Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2))
V = (4*A*R1*(P^2)*(l))/(Pline*(Vm^2))
This formula uses 7 Variables
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Area of underground dc wire - (Measured in Square Meter) - The Area of underground dc wire is the amount of two-dimensional space taken up by an object.
Resistance underground DC - (Measured in Ohm) - Resistance underground DC is defined as the time rate of flow of charge through a cross-sectional area.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.
Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Maximum Voltage - (Measured in Volt) - Maximum Voltage the highest voltage rating for electrical devices.
STEP 1: Convert Input(s) to Base Unit
Area of underground dc wire: 0.32 Square Meter --> 0.32 Square Meter No Conversion Required
Resistance underground DC: 5 Ohm --> 5 Ohm No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (4*A*R1*(P^2)*(l))/(Pline*(Vm^2)) --> (4*0.32*5*(300^2)*(3.2))/(0.6*(60^2))
Evaluating ... ...
V = 853.333333333333
STEP 3: Convert Result to Output's Unit
853.333333333333 Cubic Meter --> No Conversion Required
FINAL ANSWER
853.333333333333 853.3333 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

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9 Wire Parameters Calculators

Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)
Go Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2))
Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US)
Go Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2))
Length using Area of X-Section (2-Wire Mid-Point Earthed DC US)
Go Length of Wire DC = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*(Power Transmitted^2)*Resistivity)
Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Volume Of Conductor = 4*Resistivity*(Power Transmitted^2)*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Line Losses = 4*Resistivity*(Power Transmitted^2*Length of Wire DC^2)/(Maximum Voltage^2*Volume Of Conductor)
Length using Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Length of Wire DC = sqrt((Volume Of Conductor*Line Losses)/(4*(Current underground DC^2)*(Resistivity)))
Volume of Conductor Material using Load Current (2-Wire Mid-Point DC US)
Go Volume Of Conductor = 4*Resistivity*(Current underground DC^2)*(Length of Wire DC^2)/(Line Losses)
Area using Volume of Conductor Material (2-Wire Mid-Point DC US)
Go Area of underground dc wire = Volume Of Conductor/(2*Length of Wire DC)
Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US)
Go Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC

Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US) Formula

Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2))
V = (4*A*R1*(P^2)*(l))/(Pline*(Vm^2))

What is the volume of conductor material in DC two-wire mid-point underground system?

The volume of conductor material required in this system is as of the 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US)?

Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US) calculator uses Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2)) to calculate the Volume Of Conductor, The Volume of Conductor Material using Resistance (2-wire Mid-point DC US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC two-wire mid-point underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US) using this online calculator? To use this online calculator for Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US), enter Area of underground dc wire (A), Resistance underground DC (R1), Power Transmitted (P), Length of Wire DC (l), Line Losses (Pline) & Maximum Voltage (Vm) and hit the calculate button. Here is how the Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US) calculation can be explained with given input values -> 853.3333 = (4*0.32*5*(300^2)*(3.2))/(0.6*(60^2)).

FAQ

What is Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US)?
The Volume of Conductor Material using Resistance (2-wire Mid-point DC US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC two-wire mid-point underground system and is represented as V = (4*A*R1*(P^2)*(l))/(Pline*(Vm^2)) or Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2)). The Area of underground dc wire is the amount of two-dimensional space taken up by an object, Resistance underground DC is defined as the time rate of flow of charge through a cross-sectional area, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Length of Wire DC is the measurement or extent of something from end to end, Line Losses is defined as the losses that are produced in the line & Maximum Voltage the highest voltage rating for electrical devices.
How to calculate Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US)?
The Volume of Conductor Material using Resistance (2-wire Mid-point DC US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC two-wire mid-point underground system is calculated using Volume Of Conductor = (4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2)). To calculate Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US), you need Area of underground dc wire (A), Resistance underground DC (R1), Power Transmitted (P), Length of Wire DC (l), Line Losses (Pline) & Maximum Voltage (Vm). With our tool, you need to enter the respective value for Area of underground dc wire, Resistance underground DC, Power Transmitted, Length of Wire DC, Line Losses & Maximum Voltage and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Area of underground dc wire, Resistance underground DC, Power Transmitted, Length of Wire DC, Line Losses & Maximum Voltage. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = 4*Resistivity*(Power Transmitted^2)*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
  • Volume Of Conductor = 2*Area of underground dc wire*Length of Wire DC
  • Volume Of Conductor = 4*Resistivity*(Current underground DC^2)*(Length of Wire DC^2)/(Line Losses)
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