Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Calculator

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume Of Conductor [V]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Load Current using Volume of Conductor Material (2 Phase 4 Wire US) [I]

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Formula

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Load Current using Volume of Conductor Material (2 Phase 4 Wire US)

Formula

`"I" = sqrt("V"*"P"_{"loss"}/(4*"ρ"*("L"^2)))`

Example

`"63.95368A"=sqrt("60m³"*"2.67W"/(4*"0.000017Ω*m"*(("24m")^2)))`

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Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2)))
I = sqrt(V*P_loss/(4*ρ*(L^2)))
This formula uses 1 Functions, 5 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

I = sqrt(V*P_loss/(4*ρ*(L^2))) --> sqrt(60*2.67/(4*1.7E-05*(24^2)))

Evaluating ... ...

I = 63.9536826884251

STEP 3: Convert Result to Output's Unit

63.9536826884251 Ampere --> No Conversion Required

FINAL ANSWER

63.9536826884251 ≈ 63.95368 Ampere <-- Current Underground AC

(Calculation completed in 00.005 seconds)

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< 10+ Current & Voltage Calculators

Maximum Voltage using Area of X-Section (2 Phase 4 Wire US)

Go Maximum Voltage Underground AC = (2*Power Transmitted/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire))

RMS Voltage using Area of X-Section (2 Phase 4 Wire US)

Go Root Mean Square Voltage = (Power Transmitted/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire))

Maximum Voltage using Line Losses (2 Phase 4 Wire US)

Go Maximum Voltage Underground AC = (2*Power Transmitted/cos(Phase Difference))*sqrt(Resistance Underground AC/(Line Losses))

RMS Voltage using Line Losses (2 Phase 4 Wire US)

Go Root Mean Square Voltage = (Power Transmitted/cos(Phase Difference))*sqrt(Resistance Underground AC/(Line Losses))

Load Current using Area of X-Section (2 Phase 4 Wire US)

Go Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire))

Load Current using Volume of Conductor Material (2 Phase 4 Wire US)

Go Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2)))

Maximum Voltage using Load Current (2 Phase 4 Wire US)

Go Maximum Voltage Underground AC = sqrt(2)*Power Transmitted/(Current Underground AC*cos(Phase Difference))

Load Current (2 Phase 4 Wire US)

Go Current Underground AC = sqrt(2)*Power Transmitted/(Maximum Voltage Underground AC*cos(Phase Difference))

RMS Voltage using Load Current (2 Phase 4 Wire US)

Go Root Mean Square Voltage = Power Transmitted/(Current Underground AC*cos(Phase Difference))

Load Current using Line Losses (2 Phase 4 Wire US)

Go Current Underground AC = sqrt(Line Losses/2*Resistance Underground AC)

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Formula

Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2)))
I = sqrt(V*P_loss/(4*ρ*(L^2)))

What is the volume of conductor material in 2-phase 4-wire underground system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) calculator uses Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2))) to calculate the Current Underground AC, The Load Current using Volume of Conductor Material (2 phase 4 wire US) formula is defined as the current that flows into the load of the two-phase four-wire underground system. Current Underground AC is denoted by I symbol.

How to calculate Load Current using Volume of Conductor Material (2 Phase 4 Wire US) using this online calculator? To use this online calculator for Load Current using Volume of Conductor Material (2 Phase 4 Wire US), enter Volume Of Conductor (V), Line Losses (P_loss), Resistivity (ρ) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Load Current using Volume of Conductor Material (2 Phase 4 Wire US) calculation can be explained with given input values -> 63.95368 = sqrt(60*2.67/(4*1.7E-05*(24^2))).

FAQ

What is Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

The Load Current using Volume of Conductor Material (2 phase 4 wire US) formula is defined as the current that flows into the load of the two-phase four-wire underground system and is represented as I = sqrt(V*P_loss/(4*ρ*(L^2))) or Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2))). Volume Of Conductor the 3-dimensional space enclosed by a conductor material, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Resistivity is the measure of how strongly a material opposes the flow of current through them & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

The Load Current using Volume of Conductor Material (2 phase 4 wire US) formula is defined as the current that flows into the load of the two-phase four-wire underground system is calculated using Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2))). To calculate Load Current using Volume of Conductor Material (2 Phase 4 Wire US), you need Volume Of Conductor (V), Line Losses (P_loss), Resistivity (ρ) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Volume Of Conductor, Line Losses, Resistivity & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Current Underground AC?

In this formula, Current Underground AC uses Volume Of Conductor, Line Losses, Resistivity & Length of Underground AC Wire. We can use 3 other way(s) to calculate the same, which is/are as follows -

Current Underground AC = sqrt(Line Losses/2*Resistance Underground AC)
Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire))
Current Underground AC = sqrt(2)*Power Transmitted/(Maximum Voltage Underground AC*cos(Phase Difference))

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