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Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2
V = a4*l*2
This formula uses 2 Variables
Variables Used
Area Of 1-Φ 2-wire system - The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Area Of 1-Φ 2-wire system: 6 Square Meter --> 6 Square Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = a4*l*2 --> 6*3*2
Evaluating ... ...
V = 36
STEP 3: Convert Result to Output's Unit
36 Cubic Meter --> No Conversion Required
FINAL ANSWER
36 Cubic Meter <-- Volume Of Conductor Material
(Calculation completed in 00.011 seconds)

9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-Section (1-Phase 2-Wire US)
power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length)) Go
Maximum Voltage Using Area Of X-Section (1-Phase 2-Wire US)
maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2)) Go
RMS Voltage Using Area Of X-Section (1-Phase 2-Wire US)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-Section (1-Phase 2-Wire US)
power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2))) Go
Resistivity Using Area Of X-Section (1-Phase 2-Wire US)
resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2)) Go
Line Losses Using Area Of X-Section (1-Phase 2-Wire US)
line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Using Area Of X-Section (1-Phase 2-Wire US)
length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity) Go
Constant Using Area Of X-Section (1-Phase 2-Wire US)
constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2 Go
Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US)
volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2 Go

Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) Formula

volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2
V = a4*l*2

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US)?

Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) calculator uses volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2 to calculate the Volume Of Conductor Material, The Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire underground system. Volume Of Conductor Material and is denoted by V symbol.

How to calculate Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US), enter Area Of 1-Φ 2-wire system (a4) and Length (l) and hit the calculate button. Here is how the Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 36 = 6*3*2.

FAQ

What is Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US)?
The Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire underground system and is represented as V = a4*l*2 or volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2. The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object and Length is the measurement or extent of something from end to end.
How to calculate Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US)?
The Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire underground system is calculated using volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2. To calculate Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US), you need Area Of 1-Φ 2-wire system (a4) and Length (l). With our tool, you need to enter the respective value for Area Of 1-Φ 2-wire system and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor Material?
In this formula, Volume Of Conductor Material uses Area Of 1-Φ 2-wire system and Length. We can use 9 other way(s) to calculate the same, which is/are as follows -
  • power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length))
  • resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2))
  • length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity)
  • line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2))
  • maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2))
  • rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
  • power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2)))
  • constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2
  • volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2
Where is the Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) calculator used?
Among many, Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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