Chilvera Bhanu Teja
Institute of Aeronautical Engineering (IARE), Hyderabad
Chilvera Bhanu Teja has created this Calculator and 200+ more calculators!
Vaibhav Malani
National Institute of Technology (NIT), Tiruchirapalli
Vaibhav Malani has verified this Calculator and 100+ more calculators!

11 Other formulas that you can solve using the same Inputs

Periodic time of SHM for compound pendulum in terms of radius of gyration
Periodic time for compound pendulum=2*pi*sqrt(((Radius of gyration^2)+(Distance of point of suspension of pendulum from the center of gravity^2))/(Acceleration Due To Gravity*Distance of point of suspension of pendulum from the center of gravity)) GO
Theoretical Maximum Stress for Secant Code Steels
Critical stress=Yield Strength/(1+((Eccentricity*End Fixity Coefficient/(Radius of gyration^2))*(sec((1/Radius of gyration)*sqrt(Concentrated load/(4*Cross sectional area*Modulus Of Elasticity)))))) GO
Maximum Stress For a Circular Section Under Compression
Maximum stress at crack tip=(0.372+0.056*(Distance from nearest Edge/Radius of gyration)*(Concentrated load/Distance from nearest Edge)*sqrt(Radius of gyration*Distance from nearest Edge)) GO
Theoretical Maximum Stress for Johnson Code Steels
Critical stress=Yield Strength*(1-(Stress at any point y/(4*Coefficient for Column End Conditions*(pi^2)*Modulus Of Elasticity))*((Length/Radius of gyration)^2)) GO
Euler's Formula for Critical Buckling Load when Area is Given
Critical Buckling Load=(Coefficient for Column End Conditions*(pi^2)*Modulus Of Elasticity*Cross sectional area)/((Length/Radius of gyration)^2) GO
Total Unit Stress in Eccentric Loading when Radius of Gyration is Given
Total Unit Stress=(Axial Load/Cross sectional area)*(1+(Outermost Fiber Distance*Distance_from Load Applied/(Radius of gyration^2))) GO
Time period of Rolling
Time period of rolling=2*pi*(sqrt(((Radius of gyration)^(2))/(Acceleration Due To Gravity*Metacentric height))) GO
Theoretical Maximum Stress for ANC Code Alloy Steel Tubing
Critical stress=135000-(15.9/End Fixity Coefficient)*((Length/Radius of gyration)^2) GO
Theoretical Maximum Stress for ANC Code 2017ST Aluminium
Critical stress=34500-(245/sqrt(End Fixity Coefficient))*(Length/Radius of gyration) GO
Theoretical Maximum Stress for ANC Code Spruce
Critical stress=5000-(0.5/End Fixity Coefficient)*((Length/Radius of gyration)^2) GO
Minimum periodic time of SHM for compound pendulum
Time Period SHM=2*pi*sqrt(2*Radius of gyration/Acceleration Due To Gravity) GO

11 Other formulas that calculate the same Output

Moment of inertia of hollow rectangle about centroidal axis x-x parallel to breadth
Area Moment Of Inertia=((Breadth of rectangle*Length of rectangle^3)-(Inner breadth of hollow rectangle*Inner length of hollow rectangle^3))/12 GO
Minimum Moment of Inertia of a Transverse Stiffener
Area Moment Of Inertia=Spacing of Stirrups*Breadth of the web^3*(2.5*Overall depth of column^2/Breadth of the web^2-2) GO
Moment of inertia of hollow circle about diametrical axis
Area Moment Of Inertia=(pi/64)*(Outer diameter of circular section^4-Inner Diameter of Circular Section^4) GO
Moment of Inertia from bending moment and bending stress
Area Moment Of Inertia=(Bending moment*Distance from neutral axis)/Bending Stress GO
Moment of inertia of rectangle about centroidal axis along x-x parallel to breadth
Area Moment Of Inertia=Breadth of rectangle*(Length of rectangle^3/12) GO
Moment of inertia of rectangle about centroidal axis along y-y parallel to length
Area Moment Of Inertia=Length of rectangle*(Breadth of rectangle^3)/12 GO
Moment of inertia of triangle about centroidal axis x-x parallel to base
Area Moment Of Inertia=(Base of triangle*Height of triangle^3)/36 GO
Smallest Moment of Inertia Allowable at Worst Section for Wrought Iron
Area Moment Of Inertia=Allowable Load*(Length of column^2) GO
Moment of inertia of rectangular cross-section along centroidal axis parallel to length
Area Moment Of Inertia=((Length^3)*Breadth)/12 GO
Moment of inertia of a circular cross-section about the diameter
Area Moment Of Inertia=pi*(Diameter ^4)/64 GO
Moment of inertia of circle about diametrical axis
Area Moment Of Inertia=(pi*Diameter ^4)/64 GO

