No of Combinations of (P+Q) Things into Two Groups of P and Q Things Solution

STEP 0: Pre-Calculation Summary
Formula Used
Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!))
C = ((p+q)!)/((p!)*(q!))
This formula uses 3 Variables
Variables Used
Number of Combinations - Number of Combinations is defined as the total number of unique arrangements that can be made from a set of items, without regard to the order of the items.
Value of P - Value of P is any natural number or positive integer that can be used for combinatorial calculations.
Value of Q - Value of Q is any natural number or positive integer that can be used for combinatorial calculations.
STEP 1: Convert Input(s) to Base Unit
Value of P: 7 --> No Conversion Required
Value of Q: 6 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
C = ((p+q)!)/((p!)*(q!)) --> ((7+6)!)/((7!)*(6!))
Evaluating ... ...
C = 1716
STEP 3: Convert Result to Output's Unit
1716 --> No Conversion Required
FINAL ANSWER
1716 <-- Number of Combinations
(Calculation completed in 00.004 seconds)

Credits

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Created by Divanshi Jain
Netaji Subhash University of Technology, Delhi (NSUT Delhi), Dwarka
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14 Combinations Calculators

No of Combinations of N Different Things taken R at once given M Specific Things Always Occur
​ Go Number of Combinations = C((Value of N-Value of M),(Value of R-Value of M))
No of Combinations of (P+Q) Things into Two Groups of P and Q Things
​ Go Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!))
nCr or C(n,r)
​ Go Number of Combinations = (Value of N!)/(Value of R!*(Value of N-Value of R)!)
Nth Catalan Number
​ Go Nth Catalan Number = (1/(Value of N+1))*C(2*Value of N,Value of N)
No of Combinations of N Identical Things into R Different Groups if Empty Groups are Allowed
​ Go Number of Combinations = C(Value of N+Value of R-1,Value of R-1)
No of Combinations of N Different Things taken R at once and Repetition Allowed
​ Go Number of Combinations = C((Value of N+Value of R-1),Value of R)
No of Combinations of N Different Things taken R at once given M Specific Things Never Occur
​ Go Number of Combinations = C((Value of N-Value of M),Value of R)
No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once
​ Go Number of Combinations = (Value of P+1)*(Value of Q+1)*(2^Value of N)-1
Maximum Value of nCr when N is Odd
​ Go Number of Combinations = C(Value of N (Odd),(Value of N (Odd)+1)/2)
No of Combinations of N Identical Things into R Different Groups if Empty Groups are Not Allowed
​ Go Number of Combinations = C(Value of N-1,Value of R-1)
Maximum Value of nCr when N is Even
​ Go Number of Combinations = C(Value of N,Value of N/2)
No of Combinations of N Different Things taken R at once
​ Go Number of Combinations = C(Value of N,Value of R)
No of Combinations of N Different Things taken Atleast One at once
​ Go Number of Combinations = 2^(Value of N)-1
No of Combinations of N Identical Things taken Zero or more at once
​ Go Number of Combinations = Value of N+1

No of Combinations of (P+Q) Things into Two Groups of P and Q Things Formula

Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!))
C = ((p+q)!)/((p!)*(q!))

What are Combinations?

In combinatorics, Combinations refer to the different ways of selecting a subset of items from a larger set without regard to the order of selection. Combinations are used to count the number of possible outcomes when the order of selection does not matter. For example, if you have a set of three elements {A, B, C}, the Combinations of size 2 would be {AB, AC, BC}. In this case, the order of the items within each combination does not matter, so {AB} and {BA} are considered the same combination.

The number of Combinations of selecting "k" items from a set of "n" items is denoted as C(n, k). It is calculated using the binomial coefficient formula: C(n, k) = n! / (k! * (n - k)!)

Combinations have various applications in mathematics, probability theory, statistics, and other fields.

How to Calculate No of Combinations of (P+Q) Things into Two Groups of P and Q Things?

No of Combinations of (P+Q) Things into Two Groups of P and Q Things calculator uses Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!)) to calculate the Number of Combinations, The No of Combinations of (P+Q) Things into Two Groups of P and Q Things formula is defined as the total number of ways in which (p + q) things can be divided into two groups of p and q things, where p and q are distinct natural numbers. Number of Combinations is denoted by C symbol.

How to calculate No of Combinations of (P+Q) Things into Two Groups of P and Q Things using this online calculator? To use this online calculator for No of Combinations of (P+Q) Things into Two Groups of P and Q Things, enter Value of P (p) & Value of Q (q) and hit the calculate button. Here is how the No of Combinations of (P+Q) Things into Two Groups of P and Q Things calculation can be explained with given input values -> 792 = ((7+6)!)/((7!)*(6!)).

FAQ

What is No of Combinations of (P+Q) Things into Two Groups of P and Q Things?
The No of Combinations of (P+Q) Things into Two Groups of P and Q Things formula is defined as the total number of ways in which (p + q) things can be divided into two groups of p and q things, where p and q are distinct natural numbers and is represented as C = ((p+q)!)/((p!)*(q!)) or Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!)). Value of P is any natural number or positive integer that can be used for combinatorial calculations & Value of Q is any natural number or positive integer that can be used for combinatorial calculations.
How to calculate No of Combinations of (P+Q) Things into Two Groups of P and Q Things?
The No of Combinations of (P+Q) Things into Two Groups of P and Q Things formula is defined as the total number of ways in which (p + q) things can be divided into two groups of p and q things, where p and q are distinct natural numbers is calculated using Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!)). To calculate No of Combinations of (P+Q) Things into Two Groups of P and Q Things, you need Value of P (p) & Value of Q (q). With our tool, you need to enter the respective value for Value of P & Value of Q and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Number of Combinations?
In this formula, Number of Combinations uses Value of P & Value of Q. We can use 12 other way(s) to calculate the same, which is/are as follows -
  • Number of Combinations = C(Value of N,Value of R)
  • Number of Combinations = C((Value of N+Value of R-1),Value of R)
  • Number of Combinations = C((Value of N-Value of M),(Value of R-Value of M))
  • Number of Combinations = C((Value of N-Value of M),Value of R)
  • Number of Combinations = 2^(Value of N)-1
  • Number of Combinations = (Value of N!)/(Value of R!*(Value of N-Value of R)!)
  • Number of Combinations = Value of N+1
  • Number of Combinations = C(Value of N (Odd),(Value of N (Odd)+1)/2)
  • Number of Combinations = C(Value of N,Value of N/2)
  • Number of Combinations = (Value of P+1)*(Value of Q+1)*(2^Value of N)-1
  • Number of Combinations = C(Value of N+Value of R-1,Value of R-1)
  • Number of Combinations = C(Value of N-1,Value of R-1)
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