Heat Transfer According to Fourier's Law Calculator

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Basics of HMT

Conduction

Convection

Convective Mass Transfer

✖Thermal Conductivity of Material is the measure of the ease at which an electric charge or heat can pass through a material.ⓘ Thermal Conductivity of Material [k]			+10% -10%
✖Surface Area of Heat Flow can be referred as the area perpendicular to heat flow.ⓘ Surface Area of Heat Flow [A]			+10% -10%
✖Temperature Difference is the measure of the hotness or the coldness of an object.ⓘ Temperature Difference [ΔT]			+10% -10%
✖The thickness of the body or sample is the distance measured on a path parallel to the heat flow.ⓘ Thickness [L]			+10% -10%

✖Heat Flow Through a Body refers to the transfer of thermal energy from regions of higher temperature to regions of lower temperature per unit time within the body.ⓘ Heat Transfer According to Fourier's Law [Q_conduction]

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Formula

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Heat Transfer According to Fourier's Law

Formula

`"Q"_{"conduction"} = -("k"*"A"*"ΔT"/"L")`

Example

`"44.17875W"=-("9.35W/(m*K)"*"4.5m²"*"-105K"/"100m")`

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Heat Transfer According to Fourier's Law Solution

STEP 0: Pre-Calculation Summary

Formula Used

Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)
Q_conduction = -(k*A*ΔT/L)
This formula uses 5 Variables

Variables Used

Heat Flow Through a Body - (Measured in Watt) - Heat Flow Through a Body refers to the transfer of thermal energy from regions of higher temperature to regions of lower temperature per unit time within the body.
Thermal Conductivity of Material - (Measured in Watt per Meter per K) - Thermal Conductivity of Material is the measure of the ease at which an electric charge or heat can pass through a material.
Surface Area of Heat Flow - (Measured in Square Meter) - Surface Area of Heat Flow can be referred as the area perpendicular to heat flow.
Temperature Difference - (Measured in Kelvin) - Temperature Difference is the measure of the hotness or the coldness of an object.
Thickness - (Measured in Meter) - The thickness of the body or sample is the distance measured on a path parallel to the heat flow.

STEP 1: Convert Input(s) to Base Unit

Thermal Conductivity of Material: 9.35 Watt per Meter per K --> 9.35 Watt per Meter per K No Conversion Required
Surface Area of Heat Flow: 4.5 Square Meter --> 4.5 Square Meter No Conversion Required
Temperature Difference: -105 Kelvin --> -105 Kelvin No Conversion Required
Thickness: 100 Meter --> 100 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

Q_conduction = -(k*A*ΔT/L) --> -(9.35*4.5*(-105)/100)

Evaluating ... ...

Q_conduction = 44.17875

STEP 3: Convert Result to Output's Unit

44.17875 Watt --> No Conversion Required

FINAL ANSWER

44.17875 Watt <-- Heat Flow Through a Body

(Calculation completed in 00.004 seconds)

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< 13 Heat and Mass Transfer Calculators

Heat Transfer by Conduction at Base

Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)

Heat Exchange by Radiation due to Geometric Arrangement

Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Black Bodies Heat Exchange by Radiation

Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Heat Transfer According to Fourier's Law

Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)

One Dimensional Heat Flux

Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)

Newton's Law of Cooling

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)

Non Ideal Body Surface Emittance

Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)

Convective Processes Heat Transfer Coefficient

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)

Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface

Diameter of Rod Circular Fin given Area of Cross-Section

Go Diameter of Circular Rod = sqrt((Cross-sectional area*4)/pi)

Critical Thickness of Insulation for Cylinder

Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient

Thermal Resistance in Convection Heat Transfer

Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)

Heat Transfer

Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

< 13 Conduction, Convection and Radiation Calculators

Heat Transfer by Conduction at Base

Go Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature)

Heat Exchange by Radiation due to Geometric Arrangement

Go Heat Transfer = Emissivity*Area*[Stefan-BoltZ]*Shape Factor*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Black Bodies Heat Exchange by Radiation

