Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC
V = 2*A*l
This formula uses 3 Variables
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Area of underground dc wire - (Measured in Square Meter) - The Area of underground dc wire is the amount of two-dimensional space taken up by an object.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.
STEP 1: Convert Input(s) to Base Unit
Area of underground dc wire: 0.32 Square Meter --> 0.32 Square Meter No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = 2*A*l --> 2*0.32*3.2
Evaluating ... ...
V = 2.048
STEP 3: Convert Result to Output's Unit
2.048 Cubic Meter --> No Conversion Required
FINAL ANSWER
2.048 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.020 seconds)

Credits

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9 Wire Parameters Calculators

Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)
Go Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2))
Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US)
Go Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2))
Length using Area of X-Section (2-Wire Mid-Point Earthed DC US)
Go Length of Wire DC = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*(Power Transmitted^2)*Resistivity)
Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Volume Of Conductor = 4*Resistivity*(Power Transmitted^2)*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Line Losses = 4*Resistivity*(Power Transmitted^2*Length of Wire DC^2)/(Maximum Voltage^2*Volume Of Conductor)
Length using Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Length of Wire DC = sqrt((Volume Of Conductor*Line Losses)/(4*(Current underground DC^2)*(Resistivity)))
Volume of Conductor Material using Load Current (2-Wire Mid-Point DC US)
Go Volume Of Conductor = 4*Resistivity*(Current underground DC^2)*(Length of Wire DC^2)/(Line Losses)
Area using Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Area of underground dc wire = Volume Of Conductor/(2*Length of Wire DC)
Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US)
Go Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC

Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) Formula

Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC
V = 2*A*l

What is the volume of conductor material in DC two-wire mid-point underground system?

The volume of conductor material required in this system is as of the 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US)?

Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) calculator uses Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC to calculate the Volume Of Conductor, The Volume of Conductor Material using Area and Length (2-wire Mid-point DC US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC two-wire mid-point underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) using this online calculator? To use this online calculator for Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US), enter Area of underground dc wire (A) & Length of Wire DC (l) and hit the calculate button. Here is how the Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) calculation can be explained with given input values -> 2.048 = 2*0.32*3.2.

FAQ

What is Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US)?
The Volume of Conductor Material using Area and Length (2-wire Mid-point DC US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC two-wire mid-point underground system and is represented as V = 2*A*l or Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC. The Area of underground dc wire is the amount of two-dimensional space taken up by an object & Length of Wire DC is the measurement or extent of something from end to end.
How to calculate Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US)?
The Volume of Conductor Material using Area and Length (2-wire Mid-point DC US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC two-wire mid-point underground system is calculated using Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC. To calculate Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US), you need Area of underground dc wire (A) & Length of Wire DC (l). With our tool, you need to enter the respective value for Area of underground dc wire & Length of Wire DC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Area of underground dc wire & Length of Wire DC. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 4*Resistivity*(Power Transmitted^2)*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
  • Volume Of Conductor = 4*Resistivity*(Current underground DC^2)*(Length of Wire DC^2)/(Line Losses)
  • Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2))
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