Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) Calculator

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume Of Conductor [V]			+10% -10%
✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%

✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) [L]

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Formula

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Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)

Formula

`"L" = "V"/(2*"A")`

Example

`"23.4375m"="60m³"/(2*"1.28m²")`

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Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
L = V/(2*A)
This formula uses 3 Variables

Variables Used

Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

STEP 1: Convert Input(s) to Base Unit

Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

L = V/(2*A) --> 60/(2*1.28)

Evaluating ... ...

L = 23.4375

STEP 3: Convert Result to Output's Unit

23.4375 Meter --> No Conversion Required

FINAL ANSWER

23.4375 Meter <-- Length of Underground AC Wire

(Calculation completed in 00.004 seconds)

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< 14 Wire Parameters Calculators

Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)

Angle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Phase Difference = acos(sqrt(4*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))))

Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))

Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = 8*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)

Go Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))

Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))

Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses

Volume of Conductor Material using Constant(1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)

Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)

Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)

Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)

Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)

Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US)

Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) Formula

Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
L = V/(2*A)

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)?

Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) calculator uses Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire) to calculate the Length of Underground AC Wire, The Length using Volume of Conductor Material (1-phase 2-wire Mid-point Earthed) formula is defined as the total length of the wire that used in the two-phase three-wire mid-point earthed Underground system. Length of Underground AC Wire is denoted by L symbol.

How to calculate Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed), enter Volume Of Conductor (V) & Area of Underground AC Wire (A) and hit the calculate button. Here is how the Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 23.4375 = 60/(2*1.28).

FAQ

What is Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)?

The Length using Volume of Conductor Material (1-phase 2-wire Mid-point Earthed) formula is defined as the total length of the wire that used in the two-phase three-wire mid-point earthed Underground system and is represented as L = V/(2*A) or Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire). Volume Of Conductor the 3-dimensional space enclosed by a conductor material & Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

How to calculate Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)?

The Length using Volume of Conductor Material (1-phase 2-wire Mid-point Earthed) formula is defined as the total length of the wire that used in the two-phase three-wire mid-point earthed Underground system is calculated using Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire). To calculate Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed), you need Volume Of Conductor (V) & Area of Underground AC Wire (A). With our tool, you need to enter the respective value for Volume Of Conductor & Area of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Length of Underground AC Wire?

In this formula, Length of Underground AC Wire uses Volume Of Conductor & Area of Underground AC Wire. We can use 2 other way(s) to calculate the same, which is/are as follows -

Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))
Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)

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