## Enthalpy using integrated form of Clausius-Clapeyron Equation Solution

STEP 0: Pre-Calculation Summary
Formula Used
Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature))
ΔH = (-ln(Pf/Pi)*[R])/((1/Tf)-(1/To))
This formula uses 1 Constants, 1 Functions, 5 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324 Joule / Kelvin * Mole
Functions Used
ln - Natural logarithm function (base e), ln(Number)
Variables Used
Change in Enthalpy - (Measured in Joule per Kilogram) - Change in enthalpy is the thermodynamic quantity equivalent to the total difference between the heat content of a system.
Final Pressure of System - (Measured in Pascal) - Final Pressure of System is the total final pressure exerted by the molecules inside the system.
Initial Pressure of System - (Measured in Pascal) - Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.
Final Temperature - (Measured in Kelvin) - The Final temperature is the temperature at which measurements are made in final state.
Initial Temperature - (Measured in Kelvin) - The Initial temperature is defined as the measure of heat under initial state or conditions.
STEP 1: Convert Input(s) to Base Unit
Final Pressure of System: 15 Pascal --> 15 Pascal No Conversion Required
Initial Pressure of System: 65 Pascal --> 65 Pascal No Conversion Required
Final Temperature: 27 Kelvin --> 27 Kelvin No Conversion Required
Initial Temperature: 20 Kelvin --> 20 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ΔH = (-ln(Pf/Pi)*[R])/((1/Tf)-(1/To)) --> (-ln(15/65)*[R])/((1/27)-(1/20))
Evaluating ... ...
ΔH = -940.510651687355
STEP 3: Convert Result to Output's Unit
-940.510651687355 Joule per Kilogram --> No Conversion Required
-940.510651687355 Joule per Kilogram <-- Change in Enthalpy
(Calculation completed in 00.031 seconds)
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## Credits

Created by Prerana Bakli
National Institute of Technology (NIT), Meghalaya
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National Institute of Information Technology (NIIT), Neemrana
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## Enthalpy using integrated form of Clausius-Clapeyron Equation Formula

Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature))
ΔH = (-ln(Pf/Pi)*[R])/((1/Tf)-(1/To))

## What is the Clausius–Clapeyron relation?

The Clausius–Clapeyron relation, named after Rudolf Clausius and Benoît Paul Émile Clapeyron, is a way of characterizing a discontinuous phase transition between two phases of matter of a single constituent. On a pressure–temperature (P–T) diagram, the line separating the two phases is known as the coexistence curve. The Clausius–Clapeyron relation gives the slope of the tangents to this curve.

## How to Calculate Enthalpy using integrated form of Clausius-Clapeyron Equation?

Enthalpy using integrated form of Clausius-Clapeyron Equation calculator uses Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature)) to calculate the Change in Enthalpy, The Enthalpy using integrated form of Clausius-Clapeyron Equation is the difference in heat on the final and initial state of the system. Change in Enthalpy is denoted by ΔH symbol.

How to calculate Enthalpy using integrated form of Clausius-Clapeyron Equation using this online calculator? To use this online calculator for Enthalpy using integrated form of Clausius-Clapeyron Equation, enter Final Pressure of System (Pf), Initial Pressure of System (Pi), Final Temperature (Tf) & Initial Temperature (To) and hit the calculate button. Here is how the Enthalpy using integrated form of Clausius-Clapeyron Equation calculation can be explained with given input values -> -940.510652 = (-ln(15/65)*[R])/((1/27)-(1/20)).

### FAQ

What is Enthalpy using integrated form of Clausius-Clapeyron Equation?
The Enthalpy using integrated form of Clausius-Clapeyron Equation is the difference in heat on the final and initial state of the system and is represented as ΔH = (-ln(Pf/Pi)*[R])/((1/Tf)-(1/To)) or Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature)). Final Pressure of System is the total final pressure exerted by the molecules inside the system, Initial Pressure of System is the total initial pressure exerted by the molecules inside the system, The Final temperature is the temperature at which measurements are made in final state & The Initial temperature is defined as the measure of heat under initial state or conditions.
How to calculate Enthalpy using integrated form of Clausius-Clapeyron Equation?
The Enthalpy using integrated form of Clausius-Clapeyron Equation is the difference in heat on the final and initial state of the system is calculated using Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature)). To calculate Enthalpy using integrated form of Clausius-Clapeyron Equation, you need Final Pressure of System (Pf), Initial Pressure of System (Pi), Final Temperature (Tf) & Initial Temperature (To). With our tool, you need to enter the respective value for Final Pressure of System, Initial Pressure of System, Final Temperature & Initial Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well. Let Others Know