Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) Calculator

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) [V]

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Formula

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Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)

Formula

`"V" = "A"*"L"*2`

Example

`"61.44m³"="1.28m²"*"24m"*2`

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Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2
V = A*L*2
This formula uses 3 Variables

Variables Used

Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V = A*L*2 --> 1.28*24*2

Evaluating ... ...

V = 61.44

STEP 3: Convert Result to Output's Unit

61.44 Cubic Meter --> No Conversion Required

FINAL ANSWER

61.44 Cubic Meter <-- Volume Of Conductor

(Calculation completed in 00.006 seconds)

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< 23 Wire Parameters Calculators

Area of X-Section using Line Losses (1-Phase 2-Wire US)

Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Area of X-Section (1-Phase 2-Wire US)

Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Length using Area of X-Section (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)

Length using Line Losses (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)

Volume of Conductor Material using Line Losses (1-Phase 2-Wire US)

Go Volume Of Conductor = 8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Constant using Resistance (1-Phase 2-Wire US)

Go Constant Underground AC = (4*Power Transmitted*Length of Underground AC Wire*Resistance Underground AC*Area of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2))

Length of Wire using Constant (1-Phase 2-Wire US)

Go Length of Underground AC Wire = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Power Transmitted)^2))

Constant using Load Current (1-Phase 2-Wire US)

Go Constant Underground AC = 2*(Current Underground AC^2)*(cos(Phase Difference)^2)*Resistivity*(Length of Underground AC Wire^2)/Line Losses

Constant (1-Phase 2-Wire US)

Go Constant Underground AC = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)

Constant using Line Losses (1-Phase 2-Wire US)

Go Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2)

Length using Load Current (1-Phase 2-Wire US)

Go Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)

Area of X-Section using Load Current (1-Phase 2-Wire US)

Go Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses)

Volume of Conductor Material using Load Current (1-Phase 2-Wire US)

Go Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)

Constant using Area of X-Section (1-Phase 2-Wire US)

Go Constant Underground AC = Area of Underground AC Wire*Length of Underground AC Wire*(cos(Phase Difference))^2

Area of X-Section using Constant (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Constant Underground AC/Length of Underground AC Wire*(cos(Phase Difference))^2

Length using Resistance (1-Phase 2-Wire US)

Go Length of Underground AC Wire = (Resistance Underground AC*Area of Underground AC Wire)/(Resistivity)

Area of X-Section using Resistance (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/Resistance Underground AC

Constant using Volume of Conductor Material (1-Phase 2-Wire US)

Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference))^2/2

Volume of Conductor Material using Constant (1-Phase 2-Wire US)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2

Voltage of Conductor Material (1-Phase 2-Wire US)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2

Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)

Length using Volume of Conductor Material (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)

Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)

Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) Formula

Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2
V = A*L*2

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)?

Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) calculator uses Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2 to calculate the Volume Of Conductor, The Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US), enter Area of Underground AC Wire (A) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 61.44 = 1.28*24*2.

FAQ

What is Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)?

The Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire underground system and is represented as V = A*L*2 or Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2. Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)?

The Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire underground system is calculated using Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2. To calculate Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US), you need Area of Underground AC Wire (A) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Area of Underground AC Wire & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Volume Of Conductor?

In this formula, Volume Of Conductor uses Area of Underground AC Wire & Length of Underground AC Wire. We can use 4 other way(s) to calculate the same, which is/are as follows -

Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)
Volume Of Conductor = 8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2

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