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Effective thermal conductivity for annular space between concentric cylinders Solution

STEP 0: Pre-Calculation Summary
Formula Used
effective_thermal_conductiviity = Heat transfer*((ln(Outside temperature/Inside temperature))/(2*pi)*(Inside Temperature-Outside Temperature))
keff = e′*((ln(To/Ti))/(2*pi)*(ti-to))
This formula uses 1 Constants, 1 Functions, 5 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Functions Used
ln - Natural logarithm function (base e), ln(Number)
Variables Used
Heat transfer- Heat transfer is defined as the movement of heat across the border of the system due to a difference in temperature between the system and its surroundings.
Outside temperature- Outside temperature is the value of the temperature at outside surface
Inside temperature- Inside temperature is the temperature value at the inside surface
Inside Temperature - Inside Temperature is the temperature of air present inside. (Measured in Fahrenheit)
Outside Temperature - Outside Temperature is the temperature of air present outside. (Measured in Fahrenheit)
STEP 1: Convert Input(s) to Base Unit
Heat transfer: 1 --> No Conversion Required
Outside temperature: 35 --> No Conversion Required
Inside temperature: 30 --> No Conversion Required
Inside Temperature: 98 Fahrenheit --> 309.816662311554 Kelvin (Check conversion here)
Outside Temperature: 102 Fahrenheit --> 312.03888463974 Kelvin (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
keff = e′*((ln(To/Ti))/(2*pi)*(ti-to)) --> 1*((ln(35/30))/(2*pi)*(309.816662311554-312.03888463974))
Evaluating ... ...
keff = -0.0545196529896632
STEP 3: Convert Result to Output's Unit
-0.0545196529896632 Watt per Meter per K --> No Conversion Required
FINAL ANSWER
-0.0545196529896632 Watt per Meter per K <-- Thermal conductivity
(Calculation completed in 00.016 seconds)

10+ Free convection Calculators

Boundary layer thickness on vertical surfaces
boundary_layer_thicknes_at_distance_x_from_leading_edge = 3.93*Distance from Point to YY Axis*(Prandtl number^(-0.5))*((0.952+Prandtl number)^0.25)*(Grashof number^(-0.25)) Go
Average Nusselt number for constant wall temperature
average_nusselt_number_upto_l = 0.68+((0.67*((Grashof number*Prandtl number)^0.25))/((1+((0.492/Prandtl number)^0.5625)^0.444))) Go
Nusselt number for all the value of GrPr and constant wall temperature
nusselt_number = (0.825+((0.387*((Grashof number*Prandtl number)^0.167))/((1+((0.492/Prandtl number)^0.5625)^0.296))))^2 Go
Nusselt number for all the value of GrPr and constant heat flux
nusselt_number = (0.825+((0.387*((Grashof number*Prandtl number)^0.167))/((1+((0.437/Prandtl number)^0.5625)^0.296))))^2 Go
Local Nusselt number for constant heat flux
local_nusselt_number_ = 0.508*(Prandtl number^0.5)*((0.952+Prandtl number)^(-0.25))*(Grashof number^0.25) Go
Convective mass transfer coefficient at distance X from the leading edge
convective_mass_transfer_coefficient = (2*Thermal Conductivity)/Boundary layer thickens Go
Local Nusselt number
local_nusselt_number = Distance from Point to YY Axis/Boundary layer thickens Go
Nusselt number for higher value of GrPr
average_nusselt_number_upto_l = 0.59*(Grashof number*Prandtl number)^0.25 Go
Local Nusselt number given Grashof number
local_nusselt_number_ = 0.6*((Grashof number*Prandtl number)^0.2) Go
Average Nusselt number upto L
average_nusselt_number_upto_l = (5/4)*Nusselt number Go

Effective thermal conductivity for annular space between concentric cylinders Formula

effective_thermal_conductiviity = Heat transfer*((ln(Outside temperature/Inside temperature))/(2*pi)*(Inside Temperature-Outside Temperature))
keff = e′*((ln(To/Ti))/(2*pi)*(ti-to))

What is convection?

Convection is the process of heat transfer by the bulk movement of molecules within fluids such as gases and liquids. The initial heat transfer between the object and the fluid takes place through conduction, but the bulk heat transfer happens due to the motion of the fluid. Convection is the process of heat transfer in fluids by the actual motion of matter. It happens in liquids and gases. It may be natural or forced. It involves a bulk transfer of portions of the fluid.

