Volume of Conductor Material using Load Current (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)
V = 4*(I^2)*ρ*(L^2)/(Ploss)
This formula uses 5 Variables
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
STEP 1: Convert Input(s) to Base Unit
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = 4*(I^2)*ρ*(L^2)/(Ploss) --> 4*(9^2)*1.7E-05*(24^2)/(2.67)
Evaluating ... ...
V = 1.18824269662921
STEP 3: Convert Result to Output's Unit
1.18824269662921 Cubic Meter --> No Conversion Required
FINAL ANSWER
1.18824269662921 1.188243 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

Credits

Created by Urvi Rathod
Vishwakarma Government Engineering College (VGEC), Ahmedabad
Urvi Rathod has created this Calculator and 1500+ more calculators!
Verified by Payal Priya
Birsa Institute of Technology (BIT), Sindri
Payal Priya has verified this Calculator and 1900+ more calculators!

23 Wire Parameters Calculators

Area of X-Section using Line Losses (1-Phase 2-Wire US)
Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Area of X-Section (1-Phase 2-Wire US)
Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Length using Area of X-Section (1-Phase 2-Wire US)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
Length using Line Losses (1-Phase 2-Wire US)
Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
Volume of Conductor Material using Line Losses (1-Phase 2-Wire US)
Go Volume Of Conductor = 8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Constant using Resistance (1-Phase 2-Wire US)
Go Constant Underground AC = (4*Power Transmitted*Length of Underground AC Wire*Resistance Underground AC*Area of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2))
Length of Wire using Constant (1-Phase 2-Wire US)
Go Length of Underground AC Wire = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Power Transmitted)^2))
Constant using Load Current (1-Phase 2-Wire US)
Go Constant Underground AC = 2*(Current Underground AC^2)*(cos(Phase Difference)^2)*Resistivity*(Length of Underground AC Wire^2)/Line Losses
Constant (1-Phase 2-Wire US)
Go Constant Underground AC = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)
Constant using Line Losses (1-Phase 2-Wire US)
Go Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2)
Length using Load Current (1-Phase 2-Wire US)
Go Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)
Area of X-Section using Load Current (1-Phase 2-Wire US)
Go Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses)
Volume of Conductor Material using Load Current (1-Phase 2-Wire US)
Go Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)
Constant using Area of X-Section (1-Phase 2-Wire US)
Go Constant Underground AC = Area of Underground AC Wire*Length of Underground AC Wire*(cos(Phase Difference))^2
Area of X-Section using Constant (1-Phase 2-Wire US)
Go Area of Underground AC Wire = Constant Underground AC/Length of Underground AC Wire*(cos(Phase Difference))^2
Length using Resistance (1-Phase 2-Wire US)
Go Length of Underground AC Wire = (Resistance Underground AC*Area of Underground AC Wire)/(Resistivity)
Area of X-Section using Resistance (1-Phase 2-Wire US)
Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/Resistance Underground AC
Constant using Volume of Conductor Material (1-Phase 2-Wire US)
Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference))^2/2
Volume of Conductor Material using Constant (1-Phase 2-Wire US)
Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
Voltage of Conductor Material (1-Phase 2-Wire US)
Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)
Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
Length using Volume of Conductor Material (1-Phase 2-Wire US)
Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)
Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Volume of Conductor Material using Load Current (1-Phase 2-Wire US) Formula

Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)
V = 4*(I^2)*ρ*(L^2)/(Ploss)

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire US)?

Volume of Conductor Material using Load Current (1-Phase 2-Wire US) calculator uses Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses) to calculate the Volume Of Conductor, The Volume of Conductor Material using Load Current (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire overhead system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Load Current (1-Phase 2-Wire US), enter Current Underground AC (I), Resistivity (ρ), Length of Underground AC Wire (L) & Line Losses (Ploss) and hit the calculate button. Here is how the Volume of Conductor Material using Load Current (1-Phase 2-Wire US) calculation can be explained with given input values -> 1.188243 = 4*(9^2)*1.7E-05*(24^2)/(2.67).

FAQ

What is Volume of Conductor Material using Load Current (1-Phase 2-Wire US)?
The Volume of Conductor Material using Load Current (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire overhead system and is represented as V = 4*(I^2)*ρ*(L^2)/(Ploss) or Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses). Current Underground AC is defined as the current flowing through the overhead ac supply wire, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end & Line Losses is defined as the total losses occurring in an Underground AC line when in use.
How to calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire US)?
The Volume of Conductor Material using Load Current (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire overhead system is calculated using Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses). To calculate Volume of Conductor Material using Load Current (1-Phase 2-Wire US), you need Current Underground AC (I), Resistivity (ρ), Length of Underground AC Wire (L) & Line Losses (Ploss). With our tool, you need to enter the respective value for Current Underground AC, Resistivity, Length of Underground AC Wire & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Current Underground AC, Resistivity, Length of Underground AC Wire & Line Losses. We can use 4 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
  • Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2
  • Volume Of Conductor = 8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
  • Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!