Heat Exchange by Radiation due to Geometric Arrangement Solution

STEP 0: Pre-Calculation Summary
Formula Used
Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
q = ε*A*[Stefan-BoltZ]*SF*(T1^(4)-T2^(4))
This formula uses 1 Constants, 6 Variables
Constants Used
[Stefan-BoltZ] - Stefan-Boltzmann Constant Value Taken As 5.670367E-8
Variables Used
Heat Transfer - (Measured in Watt) - Heat Transfer is the amount of heat that is transferred per unit of time in some material, usually measured in watts (joules per second).
Emissivity - Emissivity is the ability of an object to emit infrared energy. Emissivity can have a value from 0 (shiny mirror) to 1.0 (blackbody). Most organic or oxidized surfaces have emissivity close to 0.95.
Area - (Measured in Square Meter) - The area is the amount of two-dimensional space taken up by an object.
Shape Factor - Shape factor is a term related to the compression or deflection of a material when a load is applied to the material per its given shape.
Temperature of Surface 1 - (Measured in Kelvin) - Temperature of Surface 1 is the temperature of the 1st surface.
Temperature of Surface 2 - (Measured in Kelvin) - Temperature of Surface 2 is the temperature of the 2nd surface.
STEP 1: Convert Input(s) to Base Unit
Emissivity: 0.95 --> No Conversion Required
Area: 50 Square Meter --> 50 Square Meter No Conversion Required
Shape Factor: 4.87 --> No Conversion Required
Temperature of Surface 1: 101 Kelvin --> 101 Kelvin No Conversion Required
Temperature of Surface 2: 151 Kelvin --> 151 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
q = ε*A*[Stefan-BoltZ]*SF*(T1^(4)-T2^(4)) --> 0.95*50*[Stefan-BoltZ]*4.87*(101^(4)-151^(4))
Evaluating ... ...
q = -5454.36936101831
STEP 3: Convert Result to Output's Unit
-5454.36936101831 Watt --> No Conversion Required
FINAL ANSWER
-5454.36936101831 -5454.369361 Watt <-- Heat Transfer
(Calculation completed in 00.004 seconds)

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Osmania University (OU), Hyderabad
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13 Heat and Mass Transfer Calculators

Heat Transfer by Conduction at Base
​ Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)
Heat Exchange by Radiation due to Geometric Arrangement
​ Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
Black Bodies Heat Exchange by Radiation
​ Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
Heat Transfer According to Fourier's Law
​ Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)
One Dimensional Heat Flux
​ Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)
Newton's Law of Cooling
​ Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)
Non Ideal Body Surface Emittance
​ Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)
Convective Processes Heat Transfer Coefficient
​ Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)
Thermal Conductivity given Critical Thickness of Insulation for Cylinder
​ Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface
Diameter of Rod Circular Fin given Area of Cross-Section
​ Go Diameter of Circular Rod = sqrt((Cross-sectional area*4)/pi)
Critical Thickness of Insulation for Cylinder
​ Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient
Thermal Resistance in Convection Heat Transfer
​ Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)
Heat Transfer
​ Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

13 Conduction, Convection and Radiation Calculators

Heat Transfer by Conduction at Base
​ Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)
Heat Exchange by Radiation due to Geometric Arrangement
​ Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
Black Bodies Heat Exchange by Radiation
​ Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
Heat Transfer According to Fourier's Law
​ Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)
One Dimensional Heat Flux
​ Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)
Newton's Law of Cooling
​ Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)
Non Ideal Body Surface Emittance
​ Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)
Thermal Resistance in Conduction
​ Go Thermal Resistance = (Thickness)/(Thermal Conductivity of Fin*Cross Sectional Area)
Convective Processes Heat Transfer Coefficient
​ Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)
Thermal Conductivity given Critical Thickness of Insulation for Cylinder
​ Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface
Critical Thickness of Insulation for Cylinder
​ Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient
Thermal Resistance in Convection Heat Transfer
​ Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)
Heat Transfer
​ Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

Heat Exchange by Radiation due to Geometric Arrangement Formula

Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
q = ε*A*[Stefan-BoltZ]*SF*(T1^(4)-T2^(4))

what do you mean by heat transfer?

Heat transfer, any or all of several kinds of phenomena, considered as mechanisms, that convey energy and entropy from one location to another. The specific mechanisms are usually referred to as convection, thermal radiation, and conduction.

How to Calculate Heat Exchange by Radiation due to Geometric Arrangement?

Heat Exchange by Radiation due to Geometric Arrangement calculator uses Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4)) to calculate the Heat Transfer, Heat Exchange by Radiation due to Geometric Arrangement, only a fraction of the energy leaving body 1 is intercepted by body 2. Heat Transfer is denoted by q symbol.

How to calculate Heat Exchange by Radiation due to Geometric Arrangement using this online calculator? To use this online calculator for Heat Exchange by Radiation due to Geometric Arrangement, enter Emissivity (ε), Area (A), Shape Factor (SF), Temperature of Surface 1 (T1) & Temperature of Surface 2 (T2) and hit the calculate button. Here is how the Heat Exchange by Radiation due to Geometric Arrangement calculation can be explained with given input values -> -5454.369361 = 0.95*50*[Stefan-BoltZ]*4.87*(101^(4)-151^(4)).

FAQ

What is Heat Exchange by Radiation due to Geometric Arrangement?
Heat Exchange by Radiation due to Geometric Arrangement, only a fraction of the energy leaving body 1 is intercepted by body 2 and is represented as q = ε*A*[Stefan-BoltZ]*SF*(T1^(4)-T2^(4)) or Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4)). Emissivity is the ability of an object to emit infrared energy. Emissivity can have a value from 0 (shiny mirror) to 1.0 (blackbody). Most organic or oxidized surfaces have emissivity close to 0.95, The area is the amount of two-dimensional space taken up by an object, Shape factor is a term related to the compression or deflection of a material when a load is applied to the material per its given shape, Temperature of Surface 1 is the temperature of the 1st surface & Temperature of Surface 2 is the temperature of the 2nd surface.
How to calculate Heat Exchange by Radiation due to Geometric Arrangement?
Heat Exchange by Radiation due to Geometric Arrangement, only a fraction of the energy leaving body 1 is intercepted by body 2 is calculated using Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4)). To calculate Heat Exchange by Radiation due to Geometric Arrangement, you need Emissivity (ε), Area (A), Shape Factor (SF), Temperature of Surface 1 (T1) & Temperature of Surface 2 (T2). With our tool, you need to enter the respective value for Emissivity, Area, Shape Factor, Temperature of Surface 1 & Temperature of Surface 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Heat Transfer?
In this formula, Heat Transfer uses Emissivity, Area, Shape Factor, Temperature of Surface 1 & Temperature of Surface 2. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
  • Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))
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