Molecular Mass of a liquid forming an immiscible mixture with Water Solution

STEP 0: Pre-Calculation Summary
Formula Used
Molecular Mass of Liquid B = (Partial Pressure of pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of water in an immiscible mixture)
MB = (Powater*Mwater*WB)/(PBo*Wwater)
This formula uses 6 Variables
Variables Used
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.
Partial Pressure of pure Water - (Measured in Pascal) - The Partial Pressure of pure Water is the pressure exerted by water vapours prior addition to solution.
Molecular Mass of Water - (Measured in Kilogram) - The Molecular Mass of Water is equal to 18g per mole.
Weight of Liquid B - (Measured in Kilogram) - The Weight of Liquid B in a mixture of immiscible liquids.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Weight of water in an immiscible mixture - (Measured in Kilogram) - The weight of water in an immiscible mixture with another liquid.
STEP 1: Convert Input(s) to Base Unit
Partial Pressure of pure Water: 0.5 Standard Atmosphere --> 50662.5 Pascal (Check conversion here)
Molecular Mass of Water: 18 Gram --> 0.018 Kilogram (Check conversion here)
Weight of Liquid B: 0.1 Kilogram --> 0.1 Kilogram No Conversion Required
Vapor Pressure of Pure Component B: 10 Pascal --> 10 Pascal No Conversion Required
Weight of water in an immiscible mixture: 0.1 Kilogram --> 0.1 Kilogram No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
MB = (Powater*Mwater*WB)/(PBo*Wwater (50662.5*0.018*0.1)/(10*0.1)
Evaluating ... ...
MB = 91.1925
STEP 3: Convert Result to Output's Unit
91.1925 Kilogram -->91192.5 Gram (Check conversion here)
FINAL ANSWER
91192.5 Gram <-- Molecular Mass of Liquid B
(Calculation completed in 00.031 seconds)

Credits

Created by Prerana Bakli
National Institute of Technology (NIT), Meghalaya
Prerana Bakli has created this Calculator and 800+ more calculators!
Verified by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
Akshada Kulkarni has verified this Calculator and 900+ more calculators!

10+ Immiscible Liquids Calculators

Total Vapour Pressure of mixture of given partial pressure of one liquid
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component B+((Vapor Pressure of Pure Component B*Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)) Go
Molecular Mass of a liquid forming an immiscible mixture with Water
Molecular Mass of Liquid B = (Partial Pressure of pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of water in an immiscible mixture) Go
Molecular Mass of liquid in mixture of 2 immiscible liquids given weights of liquids
Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go
Weight of liquid in mixture of 2 immiscible liquids given weight of other liquid
Weight of Liquid A = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Go
Partial Vapour Pressure of immiscible liquid given partial pressure of other
Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B) Go
Ratio of Weights of 2 Immiscible Liquids forming Mixture
Ratio of Weights of 2 immiscible liquids = (Vapor Pressure of Pure Component A*Molecular Mass of Liquid A)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) Go
Ratio of Molecular Mass of 2 immiscible liquids
Ratio of Molecular Masses of 2 immiscible liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B) Go
Ratio of partial vapour pressures of 2 Immiscible Liquids in terms of weight and molecular mass
Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A) Go
Total Pressure of mixture of two Immiscible Liquids
Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B Go
Ratio of partial pressure of 2 immiscible liquids in terms their number of moles
Ratio of Partial Pressures of 2 Immiscible Liquids = Number of moles of Liquid A/No. of moles of Liquid B Go

Molecular Mass of a liquid forming an immiscible mixture with Water Formula

Molecular Mass of Liquid B = (Partial Pressure of pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of water in an immiscible mixture)
MB = (Powater*Mwater*WB)/(PBo*Wwater)

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Molecular Mass of a liquid forming an immiscible mixture with Water?

Molecular Mass of a liquid forming an immiscible mixture with Water calculator uses Molecular Mass of Liquid B = (Partial Pressure of pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of water in an immiscible mixture) to calculate the Molecular Mass of Liquid B, The Molecular Mass of a liquid forming an immiscible mixture with Water considering A as water and B as other liquids for corresponding parameters. Molecular Mass of Liquid B is denoted by MB symbol.

How to calculate Molecular Mass of a liquid forming an immiscible mixture with Water using this online calculator? To use this online calculator for Molecular Mass of a liquid forming an immiscible mixture with Water, enter Partial Pressure of pure Water (Powater), Molecular Mass of Water (Mwater), Weight of Liquid B (WB), Vapor Pressure of Pure Component B (PBo) & Weight of water in an immiscible mixture (Wwater and hit the calculate button. Here is how the Molecular Mass of a liquid forming an immiscible mixture with Water calculation can be explained with given input values -> 91192.5 = (50662.5*0.018*0.1)/(10*0.1).

FAQ

What is Molecular Mass of a liquid forming an immiscible mixture with Water?
The Molecular Mass of a liquid forming an immiscible mixture with Water considering A as water and B as other liquids for corresponding parameters and is represented as MB = (Powater*Mwater*WB)/(PBo*Wwater) or Molecular Mass of Liquid B = (Partial Pressure of pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of water in an immiscible mixture). The Partial Pressure of pure Water is the pressure exerted by water vapours prior addition to solution, The Molecular Mass of Water is equal to 18g per mole, The Weight of Liquid B in a mixture of immiscible liquids, Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase & The weight of water in an immiscible mixture with another liquid.
How to calculate Molecular Mass of a liquid forming an immiscible mixture with Water?
The Molecular Mass of a liquid forming an immiscible mixture with Water considering A as water and B as other liquids for corresponding parameters is calculated using Molecular Mass of Liquid B = (Partial Pressure of pure Water*Molecular Mass of Water*Weight of Liquid B)/(Vapor Pressure of Pure Component B*Weight of water in an immiscible mixture). To calculate Molecular Mass of a liquid forming an immiscible mixture with Water, you need Partial Pressure of pure Water (Powater), Molecular Mass of Water (Mwater), Weight of Liquid B (WB), Vapor Pressure of Pure Component B (PBo) & Weight of water in an immiscible mixture (Wwater. With our tool, you need to enter the respective value for Partial Pressure of pure Water, Molecular Mass of Water, Weight of Liquid B, Vapor Pressure of Pure Component B & Weight of water in an immiscible mixture and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
Share Image
Let Others Know
LinkedIn
Email
WhatsApp
Copied!