Weight Density of Bar using Area at Section 1 of Bars of uniform Strength Solution

STEP 0: Pre-Calculation Summary
Formula Used
Specific Weight = (2.303*log10(Area 1/Area 2))*Uniform Stress/Length of Rod
γ = (2.303*log10(A1/A2))*σUniform/LRod
This formula uses 1 Functions, 5 Variables
Functions Used
log10 - The common logarithm, also known as the base-10 logarithm or the decimal logarithm, is a mathematical function that is the inverse of the exponential function., log10(Number)
Variables Used
Specific Weight - (Measured in Newton per Cubic Meter) - Specific Weight is defined as weight per unit volume.
Area 1 - (Measured in Square Meter) - Area 1 is the cross-sectional area at one end of a bar/shaft.
Area 2 - (Measured in Square Meter) - Area 2 is the cross-sectional area at the second end of the bar/section.
Uniform Stress - (Measured in Pascal) - Uniform Stress is one in which stress developed at every cross-section of the bar remains the same along the longitudinal axis.
Length of Rod - (Measured in Meter) - Length of Rod is defined as the total length of the conducting rod.
STEP 1: Convert Input(s) to Base Unit
Area 1: 0.001256 Square Meter --> 0.001256 Square Meter No Conversion Required
Area 2: 0.00125 Square Meter --> 0.00125 Square Meter No Conversion Required
Uniform Stress: 27 Megapascal --> 27000000 Pascal (Check conversion ​here)
Length of Rod: 1.83 Meter --> 1.83 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
γ = (2.303*log10(A1/A2))*σUniform/LRod --> (2.303*log10(0.001256/0.00125))*27000000/1.83
Evaluating ... ...
γ = 70662.977459371
STEP 3: Convert Result to Output's Unit
70662.977459371 Newton per Cubic Meter -->70.662977459371 Kilonewton per Cubic Meter (Check conversion ​here)
FINAL ANSWER
70.662977459371 70.66298 Kilonewton per Cubic Meter <-- Specific Weight
(Calculation completed in 00.008 seconds)

Credits

Creator Image
Created by Rithik Agrawal
National Institute of Technology Karnataka (NITK), Surathkal
Rithik Agrawal has created this Calculator and 1300+ more calculators!
Verifier Image
Coorg Institute of Technology (CIT), Coorg
Mithila Muthamma PA has verified this Calculator and 700+ more calculators!

Bar of Uniform Strength Calculators

Weight Density of Bar using Area at Section 1 of Bars of uniform Strength
​ LaTeX ​ Go Specific Weight = (2.303*log10(Area 1/Area 2))*Uniform Stress/Length of Rod
Area at Section 1 of Bars of Uniform Strength
​ LaTeX ​ Go Area 1 = Area 2*e^(Specific Weight*Length of Rod/Uniform Stress)
Area at Section 2 of Bars of Uniform Strength
​ LaTeX ​ Go Area 2 = Area 1/e^(Specific Weight*Length of Rod/Uniform Stress)

Weight Density of Bar using Area at Section 1 of Bars of uniform Strength Formula

​LaTeX ​Go
Specific Weight = (2.303*log10(Area 1/Area 2))*Uniform Stress/Length of Rod
γ = (2.303*log10(A1/A2))*σUniform/LRod

What is Uniform Strength of Bar?

The extreme fibers can be loaded to the maximum capacity of permissible stress (say p max), but they are loaded to less capacity. When a beam is suitably designed such that the extreme fibers are loaded to the maximum permissible stress p max by varying the cross section it will be known as a beam of uniform strength.

How to Calculate Weight Density of Bar using Area at Section 1 of Bars of uniform Strength?

Weight Density of Bar using Area at Section 1 of Bars of uniform Strength calculator uses Specific Weight = (2.303*log10(Area 1/Area 2))*Uniform Stress/Length of Rod to calculate the Specific Weight, The Weight Density of Bar using Area at Section 1 of Bars of uniform Strength is defined as self weight of bar. Specific Weight is denoted by γ symbol.

How to calculate Weight Density of Bar using Area at Section 1 of Bars of uniform Strength using this online calculator? To use this online calculator for Weight Density of Bar using Area at Section 1 of Bars of uniform Strength, enter Area 1 (A1), Area 2 (A2), Uniform Stress Uniform) & Length of Rod (LRod) and hit the calculate button. Here is how the Weight Density of Bar using Area at Section 1 of Bars of uniform Strength calculation can be explained with given input values -> 0.070663 = (2.303*log10(0.001256/0.00125))*27000000/1.83.

FAQ

What is Weight Density of Bar using Area at Section 1 of Bars of uniform Strength?
The Weight Density of Bar using Area at Section 1 of Bars of uniform Strength is defined as self weight of bar and is represented as γ = (2.303*log10(A1/A2))*σUniform/LRod or Specific Weight = (2.303*log10(Area 1/Area 2))*Uniform Stress/Length of Rod. Area 1 is the cross-sectional area at one end of a bar/shaft, Area 2 is the cross-sectional area at the second end of the bar/section, Uniform Stress is one in which stress developed at every cross-section of the bar remains the same along the longitudinal axis & Length of Rod is defined as the total length of the conducting rod.
How to calculate Weight Density of Bar using Area at Section 1 of Bars of uniform Strength?
The Weight Density of Bar using Area at Section 1 of Bars of uniform Strength is defined as self weight of bar is calculated using Specific Weight = (2.303*log10(Area 1/Area 2))*Uniform Stress/Length of Rod. To calculate Weight Density of Bar using Area at Section 1 of Bars of uniform Strength, you need Area 1 (A1), Area 2 (A2), Uniform Stress Uniform) & Length of Rod (LRod). With our tool, you need to enter the respective value for Area 1, Area 2, Uniform Stress & Length of Rod and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
© 2016-2026 calculatoratoz.com A softUsvista Inc. venture!



Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!