Percent Enantiomeric Excess Calculator

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✖Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.ⓘ Mole Fraction of R [F_R]			+10% -10%
✖Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.ⓘ Mole Fraction of S [F_S]			+10% -10%

✖Percent Enantiomeric Excess is a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other.ⓘ Percent Enantiomeric Excess [%ee]

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Formula

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Percent Enantiomeric Excess

Formula

`"%ee" = abs("F"_{"R"}-"F"_{"S"})*100`

Example

`"40"=abs("0.7"-"0.3")*100`

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Percent Enantiomeric Excess Solution

STEP 0: Pre-Calculation Summary

Formula Used

Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100
%ee = abs(F_R-F_S)*100
This formula uses 1 Functions, 3 Variables

Functions Used

abs - The absolute value of a number is its distance from zero on the number line. It's always a positive value, as it represents the magnitude of a number without considering its direction., abs(Number)

Variables Used

Percent Enantiomeric Excess - Percent Enantiomeric Excess is a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other.
Mole Fraction of R - Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.
Mole Fraction of S - Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.

STEP 1: Convert Input(s) to Base Unit

Mole Fraction of R: 0.7 --> No Conversion Required
Mole Fraction of S: 0.3 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

%ee = abs(F_R-F_S)*100 --> abs(0.7-0.3)*100

Evaluating ... ...

%ee = 40

STEP 3: Convert Result to Output's Unit

40 --> No Conversion Required

FINAL ANSWER

40 <-- Percent Enantiomeric Excess

(Calculation completed in 00.004 seconds)

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Created by Sangita Kalita

National Institute of Technology, Manipur (NIT Manipur), Imphal, Manipur

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< 7 Optical Activity Calculators

Percent Enantiomeric Excess Considering Amount of Enantiomer

Go Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100

Specific Rotation of Optically Active Compound

Go Specific Rotation = Observed Rotation/(Length Of Sample Tube*Concentration of Solution in Polarimeter)

Percent Enantiomeric Excess

Go Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100

Enantiomeric Excess

Go Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)

Optical Purity

Go Optical Purity = (Observed Specific Rotation/Maximum Specific Rotation)*100

Fraction of Major Isomer

Go Mole Fraction of R = 50+(Percent Enantiomeric Excess/2)

Fraction of Minor Isomer

Go Mole Fraction of S = 50-(Percent Enantiomeric Excess/2)

Percent Enantiomeric Excess Formula

Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100
%ee = abs(F_R-F_S)*100

What are R and S?

To name the enantiomers of a compound unambiguously, their names must include the "handedness" of the molecule. The method for this is formally known as R/S nomenclature. The letters "R" and "S" are determined by applying the Cahn-Ingold-Prelog (CIP) rules. The optical activity (+/-) can also be communicated in the name, but must be empirically derived.

How to Calculate Percent Enantiomeric Excess?

Percent Enantiomeric Excess calculator uses Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100 to calculate the Percent Enantiomeric Excess, The Percent Enantiomeric Excess formula is defined as a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other. Percent Enantiomeric Excess is denoted by %ee symbol.

How to calculate Percent Enantiomeric Excess using this online calculator? To use this online calculator for Percent Enantiomeric Excess, enter Mole Fraction of R (F_R) & Mole Fraction of S (F_S) and hit the calculate button. Here is how the Percent Enantiomeric Excess calculation can be explained with given input values -> 40 = abs(0.7-0.3)*100.

FAQ

What is Percent Enantiomeric Excess?

The Percent Enantiomeric Excess formula is defined as a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other and is represented as %ee = abs(F_R-F_S)*100 or Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100. Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture & Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.

How to calculate Percent Enantiomeric Excess?

The Percent Enantiomeric Excess formula is defined as a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other is calculated using Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100. To calculate Percent Enantiomeric Excess, you need Mole Fraction of R (F_R) & Mole Fraction of S (F_S). With our tool, you need to enter the respective value for Mole Fraction of R & Mole Fraction of S and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Percent Enantiomeric Excess?

In this formula, Percent Enantiomeric Excess uses Mole Fraction of R & Mole Fraction of S. We can use 1 other way(s) to calculate the same, which is/are as follows -

Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100

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