Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) Calculator

✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.ⓘ Phase Difference [Φ]			+10% -10%
✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume Of Conductor [V]			+10% -10%

✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) [P_loss]

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Formula

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Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)

Formula

`"P"_{"loss"} = 8*("P")^2*"ρ"*("L")^2/(("V"_{"m"}*cos("Φ"))^2*"V")`

Example

`"0.002962W"=8*("300W")^2*"0.000017Ω*m"*("24m")^2/(("230V"*cos("30°"))^2*"60m³")`

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Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Line Losses = 8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)
P_loss = 8*(P)^2*ρ*(L)^2/((V_m*cos(Φ))^2*V)
This formula uses 1 Functions, 7 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)

Variables Used

Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

STEP 1: Convert Input(s) to Base Unit

Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_loss = 8*(P)^2*ρ*(L)^2/((V_m*cos(Φ))^2*V) --> 8*(300)^2*1.7E-05*(24)^2/((230*cos(0.5235987755982))^2*60)

Evaluating ... ...

P_loss = 0.00296166351606805

STEP 3: Convert Result to Output's Unit

0.00296166351606805 Watt --> No Conversion Required

FINAL ANSWER

0.00296166351606805 ≈ 0.002962 Watt <-- Line Losses

(Calculation completed in 00.004 seconds)

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Home » Engineering » Electrical » Power System » Underground AC Supply » 1-Φ 2-Wire System » Line Parameters » Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)

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< 7 Line Parameters Calculators

Line Losses using Area of X-Section (1-Phase 2-Wire US)

Go Line Losses = (4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2))

Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)

Go Line Losses = 8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)

Line Losses using Constant (1-Phase 2-Wire US)

Go Line Losses = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*(Maximum Voltage Underground AC)^2)

Line Losses using Load Current (1-Phase 2-Wire US)

Go Line Losses = 2*Resistance Underground AC*(Current Underground AC)^2

Line Losses using Resistance (1-Phase 2-Wire US)

Go Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC

Line Losses (1-phase 2-wire Mid-point Earthed)

Go Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC

Line Losses (1-Phase 2-Wire US)

Go Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC

Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) Formula

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)?

Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) calculator uses Line Losses = 8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor) to calculate the Line Losses, The Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by P_loss symbol.

How to calculate Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Line Losses using Volume of Conductor Material (1-Phase 2-Wire US), enter Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Maximum Voltage Underground AC (V_m), Phase Difference (Φ) & Volume Of Conductor (V) and hit the calculate button. Here is how the Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) calculation can be explained with given input values -> 0.002962 = 8*(300)^2*1.7E-05*(24)^2/((230*cos(0.5235987755982))^2*60).

FAQ

What is Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)?

The Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current and is represented as P_loss = 8*(P)^2*ρ*(L)^2/((V_m*cos(Φ))^2*V) or Line Losses = 8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit & Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

How to calculate Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)?

The Line Losses using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current is calculated using Line Losses = 8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor). To calculate Line Losses using Volume of Conductor Material (1-Phase 2-Wire US), you need Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Maximum Voltage Underground AC (V_m), Phase Difference (Φ) & Volume Of Conductor (V). With our tool, you need to enter the respective value for Power Transmitted, Resistivity, Length of Underground AC Wire, Maximum Voltage Underground AC, Phase Difference & Volume Of Conductor and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Line Losses?

In this formula, Line Losses uses Power Transmitted, Resistivity, Length of Underground AC Wire, Maximum Voltage Underground AC, Phase Difference & Volume Of Conductor. We can use 6 other way(s) to calculate the same, which is/are as follows -

Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC
Line Losses = (4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2))
Line Losses = 2*Resistance Underground AC*(Current Underground AC)^2
Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC
Line Losses = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*(Maximum Voltage Underground AC)^2)
Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC

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