Effective Head given Energy through Hydraulic Turbines Calculator

✖Energy through Hydraulic Turbines describes the power generated by the turbine.ⓘ Energy through Hydraulic Turbines [E_Turbines]			+10% -10%
✖Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc.ⓘ Rate of Flow [q_flow]			+10% -10%
✖Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy.ⓘ Efficiency of Hydropower [η]			+10% -10%
✖Time period of progressive wave is the time taken by a wave to complete one oscillation.ⓘ Time Period of Progressive Wave [T_w]			+10% -10%

✖Effective Head can be described as the actual vertical drop minus this head loss.ⓘ Effective Head given Energy through Hydraulic Turbines [H_eff]

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Formula

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Effective Head given Energy through Hydraulic Turbines

Formula

`"H"_{"eff"} = "E"_{"Turbines"}/(9.81*"q"_{"flow"}*"η"*"T"_{"w"})`

Example

`"0.799996m"= "522.36N*m"/(9.81*"32m³/s"*"0.80"*"2.6s")`

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Effective Head given Energy through Hydraulic Turbines Solution

STEP 0: Pre-Calculation Summary

Formula Used

Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave)
H_eff = E_Turbines/(9.81*q_flow*η*T_w)
This formula uses 5 Variables

Variables Used

Effective Head - (Measured in Meter) - Effective Head can be described as the actual vertical drop minus this head loss.
Energy through Hydraulic Turbines - (Measured in Joule) - Energy through Hydraulic Turbines describes the power generated by the turbine.
Rate of Flow - (Measured in Cubic Meter per Second) - Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc.
Efficiency of Hydropower - Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy.
Time Period of Progressive Wave - (Measured in Second) - Time period of progressive wave is the time taken by a wave to complete one oscillation.

STEP 1: Convert Input(s) to Base Unit

Energy through Hydraulic Turbines: 522.36 Newton Meter --> 522.36 Joule (Check conversion here)
Rate of Flow: 32 Cubic Meter per Second --> 32 Cubic Meter per Second No Conversion Required
Efficiency of Hydropower: 0.8 --> No Conversion Required
Time Period of Progressive Wave: 2.6 Second --> 2.6 Second No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

H_eff = E_Turbines/(9.81*q_flow*η*T_w) --> 522.36/(9.81*32*0.8*2.6)

Evaluating ... ...

H_eff = 0.799995589273112

STEP 3: Convert Result to Output's Unit

0.799995589273112 Meter --> No Conversion Required

FINAL ANSWER

0.799995589273112 ≈ 0.799996 Meter <-- Effective Head

(Calculation completed in 00.004 seconds)

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< 11 Assessment of Available Power Calculators

Head Loss given Energy through Hydraulic Turbines

Go Head Loss due to Friction = -((Energy through Hydraulic Turbines/ (9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave))-Head of Water)

Head given Energy through Hydraulic Turbines

Go Head of Water = (Energy through Hydraulic Turbines/ (9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave))+Head Loss due to Friction

Efficiency of Hydropower Station given Energy through Hydraulic Turbines

Go Efficiency of Hydropower = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Time Period of Progressive Wave)

Rate of Flow of Water given Energy through Hydraulic Turbines

Go Rate of Flow = Energy through Hydraulic Turbines/(9.81*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower*Time Period of Progressive Wave)

Period of Flow given Energy through Hydraulic Turbines

Go Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower)

Energy through Hydraulic Turbines

Go Energy through Hydraulic Turbines = (9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower*Time Period of Progressive Wave)

Amount of Hydropower

Go Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000

Effective Head given Energy through Hydraulic Turbines

Go Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave)

Head Loss given Amount of Hydropower

Go Head Loss due to Friction = ((Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))-Head of Water)

Head given Amount of Hydropower

Go Head of Water = (Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))+Head Loss due to Friction

Efficiency of Hydropower Station given Amount of Hydropower

Go Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water))

Effective Head given Energy through Hydraulic Turbines Formula

Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave)
H_eff = E_Turbines/(9.81*q_flow*η*T_w)

What is meant by Rate of Flow of Water?

The Flow rate of a liquid is a measure of the volume of liquid that moves in a certain amount of time. The flow rate depends on the area of the section.

How to Calculate Effective Head given Energy through Hydraulic Turbines?

Effective Head given Energy through Hydraulic Turbines calculator uses Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave) to calculate the Effective Head, Effective Head given Energy through Hydraulic Turbines is defined as actual vertical drop minus this head loss. Effective Head is denoted by H_eff symbol.

How to calculate Effective Head given Energy through Hydraulic Turbines using this online calculator? To use this online calculator for Effective Head given Energy through Hydraulic Turbines, enter Energy through Hydraulic Turbines (E_Turbines), Rate of Flow (q_flow), Efficiency of Hydropower (η) & Time Period of Progressive Wave (T_w) and hit the calculate button. Here is how the Effective Head given Energy through Hydraulic Turbines calculation can be explained with given input values -> 0.824944 = 522.36/(9.81*32*0.8*2.6).

FAQ

What is Effective Head given Energy through Hydraulic Turbines?

Effective Head given Energy through Hydraulic Turbines is defined as actual vertical drop minus this head loss and is represented as H_eff = E_Turbines/(9.81*q_flow*η*T_w) or Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave). Energy through Hydraulic Turbines describes the power generated by the turbine, Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc, Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy & Time period of progressive wave is the time taken by a wave to complete one oscillation.

How to calculate Effective Head given Energy through Hydraulic Turbines?

Effective Head given Energy through Hydraulic Turbines is defined as actual vertical drop minus this head loss is calculated using Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave). To calculate Effective Head given Energy through Hydraulic Turbines, you need Energy through Hydraulic Turbines (E_Turbines), Rate of Flow (q_flow), Efficiency of Hydropower (η) & Time Period of Progressive Wave (T_w). With our tool, you need to enter the respective value for Energy through Hydraulic Turbines, Rate of Flow, Efficiency of Hydropower & Time Period of Progressive Wave and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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