Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.ⓘ Phase Difference [Φ]			+10% -10%

✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) [P_loss]

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Formula

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Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Formula

`"P"_{"loss"} = 4*"ρ"*"L"*("P"^2)/("A"*("V"_{"m"}^2)*(cos("Φ")^2))`

Example

`"0.002892W"=4*"0.000017Ω*m"*"24m"*(("300W")^2)/("1.28m²"*(("230V")^2)*(cos("30°")^2))`

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Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
P_loss = 4*ρ*L*(P^2)/(A*(V_m^2)*(cos(Φ)^2))
This formula uses 1 Functions, 7 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)

Variables Used

Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_loss = 4*ρ*L*(P^2)/(A*(V_m^2)*(cos(Φ)^2)) --> 4*1.7E-05*24*(300^2)/(1.28*(230^2)*(cos(0.5235987755982)^2))

Evaluating ... ...

P_loss = 0.00289224952741021

STEP 3: Convert Result to Output's Unit

0.00289224952741021 Watt --> No Conversion Required

FINAL ANSWER

0.00289224952741021 ≈ 0.002892 Watt <-- Line Losses

(Calculation completed in 00.004 seconds)

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Home » Engineering » Electrical » Power System » Underground AC Supply » 1-Φ 2-Wire Mid-Point Earthed System » Wire Parameters » Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

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Vishwakarma Government Engineering College (VGEC), Ahmedabad

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< 14 Wire Parameters Calculators

Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)

Angle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Phase Difference = acos(sqrt(4*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))))

Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))

Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = 8*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)

Go Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))

Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))

Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses

Volume of Conductor Material using Constant(1-Phase 2-Wire Mid-Point Earthed)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)

Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)

Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)

Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)

Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)

Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US)

Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

What is the average line loss?

System average line losses are in the range of six to ten percent on most. Power Plant Step Up Transformer Step DownDistribution Lines Transmission Lines Residence. 1 “Distribution” is, regrettably, an ambiguous term when discussing electric power.

How to Calculate Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) calculator uses Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)) to calculate the Line Losses, The Line Losses using Area of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by P_loss symbol.

How to calculate Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), enter Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button. Here is how the Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 0.002892 = 4*1.7E-05*24*(300^2)/(1.28*(230^2)*(cos(0.5235987755982)^2)).

FAQ

What is Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

The Line Losses using Area of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the loss of electric energy due to the heating of line wires by the current and is represented as P_loss = 4*ρ*L*(P^2)/(A*(V_m^2)*(cos(Φ)^2)) or Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

How to calculate Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

The Line Losses using Area of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the loss of electric energy due to the heating of line wires by the current is calculated using Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). To calculate Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), you need Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Power Transmitted, Area of Underground AC Wire, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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