Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2))))
Φ = acos(sqrt(10*ρ*((P*L)^2)/(Ploss*V*((Vm)^2))))
This formula uses 3 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
acos - The inverse cosine function, is the inverse function of the cosine function. It is the function that takes a ratio as an input and returns the angle whose cosine is equal to that ratio., acos(Number)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
STEP 1: Convert Input(s) to Base Unit
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Φ = acos(sqrt(10*ρ*((P*L)^2)/(Ploss*V*((Vm)^2)))) --> acos(sqrt(10*1.7E-05*((300*24)^2)/(2.67*60*((230)^2))))
Evaluating ... ...
Φ = 1.53854310039205
STEP 3: Convert Result to Output's Unit
1.53854310039205 Radian -->88.1520262514535 Degree (Check conversion here)
FINAL ANSWER
88.1520262514535 88.15203 Degree <-- Phase Difference
(Calculation completed in 00.004 seconds)

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14 Wire Parameters Calculators

Volume of Conductor Material using Resistance (1 Phase 3 Wire US)
Go Volume Of Conductor = (10*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US)
Go Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2))))
Length using Volume of Conductor Material(1 Phase 3 Wire US)
Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/((10)*Resistivity*(Power Transmitted^2)))
Angle using Area of X Section (1 Phase 3 Wire US)
Go Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire)))
Length using Area of X Section (1 Phase 3 Wire US)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)/(4*(Power Transmitted^2)*Resistivity)
Line Losses using Area of X Section (1 Phase 3 Wire US)
Go Line Losses = 2*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2*cos(Phase Difference)^2))
Volume of Conductor Material(1 Phase 3 Wire US)
Go Volume Of Conductor = 10*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Line Losses using Volume of Conductor Material(1 Phase 3 Wire US)
Go Line Losses = 10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Volume Of Conductor*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
Area of X-Section using Line Losses (1 Phase 3 Wire US)
Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses
Length using Line Losses (1 Phase 3 Wire US)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses/(2*Current Underground AC*Resistivity)
Volume of Conductor Material using Load Current(1 Phase 3 Wire US)
Go Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
Constant using Volume of Conductor Material(1 Phase 3 Wire US)
Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference)^2)/(2.5)
Volume of Conductor Material using Constant(1 Phase 3 Wire US)
Go Volume Of Conductor = 2.5*Constant Underground AC/(cos(Phase Difference)^2)
Volume of Conductor Material using Area and Length (1 Phase 3 Wire US)
Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2.5

Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US) Formula

Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2))))
Φ = acos(sqrt(10*ρ*((P*L)^2)/(Ploss*V*((Vm)^2))))

What is the value of maximum voltage and volume of conductor material in 1-phase 3-wire system?

The volume of conductor material required in this system is 2.5/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US)?

Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US) calculator uses Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2)))) to calculate the Phase Difference, The Angle Of PF using Volume Of Conductor Material(1 phase 3 wire US) formula is defined as the phase angle between reactive and active power. Phase Difference is denoted by Φ symbol.

How to calculate Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US) using this online calculator? To use this online calculator for Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US), enter Resistivity (ρ), Power Transmitted (P), Length of Underground AC Wire (L), Line Losses (Ploss), Volume Of Conductor (V) & Maximum Voltage Underground AC (Vm) and hit the calculate button. Here is how the Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US) calculation can be explained with given input values -> 5050.739 = acos(sqrt(10*1.7E-05*((300*24)^2)/(2.67*60*((230)^2)))).

FAQ

What is Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US)?
The Angle Of PF using Volume Of Conductor Material(1 phase 3 wire US) formula is defined as the phase angle between reactive and active power and is represented as Φ = acos(sqrt(10*ρ*((P*L)^2)/(Ploss*V*((Vm)^2)))) or Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2)))). Resistivity is the measure of how strongly a material opposes the flow of current through them, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Length of Underground AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Volume Of Conductor the 3-dimensional space enclosed by a conductor material & Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
How to calculate Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US)?
The Angle Of PF using Volume Of Conductor Material(1 phase 3 wire US) formula is defined as the phase angle between reactive and active power is calculated using Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2)))). To calculate Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US), you need Resistivity (ρ), Power Transmitted (P), Length of Underground AC Wire (L), Line Losses (Ploss), Volume Of Conductor (V) & Maximum Voltage Underground AC (Vm). With our tool, you need to enter the respective value for Resistivity, Power Transmitted, Length of Underground AC Wire, Line Losses, Volume Of Conductor & Maximum Voltage Underground AC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Phase Difference?
In this formula, Phase Difference uses Resistivity, Power Transmitted, Length of Underground AC Wire, Line Losses, Volume Of Conductor & Maximum Voltage Underground AC. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire)))
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