Head over Jet Hole given Force exerted on Tank due to Jet Calculator

✖Force of Fluid is the force resulting from liquid pressure acting over an area.ⓘ Force of Fluid [F]			+10% -10%
✖The Coefficient of Velocity is the ratio of actual velocity to theoretical velocity.ⓘ Coefficient of Velocity [C_v]			+10% -10%
✖Specific Weight of Liquid represents the force exerted by gravity on a unit volume of a fluid.ⓘ Specific Weight of Liquid [γ_f]			+10% -10%
✖Cross Sectional Area of Jet is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.ⓘ Cross Sectional Area of Jet [A_Jet]			+10% -10%

✖Impulse height is the distance between the lowest and highest points of a person/ shape/ object standing upright.ⓘ Head over Jet Hole given Force exerted on Tank due to Jet [h]

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Formula

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Head over Jet Hole given Force exerted on Tank due to Jet

Formula

`"h" = (0.5*"F")/(("C"_{"v"}^2)*"γ"_{"f"}*"A"_{"Jet"})`

Example

`"12.04357m"=(0.5*"240N")/((("0.92")^2)*"9.81kN/m³"*"1.2m²")`

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Head over Jet Hole given Force exerted on Tank due to Jet Solution

STEP 0: Pre-Calculation Summary

Formula Used

Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet)
h = (0.5*F)/((C_v^2)*γ_f*A_Jet)
This formula uses 5 Variables

Variables Used

Impulse Height - (Measured in Meter) - Impulse height is the distance between the lowest and highest points of a person/ shape/ object standing upright.
Force of Fluid - (Measured in Newton) - Force of Fluid is the force resulting from liquid pressure acting over an area.
Coefficient of Velocity - The Coefficient of Velocity is the ratio of actual velocity to theoretical velocity.
Specific Weight of Liquid - (Measured in Kilonewton per Cubic Meter) - Specific Weight of Liquid represents the force exerted by gravity on a unit volume of a fluid.
Cross Sectional Area of Jet - (Measured in Square Meter) - Cross Sectional Area of Jet is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.

STEP 1: Convert Input(s) to Base Unit

Force of Fluid: 240 Newton --> 240 Newton No Conversion Required
Coefficient of Velocity: 0.92 --> No Conversion Required
Specific Weight of Liquid: 9.81 Kilonewton per Cubic Meter --> 9.81 Kilonewton per Cubic Meter No Conversion Required
Cross Sectional Area of Jet: 1.2 Square Meter --> 1.2 Square Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

h = (0.5*F)/((C_v^2)*γ_f*A_Jet) --> (0.5*240)/((0.92^2)*9.81*1.2)

Evaluating ... ...

h = 12.0435726824794

STEP 3: Convert Result to Output's Unit

12.0435726824794 Meter --> No Conversion Required

FINAL ANSWER

12.0435726824794 ≈ 12.04357 Meter <-- Impulse Height

(Calculation completed in 00.004 seconds)

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National Institute of Technology Karnataka (NITK), Surathkal

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< 7 Jet Propulsion of Orifice Tank Calculators

Actual Velocity given Force exerted on Tank due to Jet

Go Actual Velocity = sqrt((Force of Fluid*[g])/(Specific Weight of Liquid*Cross Sectional Area of Jet))

Head over Jet Hole given Force exerted on Tank due to Jet

Go Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet)

Specific Weight of Liquid given Coefficient of Velocity for Jet

Go Specific Weight of Liquid = (0.5*Force of Fluid)/(Cross Sectional Area of Jet*Impulse Height*Coefficient of Velocity^2)

Area of Hole given Coefficient of Velocity for Jet

Go Cross Sectional Area of Jet = (0.5*Force of Fluid)/(Specific Weight of Liquid*Impulse Height*Coefficient of Velocity^2)

Specific Weight of Liquid given Force exerted on Tank due to Jet

Go Specific Weight of Liquid = ((Force of Fluid*[g])/(Cross Sectional Area of Jet*(Actual Velocity)^2))

Area of Jet given Force exerted on Tank due to Jet

Go Cross Sectional Area of Jet = Force of Fluid/(Specific Weight of Liquid*(Actual Velocity^2)/[g])

Force exerted on Tank due to Jet

Go Force of Fluid = Specific Weight of Liquid*Cross Sectional Area of Jet*(Actual Velocity^2)/[g]

Head over Jet Hole given Force exerted on Tank due to Jet Formula

Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet)
h = (0.5*F)/((C_v^2)*γ_f*A_Jet)

What is Jet?

When a jet of fluid issues from an opening and strikes an obstruction placed in its path, it exerts a force on the obstruction. This force exerted by the jet is known as the action of the jet

How to Calculate Head over Jet Hole given Force exerted on Tank due to Jet?

Head over Jet Hole given Force exerted on Tank due to Jet calculator uses Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet) to calculate the Impulse Height, The Head over Jet Hole given Force exerted on Tank due to Jet is defined as the force exerted on the tank due to the jet, typically measured as the difference in fluid level between the tank and the jet hole. Impulse Height is denoted by h symbol.

How to calculate Head over Jet Hole given Force exerted on Tank due to Jet using this online calculator? To use this online calculator for Head over Jet Hole given Force exerted on Tank due to Jet, enter Force of Fluid (F), Coefficient of Velocity (C_v), Specific Weight of Liquid (γ_f) & Cross Sectional Area of Jet (A_Jet) and hit the calculate button. Here is how the Head over Jet Hole given Force exerted on Tank due to Jet calculation can be explained with given input values -> 12.04357 = (0.5*240)/((0.92^2)*9810*1.2).

FAQ

What is Head over Jet Hole given Force exerted on Tank due to Jet?

The Head over Jet Hole given Force exerted on Tank due to Jet is defined as the force exerted on the tank due to the jet, typically measured as the difference in fluid level between the tank and the jet hole and is represented as h = (0.5*F)/((C_v^2)*γ_f*A_Jet) or Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet). Force of Fluid is the force resulting from liquid pressure acting over an area, The Coefficient of Velocity is the ratio of actual velocity to theoretical velocity, Specific Weight of Liquid represents the force exerted by gravity on a unit volume of a fluid & Cross Sectional Area of Jet is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.

How to calculate Head over Jet Hole given Force exerted on Tank due to Jet?

The Head over Jet Hole given Force exerted on Tank due to Jet is defined as the force exerted on the tank due to the jet, typically measured as the difference in fluid level between the tank and the jet hole is calculated using Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet). To calculate Head over Jet Hole given Force exerted on Tank due to Jet, you need Force of Fluid (F), Coefficient of Velocity (C_v), Specific Weight of Liquid (γ_f) & Cross Sectional Area of Jet (A_Jet). With our tool, you need to enter the respective value for Force of Fluid, Coefficient of Velocity, Specific Weight of Liquid & Cross Sectional Area of Jet and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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