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## Length Of Wire Using Area Of X-section(1-phase 2-wire OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
length = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Resistivity*(Power Transmitted^2))
l = a4*(Vm^2)*W*((cos(ϑ))^2)/(4*ρ*(P^2))
This formula uses 1 Functions, 6 Variables
Functions Used
cos - Trigonometric cosine function, cos(Angle)
Variables Used
Area Of 1-Φ 2-wire system - The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Maximum Voltage - Maximum Voltage the highest voltage rating for electrical devices (Measured in Volt)
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Theta - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint. (Measured in Degree)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
Power Transmitted - The Power Transmitted Value through a shaft. (Measured in Kilowatt)
STEP 1: Convert Input(s) to Base Unit
Area Of 1-Φ 2-wire system: 6 Square Meter --> 6 Square Meter No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 10 Kilowatt --> 10000 Watt (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
l = a4*(Vm^2)*W*((cos(ϑ))^2)/(4*ρ*(P^2)) --> 6*(60^2)*0.6*((cos(0.5235987755982))^2)/(4*1.7E-05*(10000^2))
Evaluating ... ...
l = 1.42941176470588
STEP 3: Convert Result to Output's Unit
1.42941176470588 Meter --> No Conversion Required
FINAL ANSWER
1.42941176470588 Meter <-- Length
(Calculation completed in 00.031 seconds)

## < 8 Area Of X-Section Calculators

Maximum Voltage Using Area Of X-section(1-phase 2-wire OS)
maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*((cos(Theta))^2))) Go
RMS Voltage Using Area Of X-Section(1-Phase 2-Wire OS)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*((cos(Theta))^2))) Go
Power Transmitted Using Area Of X-section(1-phase 2-wire OS)
power_transmitted = sqrt((Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length)) Go
Power Factor Using Area Of X-section(1-phase 2-wire OS)
power_factor = sqrt((4*Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2))) Go
Line Losses Using Area Of X-section(1-phase 2-wire OS)
line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Of Wire Using Area Of X-section(1-phase 2-wire OS)
length = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Resistivity*(Power Transmitted^2)) Go
Resistivity Using Area Of X-section(1-phase 2-wire OS)
resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Length*(Power Transmitted^2)) Go
Load Current Using Area Of X-Section(1-Phase 2-Wire OS)
current4 = sqrt(Area Of 1-Φ 2-wire system*Line Losses/(Resistivity*Length)) Go

### Length Of Wire Using Area Of X-section(1-phase 2-wire OS) Formula

length = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Resistivity*(Power Transmitted^2))
l = a4*(Vm^2)*W*((cos(ϑ))^2)/(4*ρ*(P^2))

## What is the value of maximum voltage and volume of conductor material in 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

## How to Calculate Length Of Wire Using Area Of X-section(1-phase 2-wire OS)?

Length Of Wire Using Area Of X-section(1-phase 2-wire OS) calculator uses length = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Resistivity*(Power Transmitted^2)) to calculate the Length, The Length Of Wire Using Area Of X-Section(1-phase 2-wire OS) formula is defined as the total length of the wire that used in the single-phase two-wire system. Length and is denoted by l symbol.

How to calculate Length Of Wire Using Area Of X-section(1-phase 2-wire OS) using this online calculator? To use this online calculator for Length Of Wire Using Area Of X-section(1-phase 2-wire OS), enter Area Of 1-Φ 2-wire system (a4), Maximum Voltage (Vm), Line Losses (W), Theta (ϑ), Resistivity (ρ) and Power Transmitted (P) and hit the calculate button. Here is how the Length Of Wire Using Area Of X-section(1-phase 2-wire OS) calculation can be explained with given input values -> 1.429412 = 6*(60^2)*0.6*((cos(0.5235987755982))^2)/(4*1.7E-05*(10000^2)).

### FAQ

What is Length Of Wire Using Area Of X-section(1-phase 2-wire OS)?
The Length Of Wire Using Area Of X-Section(1-phase 2-wire OS) formula is defined as the total length of the wire that used in the single-phase two-wire system and is represented as l = a4*(Vm^2)*W*((cos(ϑ))^2)/(4*ρ*(P^2)) or length = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Resistivity*(Power Transmitted^2)). The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object, Maximum Voltage the highest voltage rating for electrical devices, Line Losses is defined as the losses that are produced in the line, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint, Resistivity is the measure of how strongly a material opposes the flow of current through them and The Power Transmitted Value through a shaft.
How to calculate Length Of Wire Using Area Of X-section(1-phase 2-wire OS)?
The Length Of Wire Using Area Of X-Section(1-phase 2-wire OS) formula is defined as the total length of the wire that used in the single-phase two-wire system is calculated using length = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Resistivity*(Power Transmitted^2)). To calculate Length Of Wire Using Area Of X-section(1-phase 2-wire OS), you need Area Of 1-Φ 2-wire system (a4), Maximum Voltage (Vm), Line Losses (W), Theta (ϑ), Resistivity (ρ) and Power Transmitted (P). With our tool, you need to enter the respective value for Area Of 1-Φ 2-wire system, Maximum Voltage, Line Losses, Theta, Resistivity and Power Transmitted and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Length?
In this formula, Length uses Area Of 1-Φ 2-wire system, Maximum Voltage, Line Losses, Theta, Resistivity and Power Transmitted. We can use 8 other way(s) to calculate the same, which is/are as follows -
• length = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Resistivity*(Power Transmitted^2))
• resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(4*Length*(Power Transmitted^2))
• power_transmitted = sqrt((Area Of X-Section*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length))
• line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*((cos(Theta))^2))
• maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*((cos(Theta))^2)))
• power_factor = sqrt((4*Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2)))
• rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*((cos(Theta))^2)))
• current4 = sqrt(Area Of 1-Φ 2-wire system*Line Losses/(Resistivity*Length))
Where is the Length Of Wire Using Area Of X-section(1-phase 2-wire OS) calculator used?
Among many, Length Of Wire Using Area Of X-section(1-phase 2-wire OS) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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