🔍
🔍

## Credits

Vishwakarma Government Engineering College (VGEC), Ahmedabad
Urvi Rathod has created this Calculator and 1000+ more calculators!
Bipin Tripathi Kumaon Institute of Technology (BTKIT), Dwarahat
Shobhit Dimri has verified this Calculator and 100+ more calculators!

## Line Losses Using Area Of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2))
W = (4*l*ρ*(P^2))/(a*(Vm^2)*((cos(ϑ))^2))
This formula uses 1 Functions, 6 Variables
Functions Used
cos - Trigonometric cosine function, cos(Angle)
Variables Used
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
Power Transmitted - The Power Transmitted Value through a shaft. (Measured in Kilowatt)
Area Of X-Section - Area Of X-Section is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” (Measured in Square Meter)
Maximum Voltage - Maximum Voltage the highest voltage rating for electrical devices (Measured in Volt)
Theta - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint. (Measured in Degree)
STEP 1: Convert Input(s) to Base Unit
Length: 3 Meter --> 3 Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 10 Kilowatt --> 10000 Watt (Check conversion here)
Area Of X-Section: 5 Square Meter --> 5 Square Meter No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
W = (4*l*ρ*(P^2))/(a*(Vm^2)*((cos(ϑ))^2)) --> (4*3*1.7E-05*(10000^2))/(5*(60^2)*((cos(0.5235987755982))^2))
Evaluating ... ...
W = 1.51111111111111
STEP 3: Convert Result to Output's Unit
1.51111111111111 Watt --> No Conversion Required
1.51111111111111 Watt <-- Line Losses
(Calculation completed in 00.032 seconds)

## < 9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-Section (1-Phase 2-Wire US)
power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length)) Go
Maximum Voltage Using Area Of X-Section (1-Phase 2-Wire US)
maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2)) Go
RMS Voltage Using Area Of X-Section (1-Phase 2-Wire US)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-Section (1-Phase 2-Wire US)
power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2))) Go
Resistivity Using Area Of X-Section (1-Phase 2-Wire US)
resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2)) Go
Line Losses Using Area Of X-Section (1-Phase 2-Wire US)
line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Using Area Of X-Section (1-Phase 2-Wire US)
length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity) Go
Constant Using Area Of X-Section (1-Phase 2-Wire US)
constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2 Go
Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US)
volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2 Go

### Line Losses Using Area Of X-Section (1-Phase 2-Wire US) Formula

line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2))
W = (4*l*ρ*(P^2))/(a*(Vm^2)*((cos(ϑ))^2))

## What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

## How to Calculate Line Losses Using Area Of X-Section (1-Phase 2-Wire US)?

Line Losses Using Area Of X-Section (1-Phase 2-Wire US) calculator uses line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)) to calculate the Line Losses, The Line Losses Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses and is denoted by W symbol.

How to calculate Line Losses Using Area Of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Line Losses Using Area Of X-Section (1-Phase 2-Wire US), enter Length (l), Resistivity (ρ), Power Transmitted (P), Area Of X-Section (a), Maximum Voltage (Vm) and Theta (ϑ) and hit the calculate button. Here is how the Line Losses Using Area Of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 1.511111 = (4*3*1.7E-05*(10000^2))/(5*(60^2)*((cos(0.5235987755982))^2)).

### FAQ

What is Line Losses Using Area Of X-Section (1-Phase 2-Wire US)?
The Line Losses Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current and is represented as W = (4*l*ρ*(P^2))/(a*(Vm^2)*((cos(ϑ))^2)) or line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)). Length is the measurement or extent of something from end to end, Resistivity is the measure of how strongly a material opposes the flow of current through them, The Power Transmitted Value through a shaft, Area Of X-Section is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.”, Maximum Voltage the highest voltage rating for electrical devices and Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
How to calculate Line Losses Using Area Of X-Section (1-Phase 2-Wire US)?
The Line Losses Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current is calculated using line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)). To calculate Line Losses Using Area Of X-Section (1-Phase 2-Wire US), you need Length (l), Resistivity (ρ), Power Transmitted (P), Area Of X-Section (a), Maximum Voltage (Vm) and Theta (ϑ). With our tool, you need to enter the respective value for Length, Resistivity, Power Transmitted, Area Of X-Section, Maximum Voltage and Theta and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Line Losses?
In this formula, Line Losses uses Length, Resistivity, Power Transmitted, Area Of X-Section, Maximum Voltage and Theta. We can use 9 other way(s) to calculate the same, which is/are as follows -
• power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length))
• resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2))
• length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity)
• line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2))
• maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2))
• rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
• power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2)))
• constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2
• volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2
Where is the Line Losses Using Area Of X-Section (1-Phase 2-Wire US) calculator used?
Among many, Line Losses Using Area Of X-Section (1-Phase 2-Wire US) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
{FormulaExamplesList}
Let Others Know