Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD Calculator

✖Sewage discharge is the flow rate of sewage when it is being discharged in the river.ⓘ Sewage Discharge [Q_s]			+10% -10%
✖Influent BOD is the total amount of BOD which is present in the incoming sewage.ⓘ Influent BOD [Q_i]			+10% -10%
✖Effluent BOD is the amount of BOD present in the outing sewage.ⓘ Effluent BOD [Q_o]			+10% -10%
✖5 days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.ⓘ 5 days BOD [BOD5]			+10% -10%
✖Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time.ⓘ Ultimate BOD [BOD^u]			+10% -10%
✖Oxygen demand of biomass is the amount of oxygen required.ⓘ Oxygen demand of biomass [D^O2]			+10% -10%
✖Volume of wasted sludge per day is measured in terms of discharge.ⓘ Volume of Wasted Sludge per day [Q_w]			+10% -10%
✖MLSS in returned or wasted sludge is the mixed liquor suspended solids in returned sludge in terms of mg per litre.ⓘ MLSS in returned or wasted sludge [X^R]			+10% -10%

✖Theoretical oxygen requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.ⓘ Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD [O₂]

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Formula

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Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD

Formula

`"O"_{"2"} = (("Q"_{"s"}*("Q"_{"i"}-"Q"_{"o"}))/("BOD5"/"BOD"^{"u"}))-("D"^{"O2"}*"Q"_{"w"}*"X"^{"R"})`

Example

`"0.07mg/d"=(("10m³/s"*("11.2mg/L"-"0.4mg/L"))/("2mg/L"/"2mg/L"))-("2"*"9.5m³/s"*"2mg/L")`

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Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD Solution

STEP 0: Pre-Calculation Summary

Formula Used

Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-(Oxygen demand of biomass*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)
O₂ = ((Q_s*(Q_i-Q_o))/(BOD5/BOD^u))-(D^O2*Q_w*X^R)
This formula uses 9 Variables

Variables Used

Theoretical Oxygen Requirement - (Measured in Milligram per Day) - Theoretical oxygen requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.
Sewage Discharge - (Measured in Cubic Meter per Second) - Sewage discharge is the flow rate of sewage when it is being discharged in the river.
Influent BOD - (Measured in Kilogram per Cubic Meter) - Influent BOD is the total amount of BOD which is present in the incoming sewage.
Effluent BOD - (Measured in Kilogram per Cubic Meter) - Effluent BOD is the amount of BOD present in the outing sewage.
5 days BOD - (Measured in Kilogram per Cubic Meter) - 5 days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.
Ultimate BOD - (Measured in Kilogram per Cubic Meter) - Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time.
Oxygen demand of biomass - Oxygen demand of biomass is the amount of oxygen required.
Volume of Wasted Sludge per day - (Measured in Cubic Meter per Second) - Volume of wasted sludge per day is measured in terms of discharge.
MLSS in returned or wasted sludge - (Measured in Kilogram per Cubic Meter) - MLSS in returned or wasted sludge is the mixed liquor suspended solids in returned sludge in terms of mg per litre.

STEP 1: Convert Input(s) to Base Unit

Sewage Discharge: 10 Cubic Meter per Second --> 10 Cubic Meter per Second No Conversion Required
Influent BOD: 11.2 Milligram per Liter --> 0.0112 Kilogram per Cubic Meter (Check conversion here)
Effluent BOD: 0.4 Milligram per Liter --> 0.0004 Kilogram per Cubic Meter (Check conversion here)
5 days BOD: 2 Milligram per Liter --> 0.002 Kilogram per Cubic Meter (Check conversion here)
Ultimate BOD: 2 Milligram per Liter --> 0.002 Kilogram per Cubic Meter (Check conversion here)
Oxygen demand of biomass: 2 --> No Conversion Required
Volume of Wasted Sludge per day: 9.5 Cubic Meter per Second --> 9.5 Cubic Meter per Second No Conversion Required
MLSS in returned or wasted sludge: 2 Milligram per Liter --> 0.002 Kilogram per Cubic Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

O₂ = ((Q_s*(Q_i-Q_o))/(BOD5/BOD^u))-(D^O2*Q_w*X^R) --> ((10*(0.0112-0.0004))/(0.002/0.002))-(2*9.5*0.002)

Evaluating ... ...

