Length using Resistance of Natural Wire (2-Phase 3-Wire US) Calculator

✖Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.ⓘ Resistance Underground AC [R]			+10% -10%
✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%

✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length using Resistance of Natural Wire (2-Phase 3-Wire US) [L]

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Formula

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Length using Resistance of Natural Wire (2-Phase 3-Wire US)

Formula

`"L" = ("R"*sqrt(2)*"A")/("ρ")`

Example

`"532409.8m"=("5Ω"*sqrt(2)*"1.28m²")/("0.000017Ω*m")`

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Length using Resistance of Natural Wire (2-Phase 3-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity)
L = (R*sqrt(2)*A)/(ρ)
This formula uses 1 Functions, 4 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Resistance Underground AC - (Measured in Ohm) - Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.

STEP 1: Convert Input(s) to Base Unit

Resistance Underground AC: 5 Ohm --> 5 Ohm No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

L = (R*sqrt(2)*A)/(ρ) --> (5*sqrt(2)*1.28)/(1.7E-05)

Evaluating ... ...

L = 532409.81171693

STEP 3: Convert Result to Output's Unit

532409.81171693 Meter --> No Conversion Required

FINAL ANSWER

532409.81171693 ≈ 532409.8 Meter <-- Length of Underground AC Wire

(Calculation completed in 00.004 seconds)

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< 17 Wire Parameters Calculators

Volume of Conductor Material using Resistance (2 Phase 3 Wire US)

Go Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)

Angle of Pf using Line Losses (2-Phase 3-Wire US)

Go Phase Difference = acos((2+(sqrt(2)*Power Transmitted/Maximum Voltage Underground AC))*(sqrt(Resistivity*Length of Underground AC Wire/Line Losses*Area of Underground AC Wire)))

Length using Volume of Conductor Material (2 Phase 3 Wire US)

Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))

Volume of Conductor Material (2 Phase 3 Wire US)

Go Volume Of Conductor = ((2+sqrt(2))^2)*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Area of X-Section using Line Losses (2-Phase 3-Wire US)

Go Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Length using Line Losses (2-Phase 3-Wire US)

Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted^2)*Resistivity)

Line Losses using Volume of Conductor Material (2 Phase 3 Wire US)

Go Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)

Volume of Conductor Material using Area and Length(2 Phase 3 Wire US)

Go Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire)

Volume of Conductor Material using Load Current (2 Phase 3 Wire US)

Go Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses

Angle using Current in Neutral Wire (2-Phase 3-Wire US)

Go Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))

Length using Resistance of Natural Wire (2-Phase 3-Wire US)

Go Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity)

Area using Resistance of Natural Wire (2-Phase 3-Wire US)

Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/(sqrt(2)*Resistance Underground AC)

Angle using Current in Each Outer (2-Phase 3-Wire US)

Go Phase Difference = acos(Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))

Angle of PF using Volume of Conductor Material (2 Phase 3 Wire US)

Go Phase Difference = acos(sqrt((2.914)*Constant Underground AC/Volume Of Conductor))

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)

Go Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)

Constant using Volume of Conductor Material (2 Phase 3 Wire US)

Go Constant Underground AC = Volume Of Conductor*((cos(Phase Difference))^2)/(2.914)

Volume of Conductor Material using Constant(2 Phase 3 Wire US)

Go Volume Of Conductor = 2.194*Constant Underground AC/(cos(Phase Difference)^2)

Length using Resistance of Natural Wire (2-Phase 3-Wire US) Formula

Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity)
L = (R*sqrt(2)*A)/(ρ)

What is the value of maximum voltage and volume of conductor material in 2-phase 3-wire system?

The volume of conductor material required in this system is 2.914/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m/√2 so that r.m.s. value of voltage between them is v_m/2.

How to Calculate Length using Resistance of Natural Wire (2-Phase 3-Wire US)?

Length using Resistance of Natural Wire (2-Phase 3-Wire US) calculator uses Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity) to calculate the Length of Underground AC Wire, The Length using Resistance of Natural Wire (2-Phase 3-Wire US) formula is defined as the total length of the wire that used in the two-phase three-wire Underground system. Length of Underground AC Wire is denoted by L symbol.

How to calculate Length using Resistance of Natural Wire (2-Phase 3-Wire US) using this online calculator? To use this online calculator for Length using Resistance of Natural Wire (2-Phase 3-Wire US), enter Resistance Underground AC (R), Area of Underground AC Wire (A) & Resistivity (ρ) and hit the calculate button. Here is how the Length using Resistance of Natural Wire (2-Phase 3-Wire US) calculation can be explained with given input values -> 532409.8 = (5*sqrt(2)*1.28)/(1.7E-05).

FAQ

What is Length using Resistance of Natural Wire (2-Phase 3-Wire US)?

The Length using Resistance of Natural Wire (2-Phase 3-Wire US) formula is defined as the total length of the wire that used in the two-phase three-wire Underground system and is represented as L = (R*sqrt(2)*A)/(ρ) or Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity). Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system & Resistivity is the measure of how strongly a material opposes the flow of current through them.

How to calculate Length using Resistance of Natural Wire (2-Phase 3-Wire US)?

The Length using Resistance of Natural Wire (2-Phase 3-Wire US) formula is defined as the total length of the wire that used in the two-phase three-wire Underground system is calculated using Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity). To calculate Length using Resistance of Natural Wire (2-Phase 3-Wire US), you need Resistance Underground AC (R), Area of Underground AC Wire (A) & Resistivity (ρ). With our tool, you need to enter the respective value for Resistance Underground AC, Area of Underground AC Wire & Resistivity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Length of Underground AC Wire?

In this formula, Length of Underground AC Wire uses Resistance Underground AC, Area of Underground AC Wire & Resistivity. We can use 2 other way(s) to calculate the same, which is/are as follows -

Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))
Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted^2)*Resistivity)

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