Number of Moles of Substance A and B at Equilibrium Calculator

↳

⤿

Chemical equilibrium

Ionic equilibrium

⤿

Relation between Vapour Density and Degree of Dissociation

Equilibrium Constant

Henry's law

Properties of Equilibrium Constant

Relation between Equilibrium Constant and Degree of Dissociation

Relationship between Different Equilibrium Constants

Thermodynamics in Chemical Equilibrium

⤿

Degree of Dissociation

Vapour Density at Equilibrium

✖The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.ⓘ Degree of Dissociation [𝝰]			+10% -10%
✖Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.ⓘ Number of Moles [N_moles]			+10% -10%

✖The Number of Moles at Equilibrium is the quantitative amount of moles of substances A and B present at the equilibrium stage of the chemical reaction.ⓘ Number of Moles of Substance A and B at Equilibrium [n_eq]

⎘ Copy

👎

Formula

✖

Number of Moles of Substance A and B at Equilibrium

Formula

`"n"_{"eq"} = 1+"𝝰"*("N"_{"moles"}-1)`

Example

`"1.35mol"=1+"0.35"*("2"-1)`

Calculator

LaTeX

Reset

👍

Download Chemical equilibrium Formula PDF

Number of Moles of Substance A and B at Equilibrium Solution

STEP 0: Pre-Calculation Summary

Formula Used

Number of Moles at Equilibrium = 1+Degree of Dissociation*(Number of Moles-1)
n_eq = 1+𝝰*(N_moles-1)
This formula uses 3 Variables

Variables Used

Number of Moles at Equilibrium - (Measured in Mole) - The Number of Moles at Equilibrium is the quantitative amount of moles of substances A and B present at the equilibrium stage of the chemical reaction.
Degree of Dissociation - The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
Number of Moles - Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.

STEP 1: Convert Input(s) to Base Unit

Degree of Dissociation: 0.35 --> No Conversion Required
Number of Moles: 2 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

n_eq = 1+𝝰*(N_moles-1) --> 1+0.35*(2-1)

Evaluating ... ...

n_eq = 1.35

STEP 3: Convert Result to Output's Unit

1.35 Mole --> No Conversion Required

FINAL ANSWER

1.35 Mole <-- Number of Moles at Equilibrium

(Calculation completed in 00.004 seconds)

You are here -

Home » Chemistry » Equilibrium » Chemical equilibrium » Relation between Vapour Density and Degree of Dissociation » Number of Moles of Substance A and B at Equilibrium

Credits

Created by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

Akshada Kulkarni has created this Calculator and 500+ more calculators!

Verified by Shivam Sinha

National Institute Of Technology (NIT), Surathkal

Shivam Sinha has verified this Calculator and 25+ more calculators!

< 24 Relation between Vapour Density and Degree of Dissociation Calculators

Initial Vapour Density using Concentration of Reaction

Go Initial Vapour Density = (Equilibrium Vapour Density*Initial Concentration*(1+Degree of Dissociation))/Initial Concentration

Total moles at equilibrium given number of moles of reaction

Go Total Moles at Equilibrium = Equilibrium Vapour Density*Volume of Solution*(1+Degree of Dissociation*(Number of Moles-1))

Volume of Equilibrium Mixture of Substances A and B

Go Volume at Equilibrium = (1+Degree of Dissociation*(Number of Moles Products at Equilibrium-1))*Volume of Solution

Total Moles at Equilibrium

Go Total Moles at Equilibrium = (Initial Vapour Density*Initial Number of Moles)/Equilibrium Vapour Density

Initial Vapour Density

Go Initial Vapour Density = (Total Moles at Equilibrium*Equilibrium Vapour Density)/Initial Number of Moles

Initial Total moles

Go Initial Number of Moles = (Total Moles at Equilibrium*Equilibrium Vapour Density)/Initial Vapour Density

Initial Total Moles using Total Moles at Equilibrium and Number of Moles of Reaction

Go Initial Number of Moles = Total Moles at Equilibrium*(1+Degree of Dissociation*(Number of Moles-1))

Total Moles at Equilibrium using Number of Moles and Initial Total Moles

Go Total Moles at Equilibrium = Initial Number of Moles/(1+Degree of Dissociation*(Number of Moles-1))

Initial Vapour Density using Vapour Density at Equilibrium and Number of Moles

Go Initial Vapour Density = Equilibrium Vapour Density*(1+Degree of Dissociation*(Number of Moles-1))