O₂ = 0.07

STEP 3: Convert Result to Output's Unit

8.10185185185185E-13 Kilogram per Second -->0.07 Milligram per Day (Check conversion here)

FINAL ANSWER

0.07 Milligram per Day <-- Theoretical Oxygen Requirement

(Calculation completed in 00.004 seconds)

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< 4 Oxygen Required in Aeration Tank Calculators

Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD

Go Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-(Oxygen demand of biomass*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)

Oxygen Required in Aeration Tank given Oxygen Demand of Biomass

Go Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-(Oxygen demand of biomass*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)

Oxygen Required in Aeration Tank given Ultimate BOD

Go Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)

Oxygen Required in Aeration Tank

Go Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)

Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD Formula

What is aeration ?

Aeration in an activated sludge process is based on pumping air into a tank, which promotes the microbial growth in the wastewater. The microbes feed on the organic material, forming flocks which can easily settle out.

How to Calculate Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD?

Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD calculator uses Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-(Oxygen demand of biomass*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge) to calculate the Theoretical Oxygen Requirement, Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD calculates oxygen required in aeration tank when we have prior information of other parameters used. Theoretical Oxygen Requirement is denoted by O₂ symbol.

How to calculate Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD using this online calculator? To use this online calculator for Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD, enter Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q_o), 5 days BOD (BOD5), Ultimate BOD (BOD^u), Oxygen demand of biomass (D^O2), Volume of Wasted Sludge per day (Q_w) & MLSS in returned or wasted sludge (X^R) and hit the calculate button. Here is how the Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD calculation can be explained with given input values -> 6E+9 = ((10*(0.0112-0.0004))/(0.002/0.002))-(2*9.5*0.002).

FAQ

What is Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD?

Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD calculates oxygen required in aeration tank when we have prior information of other parameters used and is represented as O₂ = ((Q_s*(Q_i-Q_o))/(BOD5/BOD^u))-(D^O2*Q_w*X^R) or Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-(Oxygen demand of biomass*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge). Sewage discharge is the flow rate of sewage when it is being discharged in the river, Influent BOD is the total amount of BOD which is present in the incoming sewage, Effluent BOD is the amount of BOD present in the outing sewage, 5 days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C, Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time, Oxygen demand of biomass is the amount of oxygen required, Volume of wasted sludge per day is measured in terms of discharge & MLSS in returned or wasted sludge is the mixed liquor suspended solids in returned sludge in terms of mg per litre.

How to calculate Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD?

Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD calculates oxygen required in aeration tank when we have prior information of other parameters used is calculated using Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-(Oxygen demand of biomass*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge). To calculate Oxygen Required in Aeration Tank given Oxygen Demand and Ultimate BOD, you need Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q_o), 5 days BOD (BOD5), Ultimate BOD (BOD^u), Oxygen demand of biomass (D^O2), Volume of Wasted Sludge per day (Q_w) & MLSS in returned or wasted sludge (X^R). With our tool, you need to enter the respective value for Sewage Discharge, Influent BOD, Effluent BOD, 5 days BOD, Ultimate BOD, Oxygen demand of biomass, Volume of Wasted Sludge per day & MLSS in returned or wasted sludge and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Theoretical Oxygen Requirement?

In this formula, Theoretical Oxygen Requirement uses Sewage Discharge, Influent BOD, Effluent BOD, 5 days BOD, Ultimate BOD, Oxygen demand of biomass, Volume of Wasted Sludge per day & MLSS in returned or wasted sludge. We can use 3 other way(s) to calculate the same, which is/are as follows -

Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)
Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-(Oxygen demand of biomass*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)
Theoretical Oxygen Requirement = ((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 days BOD/Ultimate BOD))-(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)

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