Moment of inertia if radius of gyration is known Formula

Area Moment Of Inertia=Area of cross section*Radius of gyration^2
I=A*k<sub>G</sub>^2
More formulas
Force of Friction between the cylinder and the surface of inclined plane if cylinder is rolling without slipping down a ramp GO
Coefficient of Friction between the cylinder and the surface of inclined plane if cylinder is rolling without slipping down GO
Coefficient of Friction GO
Limiting angle of friction GO
Angle of repose GO
Minimum force required to slide a body on rough horizontal plane GO
Effort required to move the body up the plane neglecting friction GO
Effort required to move the body down the plane neglecting friction GO
Effort applied to move the body in upward direction on inclined plane considering friction GO
Effort applied to move the body in downward direction on inclined plane considering friction GO
Effort applied perpendicular to inclined plane to move the body in upward direction considering friction GO
Effort applied parallel to inclined plane to move the body in upward direction considering friction GO
Effort applied perpendicular to inclined plane to move the body in upward/downward direction neglecting friction GO
Effort applied parallel to inclined plane to move the body in upward/downward direction neglecting friction GO
Effort applied perpendicular to inclined plane to move the body in downward direction considering friction GO
Effort applied parallel to inclined plane to move the body in downward direction considering friction GO
Efficiency of inclined plane when effort applied to move the body in upward direction on inclined plane GO
Efficiency of inclined plane when effort applied horizontally to move the body in upward direction on inclined plane GO
Efficiency of inclined plane when effort applied parallel to move the body in upward direction on inclined plane GO
Efficiency of inclined plane when effort applied to move the body in downward direction on inclined plane GO
Efficiency of inclined plane when effort applied horizontally to move the body in downward direction on inclined plane GO
Efficiency of inclined plane when effort applied parallel to move the body in downward direction on inclined plane GO
Total torque required to overcome friction in rotating a screw GO
Resultant of two forces acting on a particle with an angle(θ) GO
Inclination of resultant of two forces acting on a particle GO
Resultant of two forces acting on a particle at 90° GO
Resultant of two forces acting on a particle at 0° GO
Resultant of two forces acting on a particle at 180° GO
Resolution of force with angle (θ) along horizontal direction GO
Resolution of force with angle (θ) along vertical direction GO
Mechanical advantage if load and effort is known GO
Effort required by machine to overcome resistance to get work done GO
Load lifted if effort and mechanical advantage is known GO
Work done by effort GO
Useful work output of the machine GO
Ideal effort if load and velocity ratio is known GO
Ideal load if velocity ratio and effort is known GO
Torque required while load is ascending in screw jack GO
Torque required while load is descending in screw jack GO
Radius of gyration if moment of inertia and area is known GO
Moment of inertia of circle about diametrical axis GO
Force of attraction between two masses separated by distance GO
Frictional effort lost GO
Net shortening of the chain in weston's differential pulley block GO
Net shortening of the string in worm gear pulley block GO
Angle of banking GO
Superelevation in railways GO
Maximum velocity to avoid overturning of a vehicle along a level circular path GO
Maximum velocity to avoid skidding away of a vehicle along a level circular path GO
Horizontal component of velocity of a particle projected upwards from a point at an angle GO
Horizontal range of a projectile GO
Horizontal range of a projectile, if horizontal velocity and time of flight is known GO
Maximum horizontal range of a projectile GO
Initial velocity, if maximum horizontal range of a projectile is known GO
Maximum height of a projectile on a horizontal plane GO
Maximum height of a projectile on a horizontal plane, if average vertical velocity is known GO
Reaction of the lift, when the lift is moving upwards GO
Net downward force, when the lift is moving downwards GO
Reaction of the lift, when the lift is moving downwards GO
Force exerted by the mass carried by the lift on its floor, when the lift is moving upwards GO
Tension in the cable, when the lift is moving upwards with mass GO
Normal reaction on the inclined plane due to mass of the body. GO
Moment of a force GO
Resultant of two like parallel forces GO
Resultant of two unlike parallel forces unequal in magnitude GO
Moment of the couple GO
Angular velocity of a body moving in a circle GO
Angular velocity if linear velocity is known GO
Angular acceleration if linear acceleration is known GO
Final angular velocity GO
Initial angular velocity GO
Angular displacement GO
Average angular velocity GO

