Moment of Inertia of Circular Ring about Perpendicular Axis through its Center Solution

STEP 0: Pre-Calculation Summary
Formula Used
Moment of Inertia = Mass of Body*Radius of body^2
I = M*r^2
This formula uses 3 Variables
Variables Used
Moment of Inertia - (Measured in Kilogram Square Meter) - Moment of Inertia is the measure of the resistance of a body to angular acceleration about a given axis.
Mass of Body - (Measured in Kilogram) - Mass of body is the quantity of matter in a body regardless of its volume or of any forces acting on it.
Radius of body - (Measured in Meter) - Radius of body is a radial line from the focus to any point of a curve.
STEP 1: Convert Input(s) to Base Unit
Mass of Body: 12.6 Kilogram --> 12.6 Kilogram No Conversion Required
Radius of body: 2.1 Meter --> 2.1 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
I = M*r^2 --> 12.6*2.1^2
Evaluating ... ...
I = 55.566
STEP 3: Convert Result to Output's Unit
55.566 Kilogram Square Meter --> No Conversion Required
FINAL ANSWER
55.566 Kilogram Square Meter <-- Moment of Inertia
(Calculation completed in 00.004 seconds)

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National Institute Of Technology (NIT), Hamirpur
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8 Rotational Motion Calculators

Moment of Inertia of Right Circular Solid Cylinder about its Symmetry Axis
Go Moment of Inertia = (Mass of Body*(Radius of body^2))/2
Moment of Inertia of Solid Sphere about its Diameter
Go Moment of Inertia = 2*(Mass of Body*Radius of body^2)/5
Moment of Inertia of Circular Disc about Perpendicular Axis through its Center
Go Moment of Inertia = (Mass of Body*Radius of body^2)/2
Moment of Inertia of Rod about Perpendicular Axis through its Center
Go Moment of Inertia = (Mass of Body*Length of Rod^2)/12
Moment of Inertia of Spherical Shell about its Diameter
Go Moment of Inertia = 2*(Mass of Body*Radius of body)/3
Moment of Inertia of Pendulum Bob
Go Moment of Inertia = Mass of Body*Length of String^2
Moment of Inertia of Circular Ring about Perpendicular Axis through its Center
Go Moment of Inertia = Mass of Body*Radius of body^2
Moment of Inertia of Right Circular Hollow Cylinder about its Axis
Go Moment of Inertia = Mass of Body*Radius of body^2

Moment of Inertia of Circular Ring about Perpendicular Axis through its Center Formula

Moment of Inertia = Mass of Body*Radius of body^2
I = M*r^2

What does moment of inertia mean?

Moment of inertia, in physics, quantitative measure of a body's rotational inertia—i.e., the opposition that the body exhibits to having its speed of rotation about an axis altered by the application of torque (turning force). The axis may be internal or external and may or may not be fixed.

How to Calculate Moment of Inertia of Circular Ring about Perpendicular Axis through its Center?

Moment of Inertia of Circular Ring about Perpendicular Axis through its Center calculator uses Moment of Inertia = Mass of Body*Radius of body^2 to calculate the Moment of Inertia, Moment of Inertia of Circular Ring about Perpendicular Axis through its Center is a quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation. Moment of Inertia is denoted by I symbol.

How to calculate Moment of Inertia of Circular Ring about Perpendicular Axis through its Center using this online calculator? To use this online calculator for Moment of Inertia of Circular Ring about Perpendicular Axis through its Center, enter Mass of Body (M) & Radius of body (r) and hit the calculate button. Here is how the Moment of Inertia of Circular Ring about Perpendicular Axis through its Center calculation can be explained with given input values -> 55.566 = 12.6*2.1^2.

FAQ

What is Moment of Inertia of Circular Ring about Perpendicular Axis through its Center?
Moment of Inertia of Circular Ring about Perpendicular Axis through its Center is a quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation and is represented as I = M*r^2 or Moment of Inertia = Mass of Body*Radius of body^2. Mass of body is the quantity of matter in a body regardless of its volume or of any forces acting on it & Radius of body is a radial line from the focus to any point of a curve.
How to calculate Moment of Inertia of Circular Ring about Perpendicular Axis through its Center?
Moment of Inertia of Circular Ring about Perpendicular Axis through its Center is a quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation is calculated using Moment of Inertia = Mass of Body*Radius of body^2. To calculate Moment of Inertia of Circular Ring about Perpendicular Axis through its Center, you need Mass of Body (M) & Radius of body (r). With our tool, you need to enter the respective value for Mass of Body & Radius of body and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Moment of Inertia?
In this formula, Moment of Inertia uses Mass of Body & Radius of body. We can use 7 other way(s) to calculate the same, which is/are as follows -
  • Moment of Inertia = 2*(Mass of Body*Radius of body^2)/5
  • Moment of Inertia = Mass of Body*Radius of body^2
  • Moment of Inertia = (Mass of Body*Length of Rod^2)/12
  • Moment of Inertia = 2*(Mass of Body*Radius of body)/3
  • Moment of Inertia = Mass of Body*Length of String^2
  • Moment of Inertia = (Mass of Body*(Radius of body^2))/2
  • Moment of Inertia = (Mass of Body*Radius of body^2)/2
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