Total Pressure of Mixture of Two Immiscible Liquids Calculator

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Immiscible Liquids

Clausius-Clapeyron Equation

Depression in Freezing Point

Elevation in Boiling Point

Gibb's Phase Rule

Important Formulas of Clausius-Clapeyron Equation

Important Formulas of Colligative Properties

Osmotic Pressure

Relative Lowering of Vapour Pressure

Van't Hoff Factor

✖Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.ⓘ Vapor Pressure of Pure Component A [P_A°]			+10% -10%
✖Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.ⓘ Vapor Pressure of Pure Component B [P_B°]			+10% -10%

✖The Total Pressure of mixture of immiscible liquids is the sum of their pure state partial pressures since mole fraction of each is 1.ⓘ Total Pressure of Mixture of Two Immiscible Liquids [P]

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Formula

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Total Pressure of Mixture of Two Immiscible Liquids

Formula

`"P" = ("P"_{"A"}"°")+("P"_{"B"}"°")`

Example

`"2.95Pa"="2.7Pa"+"0.25Pa"`

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Total Pressure of Mixture of Two Immiscible Liquids Solution

STEP 0: Pre-Calculation Summary

Formula Used

Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B
P = P_A°+P_B°
This formula uses 3 Variables

Variables Used

Total Pressure of Mixture of Immiscible Liquids - (Measured in Pascal) - The Total Pressure of mixture of immiscible liquids is the sum of their pure state partial pressures since mole fraction of each is 1.
Vapor Pressure of Pure Component A - (Measured in Pascal) - Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.

STEP 1: Convert Input(s) to Base Unit

Vapor Pressure of Pure Component A: 2.7 Pascal --> 2.7 Pascal No Conversion Required
Vapor Pressure of Pure Component B: 0.25 Pascal --> 0.25 Pascal No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P = P_A°+P_B° --> 2.7+0.25

Evaluating ... ...

P = 2.95

STEP 3: Convert Result to Output's Unit

2.95 Pascal --> No Conversion Required

FINAL ANSWER

2.95 Pascal <-- Total Pressure of Mixture of Immiscible Liquids

(Calculation completed in 00.004 seconds)

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Home » Chemistry » Solution and Colligative properties » Immiscible Liquids » Total Pressure of Mixture of Two Immiscible Liquids

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Created by Prerana Bakli

University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA

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National Institute of Information Technology (NIIT), Neemrana

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< 19 Immiscible Liquids Calculators

Total Pressure of Mixture of Water with Liquid given Vapour Pressure

Go Total Pressure of Mixture of Liquid with Water = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water))

Total Pressure of Mixture of Liquid with Water given Vapour Pressure of Water

Go Total Pressure of Mixture of Liquid with Water = Partial Pressure of Pure Water+((Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B))

Total Vapour Pressure of Mixture of given Partial Pressure of One Liquid

Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A))

Weight of Water required to form Immiscible Mixture with Liquid given Weight

Go Weight of Water in Immiscible Mixture = (Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Weight of Liquid required to form Immiscible Mixture with Water

Go Weight of Liquid B = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Partial Pressure of Pure Water*Molecular Mass of Water)

Vapour Pressure of Liquid forming Immiscible Mixture with Water

Go Vapor Pressure of Pure Component B = (Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B)

Vapour Pressure of Water forming Immiscible Mixture with Liquid

Go Partial Pressure of Pure Water = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water)

Molecular Mass of Liquid forming Immiscible Mixture with Water

Go Molecular Mass of Liquid B = (Partial Pressure of Pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of Water in Immiscible Mixture)

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids

Go Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B)

Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

Go Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B)

Weight of Liquid in Mixture of 2 Immiscible Liquids given Weight of other Liquid

Go Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Ratio of Molecular Masses of Water to Liquid forming Immiscible Mixture

Go Ratio of Molecular Masses of 2 Immiscible Liquids = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B)/(Partial Pressure of Pure Water*Weight of Liquid B)

Ratio of Weights of 2 Immiscible Liquids forming Mixture

Go Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Ratio of Molecular Mass of 2 Immiscible Liquids

Go Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B)

Ratio of Partial Vapour Pressures of Water with Liquid forming Immiscible Mixture

Go Ratio of Partial Pressures of Water and Liquid = (Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B)/(Molecular Mass of Water*Weight of Liquid B)

Ratio of Weights of Water to Liquid forming Immiscible Mixture

Go Ratio of Weights of Water and Liquid = (Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)

Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

Go Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)

Total Pressure of Mixture of Two Immiscible Liquids

Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

Go Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B

Total Pressure of Mixture of Two Immiscible Liquids Formula

Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B
P = P_A°+P_B°

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Total Pressure of Mixture of Two Immiscible Liquids?

Total Pressure of Mixture of Two Immiscible Liquids calculator uses Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B to calculate the Total Pressure of Mixture of Immiscible Liquids, The Total Pressure of Mixture of Two Immiscible Liquids is the sum of the pure liquid's partial pressures since mole fraction of each is 1. Total Pressure of Mixture of Immiscible Liquids is denoted by P symbol.

How to calculate Total Pressure of Mixture of Two Immiscible Liquids using this online calculator? To use this online calculator for Total Pressure of Mixture of Two Immiscible Liquids, enter Vapor Pressure of Pure Component A (P_A°) & Vapor Pressure of Pure Component B (P_B°) and hit the calculate button. Here is how the Total Pressure of Mixture of Two Immiscible Liquids calculation can be explained with given input values -> 2.95 = 2.7+0.25.

FAQ

What is Total Pressure of Mixture of Two Immiscible Liquids?

The Total Pressure of Mixture of Two Immiscible Liquids is the sum of the pure liquid's partial pressures since mole fraction of each is 1 and is represented as P = P_A°+P_B° or Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B. Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase & Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.

How to calculate Total Pressure of Mixture of Two Immiscible Liquids?

The Total Pressure of Mixture of Two Immiscible Liquids is the sum of the pure liquid's partial pressures since mole fraction of each is 1 is calculated using Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B. To calculate Total Pressure of Mixture of Two Immiscible Liquids, you need Vapor Pressure of Pure Component A (P_A°) & Vapor Pressure of Pure Component B (P_B°). With our tool, you need to enter the respective value for Vapor Pressure of Pure Component A & Vapor Pressure of Pure Component B and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Total Pressure of Mixture of Immiscible Liquids?

In this formula, Total Pressure of Mixture of Immiscible Liquids uses Vapor Pressure of Pure Component A & Vapor Pressure of Pure Component B. We can use 1 other way(s) to calculate the same, which is/are as follows -

Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A))

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