How to Calculate Effective thermal conductivity for annular space between concentric cylinders?

Effective thermal conductivity for annular space between concentric cylinders calculator uses effective_thermal_conductiviity = Heat transfer*((ln(Outside temperature/Inside temperature))/(2*pi)*(Inside Temperature-Outside Temperature)) to calculate the Thermal conductivity, The Effective thermal conductivity for annular space between concentric cylinders formula is defined as the transport of energy due to random molecular motion across a temperature gradient. Thermal conductivity and is denoted by keff symbol.

How to calculate Effective thermal conductivity for annular space between concentric cylinders using this online calculator? To use this online calculator for Effective thermal conductivity for annular space between concentric cylinders, enter Heat transfer (e′), Outside temperature (To), Inside temperature (Ti), Inside Temperature (ti) and Outside Temperature (to) and hit the calculate button. Here is how the Effective thermal conductivity for annular space between concentric cylinders calculation can be explained with given input values -> 0.000214 = 1*((ln(35/30))/(2*pi)*((-0.214034551291851)-(-0.222770655426213))).

FAQ

What is Effective thermal conductivity for annular space between concentric cylinders?
The Effective thermal conductivity for annular space between concentric cylinders formula is defined as the transport of energy due to random molecular motion across a temperature gradient and is represented as keff = e′*((ln(To/Ti))/(2*pi)*(ti-to)) or effective_thermal_conductiviity = Heat transfer*((ln(Outside temperature/Inside temperature))/(2*pi)*(Inside Temperature-Outside Temperature)). Heat transfer is defined as the movement of heat across the border of the system due to a difference in temperature between the system and its surroundings, Outside temperature is the value of the temperature at outside surface, Inside temperature is the temperature value at the inside surface, Inside Temperature is the temperature of air present inside and Outside Temperature is the temperature of air present outside.
How to calculate Effective thermal conductivity for annular space between concentric cylinders?
The Effective thermal conductivity for annular space between concentric cylinders formula is defined as the transport of energy due to random molecular motion across a temperature gradient is calculated using effective_thermal_conductiviity = Heat transfer*((ln(Outside temperature/Inside temperature))/(2*pi)*(Inside Temperature-Outside Temperature)). To calculate Effective thermal conductivity for annular space between concentric cylinders, you need Heat transfer (e′), Outside temperature (To), Inside temperature (Ti), Inside Temperature (ti) and Outside Temperature (to). With our tool, you need to enter the respective value for Heat transfer, Outside temperature, Inside temperature, Inside Temperature and Outside Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Thermal conductivity?
In this formula, Thermal conductivity uses Heat transfer, Outside temperature, Inside temperature, Inside Temperature and Outside Temperature. We can use 10 other way(s) to calculate the same, which is/are as follows -
  • boundary_layer_thicknes_at_distance_x_from_leading_edge = 3.93*Distance from Point to YY Axis*(Prandtl number^(-0.5))*((0.952+Prandtl number)^0.25)*(Grashof number^(-0.25))
  • convective_mass_transfer_coefficient = (2*Thermal Conductivity)/Boundary layer thickens
  • local_nusselt_number = Distance from Point to YY Axis/Boundary layer thickens
  • local_nusselt_number_ = 0.508*(Prandtl number^0.5)*((0.952+Prandtl number)^(-0.25))*(Grashof number^0.25)
  • local_nusselt_number_ = 0.6*((Grashof number*Prandtl number)^0.2)
  • average_nusselt_number_upto_l = (5/4)*Nusselt number
  • average_nusselt_number_upto_l = 0.68+((0.67*((Grashof number*Prandtl number)^0.25))/((1+((0.492/Prandtl number)^0.5625)^0.444)))
  • average_nusselt_number_upto_l = 0.59*(Grashof number*Prandtl number)^0.25
  • nusselt_number = (0.825+((0.387*((Grashof number*Prandtl number)^0.167))/((1+((0.437/Prandtl number)^0.5625)^0.296))))^2
  • nusselt_number = (0.825+((0.387*((Grashof number*Prandtl number)^0.167))/((1+((0.492/Prandtl number)^0.5625)^0.296))))^2
Where is the Effective thermal conductivity for annular space between concentric cylinders calculator used?
Among many, Effective thermal conductivity for annular space between concentric cylinders calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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