Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 Calculator

✖Cos (A-B)/2 is the value of the trigonometric sine function of angle A minus angle B whole by 2 of the triangle.ⓘ Cos (A-B)/2 [cos_(A-B)/2]			+10% -10%
✖Cos (A+B)/2 is the value of the trigonometric cosine function of angle A minus angle B whole by 2 of the triangle.ⓘ Cos (A+B)/2 [cos_(A+B)/2]			+10% -10%
✖Tan (C/2) is the value of the trigonometric tangent function of half of the given angle B.ⓘ Tan (C/2) [tan_(C/2)]			+10% -10%

✖Tan (A+B)/2 is the value of the trigonometric tangent function of angle A minus angle B whole by 2 of the triangle.ⓘ Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 [tan_(A+B)/2]

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Formula

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Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2

Formula

`"tan"_{"(A+B)/2"} = ("cos"_{"(A-B)/2"}/"cos"_{"(A+B)/2"})*"tan"_{"(C/2)"}`

Example

`"1.726463"=("0.99"/"0.82")*"1.43"`

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Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 Solution

STEP 0: Pre-Calculation Summary

Formula Used

Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Tan (C/2)
tan_(A+B)/2 = (cos_(A-B)/2/cos_(A+B)/2)*tan_(C/2)
This formula uses 4 Variables

Variables Used

Tan (A+B)/2 - Tan (A+B)/2 is the value of the trigonometric tangent function of angle A minus angle B whole by 2 of the triangle.
Cos (A-B)/2 - Cos (A-B)/2 is the value of the trigonometric sine function of angle A minus angle B whole by 2 of the triangle.
Cos (A+B)/2 - Cos (A+B)/2 is the value of the trigonometric cosine function of angle A minus angle B whole by 2 of the triangle.
Tan (C/2) - Tan (C/2) is the value of the trigonometric tangent function of half of the given angle B.

STEP 1: Convert Input(s) to Base Unit

Cos (A-B)/2: 0.99 --> No Conversion Required
Cos (A+B)/2: 0.82 --> No Conversion Required
Tan (C/2): 1.43 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

tan_(A+B)/2 = (cos_(A-B)/2/cos_(A+B)/2)*tan_(C/2) --> (0.99/0.82)*1.43

Evaluating ... ...

tan_(A+B)/2 = 1.72646341463415

STEP 3: Convert Result to Output's Unit

1.72646341463415 --> No Conversion Required

FINAL ANSWER

1.72646341463415 ≈ 1.726463 <-- Tan (A+B)/2

(Calculation completed in 00.004 seconds)

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< 10+ Tangent Rule or Napier's Analogy Calculators

Cot (A-B)/2 given Tan C/2

Go Cot (A-B)/2 = ((Side A of Triangle+Side B of Triangle)/(Side A of Triangle-Side B of Triangle))*Tan (C/2)

Cot (C-A)/2 given Tan B/2

Go Cot (C-A)/2 = ((Side C of Triangle+Side A of Triangle)/(Side C of Triangle-Side A of Triangle))*Tan (B/2)

Cot (B-C)/2 given Tan A/2

Go Cot (B-C)/2 = ((Side B of Triangle+Side C of Triangle)/(Side B of Triangle-Side C of Triangle))*Tan (A/2)

Tan (A-B)/2 given Cot C/2

Go Tan (A-B)/2 = ((Side A of Triangle-Side B of Triangle)/(Side A of Triangle+Side B of Triangle))*Cot C/2

Tan (C-A)/2 given Cot B/2

Go Tan (C-A)/2 = ((Side C of Triangle-Side A of Triangle)/(Side C of Triangle+Side A of Triangle))*Cot B/2

Tan (B-C)/2 given Cot A/2

Go Tan (B-C)/2 = ((Side B of Triangle-Side C of Triangle)/(Side B of Triangle+Side C of Triangle))*Cot A/2

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Tan C/2

Go Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Tan (C/2)

Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2

Go Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Tan (C/2)

Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Cot C/2

Go Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Cot C/2

Tan (A-B)/2 given Sin (A+B)/2 , Sin (A-B)/2 and Cot C/2

Go Tan (A-B)/2 = (Sin (A-B)/2/Sin (A+B)/2)*Cot C/2

Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 Formula

Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Tan (C/2)
tan_(A+B)/2 = (cos_(A-B)/2/cos_(A+B)/2)*tan_(C/2)

What is a Triangle?

The Triangle is the type of polygon, which have three sides and three vertices. This is a two-dimensional figure with three straight sides. A triangle is considered a 3-sided polygon. The sum of all the three angles of a triangle is equal to 180°. The triangle is contained in a single plane. Based on its sides and angle measurement, the triangle has six types.

What is Napier's analogy?

Formulas giving the tangent of half the sum or difference of two of the angles or sides of a spherical triangle in terms of the sides of the triangle.

How to Calculate Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2?

Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 calculator uses Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Tan (C/2) to calculate the Tan (A+B)/2, The Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 formula is defined as the value of Tan (A+B)/2 using the values of the Cos (A+B)/2, Cos (A-B)/2 and Tan C/2 of the triangle. Tan (A+B)/2 is denoted by tan_(A+B)/2 symbol.

How to calculate Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 using this online calculator? To use this online calculator for Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2, enter Cos (A-B)/2 (cos_(A-B)/2), Cos (A+B)/2 (cos_(A+B)/2) & Tan (C/2) (tan_(C/2)) and hit the calculate button. Here is how the Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 calculation can be explained with given input values -> 1.690244 = (0.99/0.82)*1.43.

FAQ

What is Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2?

The Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 formula is defined as the value of Tan (A+B)/2 using the values of the Cos (A+B)/2, Cos (A-B)/2 and Tan C/2 of the triangle and is represented as tan_(A+B)/2 = (cos_(A-B)/2/cos_(A+B)/2)*tan_(C/2) or Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Tan (C/2). Cos (A-B)/2 is the value of the trigonometric sine function of angle A minus angle B whole by 2 of the triangle, Cos (A+B)/2 is the value of the trigonometric cosine function of angle A minus angle B whole by 2 of the triangle & Tan (C/2) is the value of the trigonometric tangent function of half of the given angle B.

How to calculate Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2?

The Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2 formula is defined as the value of Tan (A+B)/2 using the values of the Cos (A+B)/2, Cos (A-B)/2 and Tan C/2 of the triangle is calculated using Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Tan (C/2). To calculate Tan (A+B)/2 given Cos (A+B)/2 , Cos (A-B)/2 and Tan C/2, you need Cos (A-B)/2 (cos_(A-B)/2), Cos (A+B)/2 (cos_(A+B)/2) & Tan (C/2) (tan_(C/2)). With our tool, you need to enter the respective value for Cos (A-B)/2, Cos (A+B)/2 & Tan (C/2) and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Tan (A+B)/2?

In this formula, Tan (A+B)/2 uses Cos (A-B)/2, Cos (A+B)/2 & Tan (C/2). We can use 1 other way(s) to calculate the same, which is/are as follows -

Tan (A+B)/2 = (Cos (A-B)/2/Cos (A+B)/2)*Cot C/2

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