Area of X-Section using Line Losses (1 Phase 3 Wire US) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Underground AC [I]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of X-Section using Line Losses (1 Phase 3 Wire US) [A]

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Formula

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Area of X-Section using Line Losses (1 Phase 3 Wire US)

Formula

`"A" = 2*"ρ"*"L"*("I"^2)/"P"_{"loss"}`

Example

`"0.024755m²"=2*"0.000017Ω*m"*"24m"*(("9A")^2)/"2.67W"`

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Area of X-Section using Line Losses (1 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses
A = 2*ρ*L*(I^2)/P_loss
This formula uses 5 Variables

Variables Used

Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

A = 2*ρ*L*(I^2)/P_loss --> 2*1.7E-05*24*(9^2)/2.67

Evaluating ... ...

A = 0.0247550561797753

STEP 3: Convert Result to Output's Unit

0.0247550561797753 Square Meter --> No Conversion Required

FINAL ANSWER

0.0247550561797753 ≈ 0.024755 Square Meter <-- Area of Underground AC Wire

(Calculation completed in 00.004 seconds)

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< 14 Wire Parameters Calculators

Volume of Conductor Material using Resistance (1 Phase 3 Wire US)

Go Volume Of Conductor = (10*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US)

Go Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2))))

Length using Volume of Conductor Material(1 Phase 3 Wire US)

Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/((10)*Resistivity*(Power Transmitted^2)))

Angle using Area of X Section (1 Phase 3 Wire US)

Go Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire)))

Length using Area of X Section (1 Phase 3 Wire US)

Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)/(4*(Power Transmitted^2)*Resistivity)

Line Losses using Area of X Section (1 Phase 3 Wire US)

Go Line Losses = 2*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2*cos(Phase Difference)^2))

Volume of Conductor Material(1 Phase 3 Wire US)

Go Volume Of Conductor = 10*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Line Losses using Volume of Conductor Material(1 Phase 3 Wire US)

Go Line Losses = 10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Volume Of Conductor*((Maximum Voltage Underground AC*cos(Phase Difference))^2))

Area of X-Section using Line Losses (1 Phase 3 Wire US)

Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses

Length using Line Losses (1 Phase 3 Wire US)

Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses/(2*Current Underground AC*Resistivity)

Volume of Conductor Material using Load Current(1 Phase 3 Wire US)

Go Volume Of Conductor = 5*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses

Constant using Volume of Conductor Material(1 Phase 3 Wire US)

Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference)^2)/(2.5)

Volume of Conductor Material using Constant(1 Phase 3 Wire US)

Go Volume Of Conductor = 2.5*Constant Underground AC/(cos(Phase Difference)^2)

Volume of Conductor Material using Area and Length (1 Phase 3 Wire US)

Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2.5

Area of X-Section using Line Losses (1 Phase 3 Wire US) Formula

Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses
A = 2*ρ*L*(I^2)/P_loss

What is the rms value of voltage?

The value of an AC voltage is continually changing from zero up to the positive peak, through zero to the negative peak, and back to zero again. The RMS value is the effective value of a varying voltage or current. It is the equivalent steady DC (constant) value that gives the same effect.

How to Calculate Area of X-Section using Line Losses (1 Phase 3 Wire US)?

Area of X-Section using Line Losses (1 Phase 3 Wire US) calculator uses Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses to calculate the Area of Underground AC Wire, The Area of X-Section using Line Losses (1 phase 3 wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to calculate Area of X-Section using Line Losses (1 Phase 3 Wire US) using this online calculator? To use this online calculator for Area of X-Section using Line Losses (1 Phase 3 Wire US), enter Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (P_loss) and hit the calculate button. Here is how the Area of X-Section using Line Losses (1 Phase 3 Wire US) calculation can be explained with given input values -> 0.024755 = 2*1.7E-05*24*(9^2)/2.67.

FAQ

What is Area of X-Section using Line Losses (1 Phase 3 Wire US)?

The Area of X-Section using Line Losses (1 phase 3 wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier and is represented as A = 2*ρ*L*(I^2)/P_loss or Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses. Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Current Underground AC is defined as the current flowing through the overhead ac supply wire & Line Losses is defined as the total losses occurring in an Underground AC line when in use.

How to calculate Area of X-Section using Line Losses (1 Phase 3 Wire US)?

The Area of X-Section using Line Losses (1 phase 3 wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier is calculated using Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire*(Current Underground AC^2)/Line Losses. To calculate Area of X-Section using Line Losses (1 Phase 3 Wire US), you need Resistivity (ρ), Length of Underground AC Wire (L), Current Underground AC (I) & Line Losses (P_loss). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Current Underground AC & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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