sin (A-B)/2 and Cot C/2 of the triangle is calculated using Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Cot C/2. To calculate Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2, you need Sin (A-B)/2 (sin_(A-B)/2), Sin (A+B)/2 (sin_(A+B)/2) & Cot C/2 (cot_(C/2)). With our tool, you need to enter the respective value for Sin (A-B)/2, Sin (A+B)/2 & Cot C/2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Tan (A-B)/2?

In this formula, Tan (A-B)/2 uses Sin (A-B)/2, Sin (A+B)/2 & Cot C/2. We can use 2 other way(s) to calculate the same, which is/are as follows -

Tan (A-B)/2 = ((Side A of Triangle-Side B of Triangle)/(Side A of Triangle+Side B of Triangle))*Cot C/2
Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Tan (C/2)

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