Go Heat Transfer = Emissivity*[Stefan-BoltZ]*Area*(Temperature of Surface 1^(4)-Temperature of Surface 2^(4))

Heat Transfer According to Fourier's Law

Go Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)

One Dimensional Heat Flux

Go Heat Flux = -Thermal Conductivity of Fin/Wall Thickness*(Temperature of Wall 2-Temperature of Wall 1)

Newton's Law of Cooling

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)

Non Ideal Body Surface Emittance

Go Real Surface Radiant Surface Emittance = Emissivity*[Stefan-BoltZ]*Surface Temperature^(4)

Thermal Resistance in Conduction

Go Thermal Resistance = (Thickness)/(Thermal Conductivity of Fin*Cross Sectional Area)

Convective Processes Heat Transfer Coefficient

Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Recovery temperature)

Thermal Conductivity given Critical Thickness of Insulation for Cylinder

Go Thermal Conductivity of Fin = Critical Thickness of Insulation*Heat Transfer Coefficient at Outer Surface

Critical Thickness of Insulation for Cylinder

Go Critical Thickness of Insulation = Thermal Conductivity of Fin/Heat Transfer Coefficient

Thermal Resistance in Convection Heat Transfer

Go Thermal Resistance = 1/(Exposed Surface Area*Co-efficient of Convective Heat Transfer)

Heat Transfer

Go Heat Flow Rate = Thermal Potential Difference/Thermal Resistance

Heat Transfer According to Fourier's Law Formula

Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness)
Q_conduction = -(k*A*ΔT/L)

State Fourier's law.

Fourier’s law states that the negative gradient of temperature and the time rate of heat transfer is proportional to the area at right angles of that gradient through which the heat flows. Fourier’s law is the other name of the law of heat conduction.

How to Calculate Heat Transfer According to Fourier's Law?

Heat Transfer According to Fourier's Law calculator uses Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness) to calculate the Heat Flow Through a Body, Heat Transfer according to Fourier's Law states that the negative gradient of temperature and the time rate of heat transfer is proportional to the area at right angles of that gradient through which the heat flows. Heat Flow Through a Body is denoted by Q_conduction symbol.

How to calculate Heat Transfer According to Fourier's Law using this online calculator? To use this online calculator for Heat Transfer According to Fourier's Law, enter Thermal Conductivity of Material (k), Surface Area of Heat Flow (A), Temperature Difference (ΔT) & Thickness (L) and hit the calculate button. Here is how the Heat Transfer According to Fourier's Law calculation can be explained with given input values -> 323.9775 = -(9.35*4.5*(-105)/100).

FAQ

What is Heat Transfer According to Fourier's Law?

Heat Transfer according to Fourier's Law states that the negative gradient of temperature and the time rate of heat transfer is proportional to the area at right angles of that gradient through which the heat flows and is represented as Q_conduction = -(k*A*ΔT/L) or Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness). Thermal Conductivity of Material is the measure of the ease at which an electric charge or heat can pass through a material, Surface Area of Heat Flow can be referred as the area perpendicular to heat flow, Temperature Difference is the measure of the hotness or the coldness of an object & The thickness of the body or sample is the distance measured on a path parallel to the heat flow.

How to calculate Heat Transfer According to Fourier's Law?

Heat Transfer according to Fourier's Law states that the negative gradient of temperature and the time rate of heat transfer is proportional to the area at right angles of that gradient through which the heat flows is calculated using Heat Flow Through a Body = -(Thermal Conductivity of Material*Surface Area of Heat Flow*Temperature Difference/Thickness). To calculate Heat Transfer According to Fourier's Law, you need Thermal Conductivity of Material (k), Surface Area of Heat Flow (A), Temperature Difference (ΔT) & Thickness (L). With our tool, you need to enter the respective value for Thermal Conductivity of Material, Surface Area of Heat Flow, Temperature Difference & Thickness and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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