Intricately Shaped Thin-walled Castings of Mass up to 450 kg Solution

STEP 0: Pre-Calculation Summary
Formula Used
Pouring time = Empirical constant 3*(Total mass of metal poured in mould)^(1/3)
t = K3*(Wm)^(1/3)
This formula uses 3 Variables
Variables Used
Pouring time - (Measured in Second) - Pouring time is the time for complete filling of a mould.
Empirical constant 3 - Empirical constant 3 is a constant whose value is to be determined by experiments or using certain tables.
Total mass of metal poured in mould - (Measured in Kilogram) - Total mass of metal poured in mould is the mass of metal poured inside the mould.
STEP 1: Convert Input(s) to Base Unit
Empirical constant 3: 1.62 --> No Conversion Required
Total mass of metal poured in mould: 17 Kilogram --> 17 Kilogram No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
t = K3*(Wm)^(1/3) --> 1.62*(17)^(1/3)
Evaluating ... ...
t = 4.16547617686634
STEP 3: Convert Result to Output's Unit
4.16547617686634 Second --> No Conversion Required
FINAL ANSWER
4.16547617686634 4.165476 Second <-- Pouring time
(Calculation completed in 00.004 seconds)

Credits

Created by Rajat Vishwakarma
University Institute of Technology RGPV (UIT - RGPV), Bhopal
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7 Pouring Time Relations Calculators

Grey Cast Iron, Mass less than 450 kg
Go Pouring time = (Fluidity of iron/40)*(1.41+(Average thickness of section/14.59))*sqrt(Mass of casting)
Castings above 450 kg and up to 1000 kg
Go Pouring time = Empirical constant 4*(Total mass of metal poured in mould*Average thickness of section)^(1/3)
Steel Castings
Go Pouring time = (2.4335-0.3953*log10(Mass of casting))*sqrt(Mass of casting)
Grey Cast Iron, Mass greater than 450 kg
Go Pouring time = (Fluidity of iron/40)*(1.236+(Average section thickness/16.65))*(Mass of casting)^(1/3)
Shell-moulded Ductile Iron (vertical pouring)
Go Pouring time = Empirical constant 1*sqrt(Mass of casting)
Intricately Shaped Thin-walled Castings of Mass up to 450 kg
Go Pouring time = Empirical constant 3*(Total mass of metal poured in mould)^(1/3)
Copper Alloy Castings
Go Pouring time = Empirical constant 2*(Mass of casting)^(1/3)

Intricately Shaped Thin-walled Castings of Mass up to 450 kg Formula

Pouring time = Empirical constant 3*(Total mass of metal poured in mould)^(1/3)
t = K3*(Wm)^(1/3)

What is pouring time?

The time for complete filling of a mould is termed pouring time, is a very important criterion for design.Too long a pouring time requires a higher pouring temperature and too less a pouring time means turbulent flow in the mould, which makes the casting defect-prone. There is thus an optimum pouring time for any given casting. The pouring time depends on the casting materials, complexity of the casting, section thickness and casting size. The various relations used are not theoretically obtained but established generally by the practice at various foundries and by experimenters.

What are usual values of k?

T (mm) -->K3
(1.5 to 2.5) --> 1.62,
(2.5 to 3.5) --> 1.68,
(3.5 to 8.0) --> 1.85,
(8.0 to 15.0) --> 2.20

How to Calculate Intricately Shaped Thin-walled Castings of Mass up to 450 kg?

Intricately Shaped Thin-walled Castings of Mass up to 450 kg calculator uses Pouring time = Empirical constant 3*(Total mass of metal poured in mould)^(1/3) to calculate the Pouring time, The Intricately Shaped Thin-walled Castings of Mass up to 450 kg formula describes the pouring time that is needed to fill a thin walled casting. Pouring time is denoted by t symbol.

How to calculate Intricately Shaped Thin-walled Castings of Mass up to 450 kg using this online calculator? To use this online calculator for Intricately Shaped Thin-walled Castings of Mass up to 450 kg, enter Empirical constant 3 (K3) & Total mass of metal poured in mould (Wm) and hit the calculate button. Here is how the Intricately Shaped Thin-walled Castings of Mass up to 450 kg calculation can be explained with given input values -> 4.165476 = 1.62*(17)^(1/3).

FAQ

What is Intricately Shaped Thin-walled Castings of Mass up to 450 kg?
The Intricately Shaped Thin-walled Castings of Mass up to 450 kg formula describes the pouring time that is needed to fill a thin walled casting and is represented as t = K3*(Wm)^(1/3) or Pouring time = Empirical constant 3*(Total mass of metal poured in mould)^(1/3). Empirical constant 3 is a constant whose value is to be determined by experiments or using certain tables & Total mass of metal poured in mould is the mass of metal poured inside the mould.
How to calculate Intricately Shaped Thin-walled Castings of Mass up to 450 kg?
The Intricately Shaped Thin-walled Castings of Mass up to 450 kg formula describes the pouring time that is needed to fill a thin walled casting is calculated using Pouring time = Empirical constant 3*(Total mass of metal poured in mould)^(1/3). To calculate Intricately Shaped Thin-walled Castings of Mass up to 450 kg, you need Empirical constant 3 (K3) & Total mass of metal poured in mould (Wm). With our tool, you need to enter the respective value for Empirical constant 3 & Total mass of metal poured in mould and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Pouring time?
In this formula, Pouring time uses Empirical constant 3 & Total mass of metal poured in mould. We can use 6 other way(s) to calculate the same, which is/are as follows -
  • Pouring time = (Fluidity of iron/40)*(1.41+(Average thickness of section/14.59))*sqrt(Mass of casting)
  • Pouring time = (Fluidity of iron/40)*(1.236+(Average section thickness/16.65))*(Mass of casting)^(1/3)
  • Pouring time = (2.4335-0.3953*log10(Mass of casting))*sqrt(Mass of casting)
  • Pouring time = Empirical constant 1*sqrt(Mass of casting)
  • Pouring time = Empirical constant 2*(Mass of casting)^(1/3)
  • Pouring time = Empirical constant 4*(Total mass of metal poured in mould*Average thickness of section)^(1/3)
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