Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
A = V/(2*L)
This formula uses 3 Variables
Variables Used
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
STEP 1: Convert Input(s) to Base Unit
Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
A = V/(2*L) --> 60/(2*24)
Evaluating ... ...
A = 1.25
STEP 3: Convert Result to Output's Unit
1.25 Square Meter --> No Conversion Required
FINAL ANSWER
1.25 Square Meter <-- Area of Underground AC Wire
(Calculation completed in 00.004 seconds)

Credits

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Vishwakarma Government Engineering College (VGEC), Ahmedabad
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14 Wire Parameters Calculators

Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)
Angle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Phase Difference = acos(sqrt(4*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))))
Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)
Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = 8*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)
Go Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))
Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)
Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))
Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)
Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))
Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
Volume of Conductor Material using Constant(1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)
Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)
Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)
Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US)
Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) Formula

Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
A = V/(2*L)

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)?

Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) calculator uses Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire) to calculate the Area of Underground AC Wire, The Area using Volume of Conductor Material (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to calculate Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed), enter Volume Of Conductor (V) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 1.25 = 60/(2*24).

FAQ

What is Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)?
The Area using Volume of Conductor Material (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier and is represented as A = V/(2*L) or Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire). Volume Of Conductor the 3-dimensional space enclosed by a conductor material & Length of Underground AC Wire is the total length of the wire from one end to other end.
How to calculate Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)?
The Area using Volume of Conductor Material (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier is calculated using Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire). To calculate Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed), you need Volume Of Conductor (V) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Volume Of Conductor & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Area of Underground AC Wire?
In this formula, Area of Underground AC Wire uses Volume Of Conductor & Length of Underground AC Wire. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
  • Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))
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