Total Number of Moles of Reaction at Equilibrium Solution

STEP 0: Pre-Calculation Summary
Formula Used
Total Moles in Reaction = Number of Moles*(1-Degree of Dissociation)
ntotal = Nmoles*(1-𝝰)
This formula uses 3 Variables
Variables Used
Total Moles in Reaction - (Measured in Mole) - Total Moles in Reaction is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.
Number of Moles - Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.
Degree of Dissociation - The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
STEP 1: Convert Input(s) to Base Unit
Number of Moles: 2 --> No Conversion Required
Degree of Dissociation: 0.35 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ntotal = Nmoles*(1-𝝰) --> 2*(1-0.35)
Evaluating ... ...
ntotal = 1.3
STEP 3: Convert Result to Output's Unit
1.3 Mole --> No Conversion Required
FINAL ANSWER
1.3 Mole <-- Total Moles in Reaction
(Calculation completed in 00.004 seconds)

Credits

Created by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
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Verified by Pragati Jaju
College Of Engineering (COEP), Pune
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20 Relation between Equilibrium Constant and Degree of Dissociation Calculators

Degree of Dissociation for Double Reaction given Equilibrium Pressure
Go Degree of Dissociation = sqrt(Equilibrium Constant for Partial Pressure/(Equilibrium Constant for Partial Pressure+(4*Absolute Pressure)))
Degree of Dissociation given Equilibrium Pressure
Go Degree of Dissociation = sqrt(Equilibrium Constant for Partial Pressure/(Equilibrium Constant for Partial Pressure+Absolute Pressure))
Mole Fraction of Reactant Substance A
Go Mole fraction of element A = (Number of Moles*Degree of Dissociation)/Number of Moles*(1+Degree of Dissociation)
Total Pressure given Equilibrium Constant with respect to Pressure
Go Total Pressure = (Equilibrium Constant for Partial Pressure*(1-(Degree of Dissociation^2)))/(4*(Degree of Dissociation^2))
Equilibrium Constant due to Pressure given Degree of Dissociation
Go Equilibrium Constant for Partial Pressure = (4*(Degree of Dissociation^2)*Total Pressure)/(1-(Degree of Dissociation^2))
Equilibrium Constant with respect to Pressure
Go Equilibrium Constant for Partial Pressure = (Pressure*(Degree of Dissociation^2))/(1-(Degree of Dissociation^2))
Pressure of Gas given Equilibrium Constant with respect to Pressure
Go Pressure = Equilibrium Constant for Partial Pressure*(1-(Degree of Dissociation^2))/(Degree of Dissociation^2)
Degree of Dissociation when Pressure Increases during Reaction
Go Degree of Dissociation = sqrt(Equilibrium Constant for Partial Pressure/Pressure)
Equilibrium Constant in Terms of Mole Fraction given Degree of Dissociation
Go Equilibrium Constant for Mole Fraction = (4*(Degree of Dissociation^2))/(1-(Degree of Dissociation^2))
Equilibrium Constant with respect to Pressure when Pressure Increases
Go Equilibrium Constant for Partial Pressure = Absolute Pressure*(Degree of Dissociation^2)
Increased Pressure during Chemical Reaction given Degree of Dissociation
Go Pressure = Equilibrium Constant for Partial Pressure/(Degree of Dissociation^2)
Initial Number of Moles taken given Degree of Dissociation
Go Initial Number of Moles = Number of Moles Dissociated/Degree of Dissociation
Number of Moles Dissociated given Degree of Dissociation
Go Number of Moles Dissociated = Degree of Dissociation*Initial Number of Moles
Degree of Dissociation of Reaction
Go Degree of Dissociation = Number of Moles Dissociated/Initial Number of Moles
Mole Fraction of Product Substance C
Go Mole fraction C = (1-Degree of Dissociation)/(1+Degree of Dissociation)
Number of Moles of Substance given Total Number of Moles of Reaction
Go Number of Moles = Total Moles in Reaction/(1-Degree of Dissociation)
Degree of Dissociation given Total Number of Moles of Reaction
Go Degree of Dissociation = 1-(Total Moles in Reaction/Number of Moles)
Total Number of Moles of Reaction at Equilibrium
Go Total Moles in Reaction = Number of Moles*(1-Degree of Dissociation)
Mole Fraction of Reactant Substance B
Go Mole fraction B = Degree of Dissociation/(1+Degree of Dissociation)
Number of Moles of Substance at Equilibrium
Go Total Moles in Reaction = Number of Moles*Degree of Dissociation

Total Number of Moles of Reaction at Equilibrium Formula

Total Moles in Reaction = Number of Moles*(1-Degree of Dissociation)
ntotal = Nmoles*(1-𝝰)

What is a mole?

A mole is defined as the mass of the substance which consists of the equal quantity of basic units. A mole fraction indicates the number of chemical elements. A mole is defined as 6.02214076 × 10^23 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

How to Calculate Total Number of Moles of Reaction at Equilibrium?

Total Number of Moles of Reaction at Equilibrium calculator uses Total Moles in Reaction = Number of Moles*(1-Degree of Dissociation) to calculate the Total Moles in Reaction, The Total number of moles of reaction at equilibrium formula is defined as the amount of gas present in moles in a chemical reaction at equilibrium. 1 mole of gas weighs as much as its molecular weight. Total Moles in Reaction is denoted by ntotal symbol.

How to calculate Total Number of Moles of Reaction at Equilibrium using this online calculator? To use this online calculator for Total Number of Moles of Reaction at Equilibrium, enter Number of Moles (Nmoles) & Degree of Dissociation (𝝰) and hit the calculate button. Here is how the Total Number of Moles of Reaction at Equilibrium calculation can be explained with given input values -> 1.3 = 2*(1-0.35).

FAQ

What is Total Number of Moles of Reaction at Equilibrium?
The Total number of moles of reaction at equilibrium formula is defined as the amount of gas present in moles in a chemical reaction at equilibrium. 1 mole of gas weighs as much as its molecular weight and is represented as ntotal = Nmoles*(1-𝝰) or Total Moles in Reaction = Number of Moles*(1-Degree of Dissociation). Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight & The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
How to calculate Total Number of Moles of Reaction at Equilibrium?
The Total number of moles of reaction at equilibrium formula is defined as the amount of gas present in moles in a chemical reaction at equilibrium. 1 mole of gas weighs as much as its molecular weight is calculated using Total Moles in Reaction = Number of Moles*(1-Degree of Dissociation). To calculate Total Number of Moles of Reaction at Equilibrium, you need Number of Moles (Nmoles) & Degree of Dissociation (𝝰). With our tool, you need to enter the respective value for Number of Moles & Degree of Dissociation and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Total Moles in Reaction?
In this formula, Total Moles in Reaction uses Number of Moles & Degree of Dissociation. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Total Moles in Reaction = Number of Moles*Degree of Dissociation
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