## < ⎙ 11 Other formulas that you can solve using the same Inputs

Impulsive Force
Impulsive Force=(Mass*(Final Velocity-Initial Velocity))/Time Taken to Travel GO
Specific Heat Capacity
Specific Heat Capacity=Energy Required/(Mass*Rise in Temperature) GO
Centripetal Force or Centrifugal Force when angular velocity, mass and radius of curvature are given
Centripetal Force=Mass*(Angular velocity^2)*Radius of Curvature GO
Potential Energy
Potential Energy=Mass*Acceleration Due To Gravity*Height GO
Moment of Inertia of a rod about an axis through its center of mass and perpendicular to rod
Moment of Inertia=(Mass*(Length of rod^2))/12 GO
Centripetal Force
Moment of inertia of a circular disc about an axis through its center and perpendicular to its plane
Moment of inertia of a circular ring about an axis through its center and perpendicular to its plane
Kinetic Energy
Kinetic Energy=(Mass*Velocity^2)/2 GO
Force
Force=Mass*Acceleration GO
Density
Density=Mass/Volume GO

## < ⎙ 6 Other formulas that calculate the same Output

Gravitational potential when point p is inside of non conducting solid sphere
Gravitational potential of a ring
Gravitational Potential=-([G.]*Mass)/sqrt((Radius of ring)^2+(Distance from center to a point)^2) GO
Gravitational potential when point P is outside of non-conducting solid sphere
Gravitational Potential=-([G.]*Mass)/Distance from center to a point GO
Gravitational potential when point p is outside of conducting solid sphere
Gravitational Potential=-([G.]*Mass)/Distance from center to a point GO
Gravitational potential
Gravitational Potential=-([G.]*Mass)/Displacement of Body GO
Gravitational potential when point p is inside of conducting solid sphere

### Gravitational potential of a thin circular disc Formula

Gravitational Potential=-(2*[G.]*Mass*(sqrt((Distance from center to a point)^2+(radius)^2)-Distance from center to a point))/(radius)^2
More formulas
Gravitational potential of a ring GO
Gravitational field of a ring GO
Gravitational field of a ring when cosθ is given GO
Gravitational field of a thin circular disc GO
Gravitational potential when point p is inside of non conducting solid sphere GO
Gravitational field when point P is inside of non conducting solid sphere GO
Gravitational potential when point P is outside of non-conducting solid sphere GO
Gravitational potential when point p is inside of conducting solid sphere GO
Gravitational field when point P is outside of non conducting solid sphere GO
Gravitational field when point P is outside of conducting solid sphere GO
Gravitational potential when point p is outside of conducting solid sphere GO
Variation of acceleration due to gravity on altitude GO
Variation of acceleration due to gravity on the depth GO
Variation of acceleration due to gravity effect on the surface of earth GO

## How is gravitational potential calculated for a thin circular disc ?

The gravitational potential for a ring is calculated by the formula V = -2GM / a2{ [ a2 + r2 ]1/2

## What is the unit and dimension of gravitational potential of a thin circular disc?

The unit of gravitational potential is Jkg-1. The dimension of gravitational potential is [ M0L2T-2]

## How to Calculate Gravitational potential of a thin circular disc?

Gravitational potential of a thin circular disc calculator uses Gravitational Potential=-(2*[G.]*Mass*(sqrt((Distance from center to a point)^2+(radius)^2)-Distance from center to a point))/(radius)^2 to calculate the Gravitational Potential, Gravitational Potential of a thin circular disc at a point in the gravitational field of a body is defined as the amount of work done by an external agent in bringing a body of unit mass from infinity to that point by keeping no change in kinetic energy. Gravitational Potential and is denoted by V symbol.

How to calculate Gravitational potential of a thin circular disc using this online calculator? To use this online calculator for Gravitational potential of a thin circular disc, enter Mass (m), radius (R) and Distance from center to a point (a) and hit the calculate button. Here is how the Gravitational potential of a thin circular disc calculation can be explained with given input values -> -4.282E-9 = -(2*[G.]*35.45*(sqrt((0.1)^2+(1)^2)-0.1))/(1)^2.

### FAQ

What is Gravitational potential of a thin circular disc?
Gravitational Potential of a thin circular disc at a point in the gravitational field of a body is defined as the amount of work done by an external agent in bringing a body of unit mass from infinity to that point by keeping no change in kinetic energy and is represented as V=-(2*[G.]*m*(sqrt((a)^2+(R)^2)-a))/(R)^2 or Gravitational Potential=-(2*[G.]*Mass*(sqrt((Distance from center to a point)^2+(radius)^2)-Distance from center to a point))/(radius)^2. Mass is the quantity of matter in a body regardless of its volume or of any forces acting on it, The Radius of the sphere and Distance from center to a point is the length of line segment measured from the center of a body to a particular point.
How to calculate Gravitational potential of a thin circular disc?
Gravitational Potential of a thin circular disc at a point in the gravitational field of a body is defined as the amount of work done by an external agent in bringing a body of unit mass from infinity to that point by keeping no change in kinetic energy is calculated using Gravitational Potential=-(2*[G.]*Mass*(sqrt((Distance from center to a point)^2+(radius)^2)-Distance from center to a point))/(radius)^2. To calculate Gravitational potential of a thin circular disc, you need Mass (m), radius (R) and Distance from center to a point (a). With our tool, you need to enter the respective value for Mass, radius and Distance from center to a point and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Gravitational Potential?
In this formula, Gravitational Potential uses Mass, radius and Distance from center to a point. We can use 6 other way(s) to calculate the same, which is/are as follows -
• Gravitational Potential=-([G.]*Mass)/Displacement of Body
• Gravitational Potential=-([G.]*Mass)/sqrt((Radius of ring)^2+(Distance from center to a point)^2) 