Total Pressure of mixture of two Immiscible Liquids Solution

STEP 0: Pre-Calculation Summary
Formula Used
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B
P = PAo+PBo
This formula uses 3 Variables
Variables Used
Total Pressure of Mixture of Immiscible Liquids - (Measured in Pascal) - The Total Pressure of mixture of immiscible liquids is the sum of their pure state partial pressures since mole fraction of each is 1.
Vapor Pressure of Pure Component A - (Measured in Pascal) - Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
STEP 1: Convert Input(s) to Base Unit
Vapor Pressure of Pure Component A: 2700 Pascal --> 2700 Pascal No Conversion Required
Vapor Pressure of Pure Component B: 10 Pascal --> 10 Pascal No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
P = PAo+PBo --> 2700+10
Evaluating ... ...
P = 2710
STEP 3: Convert Result to Output's Unit
2710 Pascal -->0.0267456205280039 Standard Atmosphere (Check conversion here)
FINAL ANSWER
0.0267456205280039 Standard Atmosphere <-- Total Pressure of Mixture of Immiscible Liquids
(Calculation completed in 00.016 seconds)

Credits

Created by Prerana Bakli
National Institute of Technology (NIT), Meghalaya
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National Institute of Information Technology (NIIT), Neemrana
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10+ Immiscible Liquids Calculators

Total Vapour Pressure of mixture of given partial pressure of one liquid
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)) Go
Molecular Mass of Liquid forming Immiscible Mixture with Water
Molecular Mass of Liquid B = (Partial Pressure of Pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of Water in Immiscible Mixture) Go
Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids
Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go
Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid
Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B) Go
Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid
Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Go
Ratio of Weights of 2 Immiscible Liquids forming Mixture
Ratio of Weights of 2 Immiscible Liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Go
Ratio of Molecular Mass of 2 Immiscible Liquids
Ratio of Molecular Masses of 2 immiscible liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go
Ratio of partial vapour pressures of 2 Immiscible Liquids in terms of weight and molecular mass
Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A) Go
Total Pressure of mixture of two Immiscible Liquids
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B Go
Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles
Ratio of Partial Pressures of 2 Immiscible Liquids = Number of moles of Liquid A/Number of Moles of Liquid B Go

Total Pressure of mixture of two Immiscible Liquids Formula

Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B
P = PAo+PBo

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Total Pressure of mixture of two Immiscible Liquids?

Total Pressure of mixture of two Immiscible Liquids calculator uses Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B to calculate the Total Pressure of Mixture of Immiscible Liquids, The Total Pressure of mixture of two Immiscible Liquids is the sum of the pure liquid's partial pressures since mole fraction of each is 1. Total Pressure of Mixture of Immiscible Liquids is denoted by P symbol.

How to calculate Total Pressure of mixture of two Immiscible Liquids using this online calculator? To use this online calculator for Total Pressure of mixture of two Immiscible Liquids, enter Vapor Pressure of Pure Component A (PAo) & Vapor Pressure of Pure Component B (PBo) and hit the calculate button. Here is how the Total Pressure of mixture of two Immiscible Liquids calculation can be explained with given input values -> 0.026746 = 2700+10.

FAQ

What is Total Pressure of mixture of two Immiscible Liquids?
The Total Pressure of mixture of two Immiscible Liquids is the sum of the pure liquid's partial pressures since mole fraction of each is 1 and is represented as P = PAo+PBo or Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B. Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase & Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
How to calculate Total Pressure of mixture of two Immiscible Liquids?
The Total Pressure of mixture of two Immiscible Liquids is the sum of the pure liquid's partial pressures since mole fraction of each is 1 is calculated using Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B. To calculate Total Pressure of mixture of two Immiscible Liquids, you need Vapor Pressure of Pure Component A (PAo) & Vapor Pressure of Pure Component B (PBo). With our tool, you need to enter the respective value for Vapor Pressure of Pure Component A & Vapor Pressure of Pure Component B and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Total Pressure of Mixture of Immiscible Liquids?
In this formula, Total Pressure of Mixture of Immiscible Liquids uses Vapor Pressure of Pure Component A & Vapor Pressure of Pure Component B. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A))
  • Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Water))
  • Total Pressure of Mixture of Immiscible Liquids = Partial Pressure of Pure Water+((Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Weight of Water in Immiscible Mixture*Molecular Mass of Liquid B))
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