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Enantiomeric Excess Calculator

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✖Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.ⓘ Mole Fraction of R [FR]
+10%
-10%
✖Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.ⓘ Mole Fraction of S [FS]
+10%
-10%
✖Enantiomeric excess is defined as the absolute difference between the mole fraction of each enantiomer.ⓘ Enantiomeric Excess [ee]
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Formula
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Enantiomeric Excess

Formula
`"ee" = abs("F"_{"R"}-"F"_{"S"})`

Example
`"0.4"=abs("0.7"-"0.3")`

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Enantiomeric Excess Solution

STEP 0: Pre-Calculation Summary
Formula Used
Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)
ee = abs(FR-FS)
This formula uses 1 Functions, 3 Variables
Functions Used
abs - Absolut value function, abs(Number)
Variables Used
Enantiomeric Excess - Enantiomeric excess is defined as the absolute difference between the mole fraction of each enantiomer.
Mole Fraction of R - Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.
Mole Fraction of S - Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.
STEP 1: Convert Input(s) to Base Unit
Mole Fraction of R: 0.7 --> No Conversion Required
Mole Fraction of S: 0.3 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ee = abs(FR-FS) --> abs(0.7-0.3)
Evaluating ... ...
ee = 0.4
STEP 3: Convert Result to Output's Unit
0.4 --> No Conversion Required
FINAL ANSWER
0.4 <-- Enantiomeric Excess
(Calculation completed in 00.004 seconds)
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Created by Sangita Kalita
National Institute of Technology, Manipur (NIT Manipur), Imphal, Manipur
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National University of Judicial Science (NUJS), Kolkata
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7 Optical Activity Calculators

Percent Enantiomeric Excess Considering Amount of Enantiomer
Go Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100
Specific Rotation of Optically Active Compound
Go Specific Rotation = Observed Rotation/(Length Of Sample Tube*Concentration of Solution in Polarimeter)
Percent Enantiomeric Excess
Go Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100
Enantiomeric Excess
Go Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)
Optical Purity
Go Optical Purity = (Observed Specific Rotation/Maximum Specific Rotation)*100
Fraction of Major Isomer
Go Mole Fraction of R = 50+(Percent Enantiomeric Excess/2)
Fraction of Minor Isomer
Go Mole Fraction of S = 50-(Percent Enantiomeric Excess/2)

Enantiomeric Excess Formula

Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)
ee = abs(FR-FS)

What are R and S?

To name the enantiomers of a compound unambiguously, their names must include the "handedness" of the molecule. The method for this is formally known as R/S nomenclature. The letters "R" and "S" are determined by applying the Cahn-Ingold-Prelog (CIP) rules. The optical activity (+/-) can also be communicated in the name, but must be empirically derived.

How to Calculate Enantiomeric Excess?

Enantiomeric Excess calculator uses Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S) to calculate the Enantiomeric Excess, The Enantiomeric Excess formula is defined as the absolute difference between the mole fraction of each enantiomer. Enantiomeric Excess is denoted by ee symbol.

How to calculate Enantiomeric Excess using this online calculator? To use this online calculator for Enantiomeric Excess, enter Mole Fraction of R (FR) & Mole Fraction of S (FS) and hit the calculate button. Here is how the Enantiomeric Excess calculation can be explained with given input values -> 0.4 = abs(0.7-0.3).

FAQ

What is Enantiomeric Excess?
The Enantiomeric Excess formula is defined as the absolute difference between the mole fraction of each enantiomer and is represented as ee = abs(FR-FS) or Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S). Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture & Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.
How to calculate Enantiomeric Excess?
The Enantiomeric Excess formula is defined as the absolute difference between the mole fraction of each enantiomer is calculated using Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S). To calculate Enantiomeric Excess, you need Mole Fraction of R (FR) & Mole Fraction of S (FS). With our tool, you need to enter the respective value for Mole Fraction of R & Mole Fraction of S and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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