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Total moles at equilibrium given number of moles of reaction Calculator

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โœ–Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium.โ“˜ Equilibrium Vapour Density [d]
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-10%
โœ–The Volume of Solution gives the volume of the solution in liters.โ“˜ Volume of Solution [V]
+10%
-10%
โœ–The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.โ“˜ Degree of Dissociation [๐ฐ]
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-10%
โœ–Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.โ“˜ Number of Moles [Nmoles]
+10%
-10%
โœ–Total Moles at Equilibrium is the complete moles which are present at the equilibrium stage of the chemical reaction.โ“˜ Total moles at equilibrium given number of moles of reaction [M]
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Formula
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Total moles at equilibrium given number of moles of reaction

Formula
`"M" = "d"*"V"*(1+"๐ฐ"*("N"_{"moles"}-1))`

Example
`"91.125"="150"*"450L"*(1+"0.35"*("2"-1))`

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Total moles at equilibrium given number of moles of reaction Solution

STEP 0: Pre-Calculation Summary
Formula Used
Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1))
M = d*V*(1+๐ฐ*(Nmoles-1))
This formula uses 5 Variables
Variables Used
Total Moles at Equilibrium - Total Moles at Equilibrium is the complete moles which are present at the equilibrium stage of the chemical reaction.
Equilibrium Vapour Density - Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium.
Volume of Solution - (Measured in Cubic Meter) - The Volume of Solution gives the volume of the solution in liters.
Degree of Dissociation - The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
Number of Moles - Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.
STEP 1: Convert Input(s) to Base Unit
Equilibrium Vapour Density: 150 --> No Conversion Required
Volume of Solution: 450 Liter --> 0.45 Cubic Meter (Check conversion here)
Degree of Dissociation: 0.35 --> No Conversion Required
Number of Moles: 2 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
M = d*V*(1+๐ฐ*(Nmoles-1)) --> 150*0.45*(1+0.35*(2-1))
Evaluating ... ...
M = 91.125
STEP 3: Convert Result to Output's Unit
91.125 --> No Conversion Required
FINAL ANSWER
91.125 <-- Total Moles at Equilibrium
(Calculation completed in 00.004 seconds)
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National Institute of Information Technology (NIIT), Neemrana
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24 Relation between Vapour Density and Degree of Dissociation Calculators

Initial Vapour Density using Concentration of Reaction
Go Initial Vapour Density = (Equilibrium Vapour Density*Initial Concentration*(1+Degree of Dissociation))/Initial Concentration
Total moles at equilibrium given number of moles of reaction
Go Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1))
Volume of Equilibrium Mixture of Substances A and B
Go Volume at Equilibrium = (1+Degree of Dissociation*(Number of Moles Products at Equilibrium-1))*Volume of Solution
Total Moles at Equilibrium
Go Total Moles at Equilibrium = (Initial Vapour Density*Initial Number of Moles)/Equilibrium Vapour Density
Initial Vapour Density
Go Initial Vapour Density = (Total Moles at Equilibrium*Equilibrium Vapour Density)/Initial Number of Moles
Initial Total moles
Go Initial Number of Moles = (Total Moles at Equilibrium*Equilibrium Vapour Density)/Initial Vapour Density
Initial Total Moles using Total Moles at Equilibrium and Number of Moles of Reaction
Go Initial Number of Moles = Total Moles at Equilibrium*(1+Degree of Dissociation*(Number of Moles-1))
Total Moles at Equilibrium using Number of Moles and Initial Total Moles
Go Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1))
Initial Vapour Density using Vapour Density at Equilibrium and Number of Moles
Go Initial Vapour Density = Equilibrium Vapour Density*(1+Degree of Dissociation*(Number of Moles-1))
Initial Vapour Density when Number of Moles of Products at Equilibrium is Half
Go Initial Vapour Density = Equilibrium Vapour Density*(2-Degree of Dissociation)/2
Number of moles of products using degree of dissociation
Go Number of Moles = ((Number of Moles at Equilibrium-1)/Degree of Dissociation)+1
Total Moles at Equilibrium using Degree of Dissociation
Go Total Moles at Equilibrium = Initial Number of Moles*(1+Degree of Dissociation)
Initial Total Moles using Degree of Dissociation
Go Initial Number of Moles = Total Moles at Equilibrium/(1+Degree of Dissociation)
Initial Vapour Density given Degree of Dissociation
Go Initial Vapour Density = Equilibrium Vapour Density*(1+Degree of Dissociation)
Initial Vapour Density when Number of Moles is 2
Go Initial Vapour Density = Equilibrium Vapour Density*(Degree of Dissociation+1)
Number of Moles of Substance A and B at Equilibrium
Go Number of Moles at Equilibrium = 1+Degree of Dissociation*(Number of Moles-1)
Initial Vapour Density given Van't Hoff Factor
Go Initial Vapour Density = Van't Hoff Factor*Equilibrium Vapour Density
Van't Hoff Factor using Vapour Densities
Go Van't Hoff Factor = Initial Vapour Density/Equilibrium Vapour Density
Molecular Weight of Substance given Initial Vapour Density
Go Molecular Weight = Initial Vapour Density*Volume of Solution
Volume of Solution given Initial Vapour Density
Go Volume of Solution = Molecular Weight/Initial Vapour Density
Initial Vapour Density given Molecular Weight
Go Initial Vapour Density = Molecular Weight/Volume of Solution
Molecular Weight abnormal given Vapour Density at Equilibrium
Go Molecular Weight Abnormal = Equilibrium Vapour Density*2
Theoretical Molecular Weight given Initial Vapour Density
Go Molecular Weight Theoretical = Initial Vapour Density*2
Initial Vapour Density given Theoretical Molecular Weight
Go Initial Vapour Density = Molecular Weight Theoretical/2

