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## Volume Of Conductor Material (2-phase 4-wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
volume_of_conductor_material = 2*Area Of 2-Φ 4-wire system*Length
V = 2*a7*l
This formula uses 2 Variables
Variables Used
Area Of 2-Φ 4-wire system - The Area Of 2-Φ 4-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Area Of 2-Φ 4-wire system: 7 Square Meter --> 7 Square Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = 2*a7*l --> 2*7*3
Evaluating ... ...
V = 42
STEP 3: Convert Result to Output's Unit
42 Cubic Meter --> No Conversion Required
42 Cubic Meter <-- Volume Of Conductor Material
(Calculation completed in 00.016 seconds)

## < 11 Other formulas that you can solve using the same Inputs

Surface Area of a Rectangular Prism
surface_area = 2*(Length*Width+Length*Height+Width*Height) Go
Magnetic Flux
Perimeter of a rectangle when diagonal and length are given
perimeter = 2*(Length+sqrt((Diagonal)^2-(Length)^2)) Go
Diagonal of a Rectangle when length and area are given
diagonal = sqrt(((Area)^2/(Length)^2)+(Length)^2) Go
Area of a Rectangle when length and diagonal are given
area = Length*(sqrt((Diagonal)^2-(Length)^2)) Go
Diagonal of a Rectangle when length and breadth are given
Volume of a Rectangular Prism
volume = Width*Height*Length Go
Strain
strain = Change In Length/Length Go
Surface Tension when Force and Length are Given
surface_tension = Force/Length Go
Perimeter of a rectangle when length and width are given
perimeter = 2*Length+2*Width Go
Area of a Rectangle when length and breadth are given

## < 11 Other formulas that calculate the same Output

Volume Of Conductor Material(2-Phase 3-Wire OS)
volume_of_conductor_material = (2+sqrt(2))*Area Of 2-Φ 3-wire system*Length Go
Volume Of Conductor Material Using Area Of X-Section(2-phase 3-wire OS)
volume_of_conductor_material = (2+sqrt(2))*Area Of X-Section*Length Go
Volume Of Conductor Material Using Area Of X-section(1-Phase 2-Wire Mid-point Earthed OS)
volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length Go
Volume Of Conductor Material(Two-Wire Mid-point Earthed)
volume_of_conductor_material = (2)*Area Of 2-wire Mid-point DC system*Length Go
Volume Of Conductor Material(1-Phase 2-Wire Mid-Point Earthed)
volume_of_conductor_material = 2*Area Of 1-Φ 2-wire mid-point system*Length Go
Volume Of Conductor Material(2-Phase 4-Wire OS)
volume_of_conductor_material = (4)*Area Of 2-Φ 4-wire system*Length Go
Volume Of Conductor Material(1-Phase 2-Wire OS)
volume_of_conductor_material = 2*Area Of 1-Φ 2-wire system*Length Go
Volume Of Conductor Material(1-Phase 3-Wire OS)
volume_of_conductor_material = (2.5)*Area Of X-Section*Length Go
Volume Of Conductor Material(3-Phase 4-Wire OS)
volume_of_conductor_material = (3.5)*Area Of X-Section*Length Go
Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS)
volume_of_conductor_material = (4)*Area Of X-Section*Length Go
Volume Of Conductor Material(3-Phase 3-Wire OS)
volume_of_conductor_material = (3)*Area Of X-Section*Length Go

### Volume Of Conductor Material (2-phase 4-wire US) Formula

volume_of_conductor_material = 2*Area Of 2-Φ 4-wire system*Length
V = 2*a7*l

## What is the volume of conductor material in 2-phase 4-wire underground system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

## How to Calculate Volume Of Conductor Material (2-phase 4-wire US)?

Volume Of Conductor Material (2-phase 4-wire US) calculator uses volume_of_conductor_material = 2*Area Of 2-Φ 4-wire system*Length to calculate the Volume Of Conductor Material, The Volume Of Conductor Material (2-phase 4-wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of the two-phase four-wire underground system. Volume Of Conductor Material and is denoted by V symbol.

How to calculate Volume Of Conductor Material (2-phase 4-wire US) using this online calculator? To use this online calculator for Volume Of Conductor Material (2-phase 4-wire US), enter Area Of 2-Φ 4-wire system (a7) and Length (l) and hit the calculate button. Here is how the Volume Of Conductor Material (2-phase 4-wire US) calculation can be explained with given input values -> 42 = 2*7*3.

### FAQ

What is Volume Of Conductor Material (2-phase 4-wire US)?
The Volume Of Conductor Material (2-phase 4-wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of the two-phase four-wire underground system and is represented as V = 2*a7*l or volume_of_conductor_material = 2*Area Of 2-Φ 4-wire system*Length. The Area Of 2-Φ 4-wire system is the amount of two-dimensional space taken up by an object and Length is the measurement or extent of something from end to end.
How to calculate Volume Of Conductor Material (2-phase 4-wire US)?
The Volume Of Conductor Material (2-phase 4-wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of the two-phase four-wire underground system is calculated using volume_of_conductor_material = 2*Area Of 2-Φ 4-wire system*Length. To calculate Volume Of Conductor Material (2-phase 4-wire US), you need Area Of 2-Φ 4-wire system (a7) and Length (l). With our tool, you need to enter the respective value for Area Of 2-Φ 4-wire system and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor Material?
In this formula, Volume Of Conductor Material uses Area Of 2-Φ 4-wire system and Length. We can use 11 other way(s) to calculate the same, which is/are as follows -
• volume_of_conductor_material = 2*Area Of 1-Φ 2-wire system*Length
• volume_of_conductor_material = 2*Area Of 1-Φ 2-wire mid-point system*Length
• volume_of_conductor_material = (2.5)*Area Of X-Section*Length
• volume_of_conductor_material = (4)*Area Of 2-Φ 4-wire system*Length
• volume_of_conductor_material = (3.5)*Area Of X-Section*Length
• volume_of_conductor_material = (3)*Area Of X-Section*Length
• volume_of_conductor_material = (2+sqrt(2))*Area Of 2-Φ 3-wire system*Length
• volume_of_conductor_material = (2)*Area Of 2-wire Mid-point DC system*Length
• volume_of_conductor_material = (2+sqrt(2))*Area Of X-Section*Length
• volume_of_conductor_material = (4)*Area Of X-Section*Length
• volume_of_conductor_material = (2)*Area Of 1-Φ 2-wire mid-point system*Length
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