Area of Octagon given Medium Diagonal Solution

STEP 0: Pre-Calculation Summary
Formula Used
Area of Octagon = 2*(sqrt(2)-1)*Medium Diagonal of Octagon^2
A = 2*(sqrt(2)-1)*dMedium^2
This formula uses 1 Functions, 2 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Area of Octagon - (Measured in Square Meter) - The Area of Octagon is the total quantity of plane enclosed by the boundary of the Regular Octagon.
Medium Diagonal of Octagon - (Measured in Meter) - The Medium Diagonal of Octagon is the length of medium diagonals or the line joining one vertex and any one of vertices that closest to the opposite vertex of first vertex of the Regular Octagon.
STEP 1: Convert Input(s) to Base Unit
Medium Diagonal of Octagon: 24 Meter --> 24 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
A = 2*(sqrt(2)-1)*dMedium^2 --> 2*(sqrt(2)-1)*24^2
Evaluating ... ...
A = 477.174023853806
STEP 3: Convert Result to Output's Unit
477.174023853806 Square Meter --> No Conversion Required
FINAL ANSWER
477.174023853806 477.174 Square Meter <-- Area of Octagon
(Calculation completed in 00.004 seconds)

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11 Area of Octagon Calculators

Area of Octagon given Edge Length and Inradius
Go Area of Octagon = 4*Edge Length of Octagon*Inradius of Octagon
Area of Octagon given Medium Diagonal
Go Area of Octagon = 2*(sqrt(2)-1)*Medium Diagonal of Octagon^2
Area of Octagon given Perimeter
Go Area of Octagon = (1+sqrt(2))*(Perimeter of Octagon^2)/32
Area of Octagon given Long Diagonal
Go Area of Octagon = (Long Diagonal of Octagon^2)/(sqrt(2))
Area of Octagon given Edge Length
Go Area of Octagon = 2*(1+sqrt(2))*Edge Length of Octagon^2
Area of Octagon given edge
Go Area of Octagon = 2*(1+sqrt(2))*Edge Length of Octagon^2
Area of Octagon
Go Area of Octagon = 2*(1+sqrt(2))*Edge Length of Octagon^2
Area of Octagon given Short Diagonal
Go Area of Octagon = sqrt(2)*Short Diagonal of Octagon^2
Area of Octagon given Circumradius
Go Area of Octagon = 2*sqrt(2)*Circumradius of Octagon^2
Area of Octagon given Inradius
Go Area of Octagon = 8*(sqrt(2)-1)*Inradius of Octagon^2
Area of Octagon given Height
Go Area of Octagon = 2*(sqrt(2)-1)*Height of Octagon^2

Area of Octagon given Medium Diagonal Formula

Area of Octagon = 2*(sqrt(2)-1)*Medium Diagonal of Octagon^2
A = 2*(sqrt(2)-1)*dMedium^2

What is an Octagon?

Octagon is a polygon in geometry, which has 8 sides and 8 angles. That means the number of vertices is 8 and the number of edges is 8. All the sides are joined with each other end-to-end to form a shape. These sides are in a straight line form; they are not curved or disjoint with each other. Each interior angle of a regular octagon is 135° and each exterior angle will be 45°.

How to Calculate Area of Octagon given Medium Diagonal?

Area of Octagon given Medium Diagonal calculator uses Area of Octagon = 2*(sqrt(2)-1)*Medium Diagonal of Octagon^2 to calculate the Area of Octagon, The Area of Octagon given Medium Diagonal formula is defined as the total quantity of plane enclosed by the boundary of the Regular Octagon and calculated using the medium diagonal of the Octagon. Area of Octagon is denoted by A symbol.

How to calculate Area of Octagon given Medium Diagonal using this online calculator? To use this online calculator for Area of Octagon given Medium Diagonal, enter Medium Diagonal of Octagon (dMedium) and hit the calculate button. Here is how the Area of Octagon given Medium Diagonal calculation can be explained with given input values -> 477.174 = 2*(sqrt(2)-1)*24^2.

FAQ

What is Area of Octagon given Medium Diagonal?
The Area of Octagon given Medium Diagonal formula is defined as the total quantity of plane enclosed by the boundary of the Regular Octagon and calculated using the medium diagonal of the Octagon and is represented as A = 2*(sqrt(2)-1)*dMedium^2 or Area of Octagon = 2*(sqrt(2)-1)*Medium Diagonal of Octagon^2. The Medium Diagonal of Octagon is the length of medium diagonals or the line joining one vertex and any one of vertices that closest to the opposite vertex of first vertex of the Regular Octagon.
How to calculate Area of Octagon given Medium Diagonal?
The Area of Octagon given Medium Diagonal formula is defined as the total quantity of plane enclosed by the boundary of the Regular Octagon and calculated using the medium diagonal of the Octagon is calculated using Area of Octagon = 2*(sqrt(2)-1)*Medium Diagonal of Octagon^2. To calculate Area of Octagon given Medium Diagonal, you need Medium Diagonal of Octagon (dMedium). With our tool, you need to enter the respective value for Medium Diagonal of Octagon and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Area of Octagon?
In this formula, Area of Octagon uses Medium Diagonal of Octagon. We can use 10 other way(s) to calculate the same, which is/are as follows -
  • Area of Octagon = 4*Edge Length of Octagon*Inradius of Octagon
  • Area of Octagon = 2*(1+sqrt(2))*Edge Length of Octagon^2
  • Area of Octagon = 2*(1+sqrt(2))*Edge Length of Octagon^2
  • Area of Octagon = (Long Diagonal of Octagon^2)/(sqrt(2))
  • Area of Octagon = sqrt(2)*Short Diagonal of Octagon^2
  • Area of Octagon = 2*(sqrt(2)-1)*Height of Octagon^2
  • Area of Octagon = (1+sqrt(2))*(Perimeter of Octagon^2)/32
  • Area of Octagon = 8*(sqrt(2)-1)*Inradius of Octagon^2
  • Area of Octagon = 2*sqrt(2)*Circumradius of Octagon^2
  • Area of Octagon = 2*(1+sqrt(2))*Edge Length of Octagon^2
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