Molal Heat of Vaporization given Rate of Pressure Change Calculator

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✖Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP.ⓘ Change in Pressure [ΔP]			+10% -10%
✖Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.ⓘ Molar Volume [V_m]			+10% -10%
✖Molal Liquid Volume is the volume of liquid substance.ⓘ Molal Liquid Volume [v]			+10% -10%
✖Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.ⓘ Absolute Temperature [T_abs]			+10% -10%
✖The Change in Temperature is the difference between the initial and final temperature.ⓘ Change in Temperature [∆T]			+10% -10%

✖Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid.ⓘ Molal Heat of Vaporization given Rate of Pressure Change [ΔH_v]

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Formula

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Molal Heat of Vaporization given Rate of Pressure Change

Formula

`"ΔH"_{"v"} = ("ΔP"*("V"_{"m"}-"v")*"T"_{"abs"})/"∆T"`

Example

`"14.469KJ/mol"=("100Pa"*("32m³/mol"-"5.5m³")*"273")/"50K"`

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Molal Heat of Vaporization given Rate of Pressure Change Solution

STEP 0: Pre-Calculation Summary

Formula Used

Molal Heat of Vaporization = (Change in Pressure*(Molar Volume-Molal Liquid Volume)*Absolute Temperature)/Change in Temperature
ΔH_v = (ΔP*(V_m-v)*T_abs)/∆T
This formula uses 6 Variables

Variables Used

Molal Heat of Vaporization - (Measured in Joule Per Mole) - Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid.
Change in Pressure - (Measured in Pascal) - Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP.
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.
Molal Liquid Volume - (Measured in Cubic Meter) - Molal Liquid Volume is the volume of liquid substance.
Absolute Temperature - Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.
Change in Temperature - (Measured in Kelvin) - The Change in Temperature is the difference between the initial and final temperature.

STEP 1: Convert Input(s) to Base Unit

Change in Pressure: 100 Pascal --> 100 Pascal No Conversion Required
Molar Volume: 32 Cubic Meter per Mole --> 32 Cubic Meter per Mole No Conversion Required
Molal Liquid Volume: 5.5 Cubic Meter --> 5.5 Cubic Meter No Conversion Required
Absolute Temperature: 273 --> No Conversion Required
Change in Temperature: 50 Kelvin --> 50 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ΔH_v = (ΔP*(V_m-v)*T_abs)/∆T --> (100*(32-5.5)*273)/50

Evaluating ... ...

ΔH_v = 14469

STEP 3: Convert Result to Output's Unit

14469 Joule Per Mole -->14.469 KiloJoule Per Mole (Check conversion here)

FINAL ANSWER

14.469 KiloJoule Per Mole <-- Molal Heat of Vaporization

(Calculation completed in 00.004 seconds)

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Molal Heat of Vaporization given Rate of Pressure Change

Go Molal Heat of Vaporization = (Change in Pressure*(Molar Volume-Molal Liquid Volume)*Absolute Temperature)/Change in Temperature

Specific Heat Capacity in Thermochemical Equation

Go Specific Heat Capacity = Heat Transfer/(Mass*Change in Temperature)

Heat Transfer in Thermochemical Reaction

Go Heat Transfer = Mass*Specific Heat Capacity*Change in Temperature

Amount of Heat Released in Bomb Calorimetry

Go Heat Transfer in Reaction = -(Heat Transfer in Bomb Calorimeter*Change in Temperature)

Change in Enthalpy of Vaporization

Go Change in Enthalpy of Vaporization = Enthalpy of gas state-Enthalpy of liquid state

Change in Internal Energy of Thermochemical System

Go Change in Internal Energy = Final Potential Energy-Initial Potential Energy

Amount of Heat released in Constant-Volume Calorimetry

Go Heat Transfer = -(Heat Capacity*Change in Temperature)

Change in Temperature in Calorimetry

Go Change in Temperature = -(Heat Transfer/Heat Capacity)

Heat Capacity in Calorimetry

Go Heat Capacity = Heat/Difference in Temperature

Molal Heat of Vaporization given Rate of Pressure Change Formula

Molal Heat of Vaporization = (Change in Pressure*(Molar Volume-Molal Liquid Volume)*Absolute Temperature)/Change in Temperature
ΔH_v = (ΔP*(V_m-v)*T_abs)/∆T

What is Clausius-Clapeyron Equation ?

The rate of increase in vapor pressure per unit increase in temperature is given by the Clausius-Clapeyron equation. More generally the Clausius-Clapeyron equation pertains to the relationship between the pressure and temperature for conditions of equilibrium between two phases. The two phases could be vapor and solid for sublimation or solid and liquid for melting.

How to Calculate Molal Heat of Vaporization given Rate of Pressure Change?

Molal Heat of Vaporization given Rate of Pressure Change calculator uses Molal Heat of Vaporization = (Change in Pressure*(Molar Volume-Molal Liquid Volume)*Absolute Temperature)/Change in Temperature to calculate the Molal Heat of Vaporization, The Molal Heat of Vaporization given rate of pressure change is the energy needed to vaporize one mole of a liquid. Molal Heat of Vaporization is denoted by ΔH_v symbol.

How to calculate Molal Heat of Vaporization given Rate of Pressure Change using this online calculator? To use this online calculator for Molal Heat of Vaporization given Rate of Pressure Change, enter Change in Pressure (ΔP), Molar Volume (V_m), Molal Liquid Volume (v), Absolute Temperature (T_abs) & Change in Temperature (∆T) and hit the calculate button. Here is how the Molal Heat of Vaporization given Rate of Pressure Change calculation can be explained with given input values -> 0.014469 = (100*(32-5.5)*273)/50.

FAQ

What is Molal Heat of Vaporization given Rate of Pressure Change?

The Molal Heat of Vaporization given rate of pressure change is the energy needed to vaporize one mole of a liquid and is represented as ΔH_v = (ΔP*(V_m-v)*T_abs)/∆T or Molal Heat of Vaporization = (Change in Pressure*(Molar Volume-Molal Liquid Volume)*Absolute Temperature)/Change in Temperature. Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP, Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure, Molal Liquid Volume is the volume of liquid substance, Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero & The Change in Temperature is the difference between the initial and final temperature.

How to calculate Molal Heat of Vaporization given Rate of Pressure Change?

The Molal Heat of Vaporization given rate of pressure change is the energy needed to vaporize one mole of a liquid is calculated using Molal Heat of Vaporization = (Change in Pressure*(Molar Volume-Molal Liquid Volume)*Absolute Temperature)/Change in Temperature. To calculate Molal Heat of Vaporization given Rate of Pressure Change, you need Change in Pressure (ΔP), Molar Volume (V_m), Molal Liquid Volume (v), Absolute Temperature (T_abs) & Change in Temperature (∆T). With our tool, you need to enter the respective value for Change in Pressure, Molar Volume, Molal Liquid Volume, Absolute Temperature & Change in Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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