Initial Vapour Density when Number of Moles of Products at Equilibrium is Half

Go Initial Vapour Density = Equilibrium Vapour Density*(2-Degree of Dissociation)/2

Number of moles of products using degree of dissociation

Go Number of Moles = ((Number of Moles at Equilibrium-1)/Degree of Dissociation)+1

Total Moles at Equilibrium using Degree of Dissociation

Go Total Moles at Equilibrium = Initial Number of Moles*(1+Degree of Dissociation)

Initial Total Moles using Degree of Dissociation

Go Initial Number of Moles = Total Moles at Equilibrium/(1+Degree of Dissociation)

Initial Vapour Density given Degree of Dissociation

Go Initial Vapour Density = Equilibrium Vapour Density*(1+Degree of Dissociation)

Initial Vapour Density when Number of Moles is 2

Go Initial Vapour Density = Equilibrium Vapour Density*(Degree of Dissociation+1)

Number of Moles of Substance A and B at Equilibrium

Go Number of Moles at Equilibrium = 1+Degree of Dissociation*(Number of Moles-1)

Initial Vapour Density given Van't Hoff Factor

Go Initial Vapour Density = Van't Hoff Factor*Equilibrium Vapour Density

Van't Hoff Factor using Vapour Densities

Go Van't Hoff Factor = Initial Vapour Density/Equilibrium Vapour Density

Molecular Weight of Substance given Initial Vapour Density

Go Molecular Weight = Initial Vapour Density*Volume of Solution

Volume of Solution given Initial Vapour Density

Go Volume of Solution = Molecular Weight/Initial Vapour Density

Initial Vapour Density given Molecular Weight

Go Initial Vapour Density = Molecular Weight/Volume of Solution

Molecular Weight abnormal given Vapour Density at Equilibrium

Go Molecular Weight Abnormal = Equilibrium Vapour Density*2

Theoretical Molecular Weight given Initial Vapour Density

Go Molecular Weight Theoretical = Initial Vapour Density*2

Initial Vapour Density given Theoretical Molecular Weight

Go Initial Vapour Density = Molecular Weight Theoretical/2

Number of Moles of Substance A and B at Equilibrium Formula

Number of Moles at Equilibrium = 1+Degree of Dissociation*(Number of Moles-1)
n_eq = 1+𝝰*(N_moles-1)

What is Degree of Dissociation?

The fraction of the initial molecules that are converted at equilibrium is called the degree of Dissociation/ionization. It is unit less. The degree of dissociation is the phenomenon of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.

How to Calculate Number of Moles of Substance A and B at Equilibrium?

Number of Moles of Substance A and B at Equilibrium calculator uses Number of Moles at Equilibrium = 1+Degree of Dissociation*(Number of Moles-1) to calculate the Number of Moles at Equilibrium, The Number of moles of substance A and B at equilibrium formula is defined as the moles of reactants and products namely, A and B during the equilibrium stage of a chemical reaction. Number of Moles at Equilibrium is denoted by n_eq symbol.

How to calculate Number of Moles of Substance A and B at Equilibrium using this online calculator? To use this online calculator for Number of Moles of Substance A and B at Equilibrium, enter Degree of Dissociation (𝝰) & Number of Moles (N_moles) and hit the calculate button. Here is how the Number of Moles of Substance A and B at Equilibrium calculation can be explained with given input values -> 1.35 = 1+0.35*(2-1).

FAQ

What is Number of Moles of Substance A and B at Equilibrium?

The Number of moles of substance A and B at equilibrium formula is defined as the moles of reactants and products namely, A and B during the equilibrium stage of a chemical reaction and is represented as n_eq = 1+𝝰*(N_moles-1) or Number of Moles at Equilibrium = 1+Degree of Dissociation*(Number of Moles-1). The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration & Number of Moles is the amount of gas present in moles. 1 mole of gas weighs as much as its molecular weight.

How to calculate Number of Moles of Substance A and B at Equilibrium?

The Number of moles of substance A and B at equilibrium formula is defined as the moles of reactants and products namely, A and B during the equilibrium stage of a chemical reaction is calculated using Number of Moles at Equilibrium = 1+Degree of Dissociation*(Number of Moles-1). To calculate Number of Moles of Substance A and B at Equilibrium, you need Degree of Dissociation (𝝰) & Number of Moles (N_moles). With our tool, you need to enter the respective value for Degree of Dissociation & Number of Moles and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

Home

FREE PDFs

🔍 Search