Volume of Box having Gas Molecule given Pressure Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas
Vbox_P = (m*(u)^2)/Pgas
This formula uses 4 Variables
Variables Used
Volume of Rectangular Box given P - (Measured in Cubic Meter) - Volume of Rectangular Box given P is the product of length, breadth, and height.
Mass per Molecule - (Measured in Kilogram) - The Mass per Molecule is defined as the molar mass of the molecule divided by the Avogadro number.
Speed of Particle - (Measured in Meter per Second) - The Speed of Particle is the amount of distance travelled by the particle per unit time.
Pressure of Gas - (Measured in Pascal) - The pressure of Gas is the force that the gas exerts on the walls of its container.
STEP 1: Convert Input(s) to Base Unit
Mass per Molecule: 0.2 Gram --> 0.0002 Kilogram (Check conversion here)
Speed of Particle: 15 Meter per Second --> 15 Meter per Second No Conversion Required
Pressure of Gas: 0.215 Pascal --> 0.215 Pascal No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vbox_P = (m*(u)^2)/Pgas --> (0.0002*(15)^2)/0.215
Evaluating ... ...
Vbox_P = 0.209302325581395
STEP 3: Convert Result to Output's Unit
0.209302325581395 Cubic Meter -->209.302325581395 Liter (Check conversion here)
FINAL ANSWER
209.302325581395 209.3023 Liter <-- Volume of Rectangular Box given P
(Calculation completed in 00.004 seconds)

Credits

Created by Prashant Singh
K J Somaiya College of science (K J Somaiya), Mumbai
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National Institute of Information Technology (NIIT), Neemrana
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18 PIB Calculators

Number of Moles of Gas 1 given Kinetic Energy of both Gases
Go Number of Moles given KE of Two Gases = (Kinetic Energy of Gas 1/Kinetic Energy of Gas 2)*Number of Moles of Gas 2*(Temperature of Gas 2/Temperature of Gas 1)
Number of Moles of Gas 2 given Kinetic Energy of both Gases
Go Number of Moles given KE of Two Gases = Number of Moles of Gas 1*(Kinetic Energy of Gas 2/Kinetic Energy of Gas 1)*(Temperature of Gas 1/Temperature of Gas 2)
Mass of Each Gas Molecule in 3D Box given Pressure
Go Mass per Molecule given P = (3*Pressure of Gas*Volume of Gas)/(Number of Molecules*(Root Mean Square Speed)^2)
Mass of Each Gas Molecule in 2D Box given Pressure
Go Mass per Molecule given P = (2*Pressure of Gas*Volume of Gas)/(Number of Molecules*(Root Mean Square Speed)^2)
Number of Gas Molecules in 3D Box given Pressure
Go Number of Molecules given P = (3*Pressure of Gas*Volume of Gas)/(Mass per Molecule*(Root Mean Square Speed)^2)
Number of Gas Molecules in 2D Box given Pressure
Go Number of Molecules given P = (2*Pressure of Gas*Volume of Gas)/(Mass per Molecule*(Root Mean Square Speed)^2)
Speed of Gas Molecule in 1D given Pressure
Go Speed of Particle given P = sqrt((Pressure of Gas*Volume of Rectangular Box)/Mass per Molecule)
Speed of Gas Molecule given Force
Go Speed of Particle given F = sqrt((Force*Length of Rectangular Section)/Mass per Molecule)
Volume of Box having Gas Molecule given Pressure
Go Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas
Mass of Gas Molecule in 1D given Pressure
Go Mass per Molecule given P = (Pressure of Gas*Volume of Rectangular Box)/(Speed of Particle)^2
Pressure Exerted by Single Gas Molecule in 1D
Go Pressure of Gas in 1D = (Mass per Molecule*(Speed of Particle)^2)/Volume of Rectangular Box
Force by Gas Molecule on Wall of Box
Go Force on a wall = (Mass per Molecule*(Speed of Particle)^2)/Length of Rectangular Section
Mass of Gas Molecule given Force
Go Mass per Molecule given F = (Force*Length of Rectangular Section)/((Speed of Particle)^2)
Length of Box given Force
Go Length of Rectangular box = (Mass per Molecule*(Speed of Particle)^2)/Force
Number of Moles given Kinetic Energy
Go Number of Moles given KE = (2/3)*(Kinetic Energy/([R]*Temperature))
Speed of Particle in 3D Box
Go Speed of Particle given in 3D = (2*Length of Rectangular Section)/Time between Collision
Length of Rectangular Box given Time of Collision
Go Length of Rectangular box given T = (Time between Collision*Speed of Particle)/2
Time between Collisions of Particle and Walls
Go Time of Collision = (2*Length of Rectangular Section)/Speed of Particle

Volume of Box having Gas Molecule given Pressure Formula

Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas
Vbox_P = (m*(u)^2)/Pgas

What are postulates of Kinetic molecular theory of gas?

1) Actual volume of gas molecules is negligible in comparison to the total volume of the gas.
2) no force of attraction between the gas molecules.
3) Particles of gas are in constant random motion.
4) Particles of gas collide with each other and with the walls of the container.
5)Collisions are perfectly elastic.
6) Different particles of the gas, have different speeds.
7) The average kinetic energy of the gas molecule is directly proportional to the absolute temperature.

How to Calculate Volume of Box having Gas Molecule given Pressure?

Volume of Box having Gas Molecule given Pressure calculator uses Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas to calculate the Volume of Rectangular Box given P, The volume of box having gas molecule given pressure formula is defined as product of the mass of particle and square of the speed of the particle per pressure of the gas in the box. Volume of Rectangular Box given P is denoted by Vbox_P symbol.

How to calculate Volume of Box having Gas Molecule given Pressure using this online calculator? To use this online calculator for Volume of Box having Gas Molecule given Pressure, enter Mass per Molecule (m), Speed of Particle (u) & Pressure of Gas (Pgas) and hit the calculate button. Here is how the Volume of Box having Gas Molecule given Pressure calculation can be explained with given input values -> 209302.3 = (0.0002*(15)^2)/0.215.

FAQ

What is Volume of Box having Gas Molecule given Pressure?
The volume of box having gas molecule given pressure formula is defined as product of the mass of particle and square of the speed of the particle per pressure of the gas in the box and is represented as Vbox_P = (m*(u)^2)/Pgas or Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas. The Mass per Molecule is defined as the molar mass of the molecule divided by the Avogadro number, The Speed of Particle is the amount of distance travelled by the particle per unit time & The pressure of Gas is the force that the gas exerts on the walls of its container.
How to calculate Volume of Box having Gas Molecule given Pressure?
The volume of box having gas molecule given pressure formula is defined as product of the mass of particle and square of the speed of the particle per pressure of the gas in the box is calculated using Volume of Rectangular Box given P = (Mass per Molecule*(Speed of Particle)^2)/Pressure of Gas. To calculate Volume of Box having Gas Molecule given Pressure, you need Mass per Molecule (m), Speed of Particle (u) & Pressure of Gas (Pgas). With our tool, you need to enter the respective value for Mass per Molecule, Speed of Particle & Pressure of Gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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