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Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
volume_of_conductor_material = (4)*Area Of X-Section*Length
V = (4)*a*l
This formula uses 2 Variables
Variables Used
Area Of X-Section - Area Of X-Section is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” (Measured in Square Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Area Of X-Section: 5 Square Meter --> 5 Square Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (4)*a*l --> (4)*5*3
Evaluating ... ...
V = 60
STEP 3: Convert Result to Output's Unit
60 Cubic Meter --> No Conversion Required
FINAL ANSWER
60 Cubic Meter <-- Volume Of Conductor Material
(Calculation completed in 00.000 seconds)

9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-Section(2-phase 4-wire OS)
power_transmitted = sqrt((2*Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length)) Go
Maximum Voltage Using Area Of X-section(2-phase 4-wire OS)
maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(2*Area Of X-Section*Line Losses*((cos(Theta))^2))) Go
RMS Voltage Using Area Of X-Section(2-phase 4-wire OS)
rms_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-section(2-phase 4-wire OS)
power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(2*Area Of X-Section*Line Losses*(Maximum Voltage^2))) Go
Line Losses Using Area Of X-Section(2-phase 4-wire OS)
line_losses = (Length*Resistivity*(Power Transmitted^2))/(2*Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Of Wire Using Area Of X-section(2-phase 4-wire OS)
length = 2*Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2)) Go
Resistivity Using Area Of X-Section(2-phase 4-wire OS)
resistivity = 2*Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2)) Go
Load Current Using Area Of X-section(2-phase 4-wire OS)
load_current = sqrt(Line Losses*Area Of X-Section/((32)*Resistivity*Length)) Go
Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS)
volume_of_conductor_material = (4)*Area Of X-Section*Length Go

Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS) Formula

volume_of_conductor_material = (4)*Area Of X-Section*Length
V = (4)*a*l

What is the value of maximum voltage and volume of conductor material in 2-phase 4-wire system?

The volume of conductor material required in this system is 1/2cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is 2vm so that r.m.s. value of voltage between them is √2vm.

How to Calculate Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS)?

Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS) calculator uses volume_of_conductor_material = (4)*Area Of X-Section*Length to calculate the Volume Of Conductor Material, The Volume Of Conductor Material Using Area Of X-section(2-phase 4-wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire overhead system. Volume Of Conductor Material and is denoted by V symbol.

How to calculate Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS) using this online calculator? To use this online calculator for Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS), enter Area Of X-Section (a) and Length (l) and hit the calculate button. Here is how the Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS) calculation can be explained with given input values -> 60 = (4)*5*3.

FAQ

What is Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS)?
The Volume Of Conductor Material Using Area Of X-section(2-phase 4-wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire overhead system and is represented as V = (4)*a*l or volume_of_conductor_material = (4)*Area Of X-Section*Length. Area Of X-Section is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” and Length is the measurement or extent of something from end to end.
How to calculate Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS)?
The Volume Of Conductor Material Using Area Of X-section(2-phase 4-wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire overhead system is calculated using volume_of_conductor_material = (4)*Area Of X-Section*Length. To calculate Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS), you need Area Of X-Section (a) and Length (l). With our tool, you need to enter the respective value for Area Of X-Section and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor Material?
In this formula, Volume Of Conductor Material uses Area Of X-Section and Length. We can use 9 other way(s) to calculate the same, which is/are as follows -
  • line_losses = (Length*Resistivity*(Power Transmitted^2))/(2*Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2))
  • maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(2*Area Of X-Section*Line Losses*((cos(Theta))^2)))
  • power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(2*Area Of X-Section*Line Losses*(Maximum Voltage^2)))
  • power_transmitted = sqrt((2*Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length))
  • resistivity = 2*Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2))
  • length = 2*Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2))
  • volume_of_conductor_material = (4)*Area Of X-Section*Length
  • load_current = sqrt(Line Losses*Area Of X-Section/((32)*Resistivity*Length))
  • rms_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*Line Losses*((cos(Theta))^2)))
Where is the Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS) calculator used?
Among many, Volume Of Conductor Material Using Area Of X-Section(2-phase 4-wire OS) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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