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## Load Current Using Volume Of Conductor Material (2-phase 4-wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
current7 = sqrt(Volume Of Conductor Material*Line Losses/(4*Resistivity*(Length^2)))
C7 = sqrt(V*W/(4*ρ*(l^2)))
This formula uses 1 Functions, 4 Variables
Functions Used
sqrt - Squre root function, sqrt(Number)
Variables Used
Volume Of Conductor Material - Volume Of Conductor Material the 3-dimensional space enclosed by a conductor material (Measured in Cubic Meter)
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Volume Of Conductor Material: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
C7 = sqrt(V*W/(4*ρ*(l^2))) --> sqrt(60*0.6/(4*1.7E-05*(3^2)))
Evaluating ... ...
C7 = 242.535625036333
STEP 3: Convert Result to Output's Unit
242.535625036333 Ampere --> No Conversion Required
242.535625036333 Ampere <-- Current Of 2-Φ 4-wire system
(Calculation completed in 00.031 seconds)

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## < 1 Other formulas that calculate the same Output

current7 = sqrt(2)*Power Transmitted/(Maximum Voltage*cos(Theta)) Go

### Load Current Using Volume Of Conductor Material (2-phase 4-wire US) Formula

current7 = sqrt(Volume Of Conductor Material*Line Losses/(4*Resistivity*(Length^2)))
C7 = sqrt(V*W/(4*ρ*(l^2)))

## What is the volume of conductor material in 2-phase 4-wire underground system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

## How to Calculate Load Current Using Volume Of Conductor Material (2-phase 4-wire US)?

Load Current Using Volume Of Conductor Material (2-phase 4-wire US) calculator uses current7 = sqrt(Volume Of Conductor Material*Line Losses/(4*Resistivity*(Length^2))) to calculate the Current Of 2-Φ 4-wire system, The Load Current Using Volume Of Conductor Material (2-phase 4-wire US) formula is defined as the current that flows into the load of the two-phase four-wire underground system. Current Of 2-Φ 4-wire system and is denoted by C7 symbol.

How to calculate Load Current Using Volume Of Conductor Material (2-phase 4-wire US) using this online calculator? To use this online calculator for Load Current Using Volume Of Conductor Material (2-phase 4-wire US), enter Volume Of Conductor Material (V), Line Losses (W), Resistivity (ρ) and Length (l) and hit the calculate button. Here is how the Load Current Using Volume Of Conductor Material (2-phase 4-wire US) calculation can be explained with given input values -> 242.5356 = sqrt(60*0.6/(4*1.7E-05*(3^2))).

### FAQ

What is Load Current Using Volume Of Conductor Material (2-phase 4-wire US)?
The Load Current Using Volume Of Conductor Material (2-phase 4-wire US) formula is defined as the current that flows into the load of the two-phase four-wire underground system and is represented as C7 = sqrt(V*W/(4*ρ*(l^2))) or current7 = sqrt(Volume Of Conductor Material*Line Losses/(4*Resistivity*(Length^2))). Volume Of Conductor Material the 3-dimensional space enclosed by a conductor material, Line Losses is defined as the losses that are produced in the line, Resistivity is the measure of how strongly a material opposes the flow of current through them and Length is the measurement or extent of something from end to end.
How to calculate Load Current Using Volume Of Conductor Material (2-phase 4-wire US)?
The Load Current Using Volume Of Conductor Material (2-phase 4-wire US) formula is defined as the current that flows into the load of the two-phase four-wire underground system is calculated using current7 = sqrt(Volume Of Conductor Material*Line Losses/(4*Resistivity*(Length^2))). To calculate Load Current Using Volume Of Conductor Material (2-phase 4-wire US), you need Volume Of Conductor Material (V), Line Losses (W), Resistivity (ρ) and Length (l). With our tool, you need to enter the respective value for Volume Of Conductor Material, Line Losses, Resistivity and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Current Of 2-Φ 4-wire system?
In this formula, Current Of 2-Φ 4-wire system uses Volume Of Conductor Material, Line Losses, Resistivity and Length. We can use 1 other way(s) to calculate the same, which is/are as follows -
• current7 = sqrt(2)*Power Transmitted/(Maximum Voltage*cos(Theta))
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