Total moles at equilibrium given number of moles of reaction Formula

Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1))
M = d*V*(1+๐ฐ*(Nmoles-1))

What is Vapour density?

Vapour density is the weight of a volume of pure vapor or gas compared to an equal volume of dry air at the same temperature and pressure. It is obtained by dividing the molecular weight of the vapor by the average molecular weight of air thus, it is unitless. It is also defined as the fraction of moles dissociated out of 1 mole.

How to Calculate Total moles at equilibrium given number of moles of reaction?

Total moles at equilibrium given number of moles of reaction calculator uses Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1)) to calculate the Total Moles at Equilibrium, The Total moles at equilibrium given number of moles of reaction formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction. Total Moles at Equilibrium is denoted by M symbol.

How to calculate Total moles at equilibrium given number of moles of reaction using this online calculator? To use this online calculator for Total moles at equilibrium given number of moles of reaction, enter Equilibrium Vapour Density (d), Volume of Solution (V), Degree of Dissociation (๐ฐ) & Number of Moles (Nmoles) and hit the calculate button. Here is how the Total moles at equilibrium given number of moles of reaction calculation can be explained with given input values -> 91.125 = 150*0.45*(1+0.35*(2-1)).

FAQ

What is Total moles at equilibrium given number of moles of reaction?
The Total moles at equilibrium given number of moles of reaction formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction and is represented as M = d*V*(1+๐ฐ*(Nmoles-1)) or Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1)). Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium, The Volume of Solution gives the volume of the solution in liters, The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration & Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.
How to calculate Total moles at equilibrium given number of moles of reaction?
The Total moles at equilibrium given number of moles of reaction formula is defined as the complete moles which are present at the equilibrium stage of the chemical reaction is calculated using Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1)). To calculate Total moles at equilibrium given number of moles of reaction, you need Equilibrium Vapour Density (d), Volume of Solution (V), Degree of Dissociation (๐ฐ) & Number of Moles (Nmoles). With our tool, you need to enter the respective value for Equilibrium Vapour Density, Volume of Solution, Degree of Dissociation & Number of Moles and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Total Moles at Equilibrium?
In this formula, Total Moles at Equilibrium uses Equilibrium Vapour Density, Volume of Solution, Degree of Dissociation & Number of Moles. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Total Moles at Equilibrium = (Initial Vapour Density*Initial Number of Moles)/Equilibrium Vapour Density
  • Total Moles at Equilibrium = Initial Number of Moles*(1+Degree of Dissociation)
  • Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1))
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