What is moment of inertia?

Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

How to Calculate Moment of inertia if radius of gyration is known?

Moment of inertia if radius of gyration is known calculator uses Area Moment Of Inertia=Area of cross section*Radius of gyration^2 to calculate the Area Moment Of Inertia, The Moment of inertia if radius of gyration is known formula is defined as the product of area of cross section and square of radius of gyration. Area Moment Of Inertia and is denoted by I symbol.

How to calculate Moment of inertia if radius of gyration is known using this online calculator? To use this online calculator for Moment of inertia if radius of gyration is known, enter Area of cross section (A) and Radius of gyration (kG) and hit the calculate button. Here is how the Moment of inertia if radius of gyration is known calculation can be explained with given input values -> 432 = 48*3^2.

FAQ

What is Moment of inertia if radius of gyration is known?
The Moment of inertia if radius of gyration is known formula is defined as the product of area of cross section and square of radius of gyration and is represented as I=A*kG^2 or Area Moment Of Inertia=Area of cross section*Radius of gyration^2. Area of cross section is the enclosed surface area, product of length and breadth. and Radius of gyration or gyradius of a body about an axis of rotation is defined as the radial distance to a point which would have a moment of inertia the same as the body's actual distribution of mass, if the total mass of the body were concentrated there.
How to calculate Moment of inertia if radius of gyration is known?
The Moment of inertia if radius of gyration is known formula is defined as the product of area of cross section and square of radius of gyration is calculated using Area Moment Of Inertia=Area of cross section*Radius of gyration^2. To calculate Moment of inertia if radius of gyration is known, you need Area of cross section (A) and Radius of gyration (kG). With our tool, you need to enter the respective value for Area of cross section and Radius of gyration and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Area Moment Of Inertia?
In this formula, Area Moment Of Inertia uses Area of cross section and Radius of gyration. We can use 11 other way(s) to calculate the same, which is/are as follows -
  • Area Moment Of Inertia=Allowable Load*(Length of column^2)
  • Area Moment Of Inertia=(Bending moment*Distance from neutral axis)/Bending Stress
  • Area Moment Of Inertia=((Length^3)*Breadth)/12
  • Area Moment Of Inertia=Breadth of rectangle*(Length of rectangle^3/12)
  • Area Moment Of Inertia=Length of rectangle*(Breadth of rectangle^3)/12
  • Area Moment Of Inertia=((Breadth of rectangle*Length of rectangle^3)-(Inner breadth of hollow rectangle*Inner length of hollow rectangle^3))/12
  • Area Moment Of Inertia=(Base of triangle*Height of triangle^3)/36
  • Area Moment Of Inertia=(pi*Diameter ^4)/64
  • Area Moment Of Inertia=(pi/64)*(Outer diameter of circular section^4-Inner Diameter of Circular Section^4)
  • Area Moment Of Inertia=pi*(Diameter ^4)/64
  • Area Moment Of Inertia=Spacing of Stirrups*Breadth of the web^3*(2.5*Overall depth of column^2/Breadth of the web^2-2)
Share Image
Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!