3 Other formulas that calculate the same Output

Polar Moment Of Inertia Of Hollow Circular Shaft
Polar moment of Inertia=(pi*(Outer Diameter of Shaft^(4)-Inner Diameter of Shaft^(4)))/32 GO
Moment of Inertia for Hollow Circular Shaft
Polar moment of Inertia=pi*(Outer diameter^(4)-Inner Diameter^(4))/32 GO
Moment of Inertia about Polar Axis
Polar moment of Inertia=(pi*Shaft Diameter^(4))/32 GO

Polar Moment Of Inertia Of Solid Circular Shaft Formula

Polar moment of Inertia=(pi*(Diameter of shaft)^4)/32
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Polar Moment Of Inertia Of Hollow Circular Shaft GO
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Define polar moment of inertia?

Polar Moment of Inertia is a measure of an object’s capacity to oppose or resist torsion when some amount of torque is applied to it on a specified axis. Torsion, on the other hand, is nothing but the twisting of an object due to an applied torque. Polar moment of inertia basically describes the cylindrical object’s (including its segments) resistance to torsional deformation when torque is applied in a plane that is parallel to the cross-section area or in a plane that is perpendicular to the object’s central axis.

How to Calculate Polar Moment Of Inertia Of Solid Circular Shaft?

Polar Moment Of Inertia Of Solid Circular Shaft calculator uses Polar moment of Inertia=(pi*(Diameter of shaft)^4)/32 to calculate the Polar moment of Inertia, The Polar Moment of Inertia of Solid Circular Shaft formula is a quantity used to describe resistance to torsional deformation, in cylindrical objects (or segments of the cylindrical object) with an invariant cross-section and no significant warping or out-of-plane deformation. Polar moment of Inertia and is denoted by J symbol.

How to calculate Polar Moment Of Inertia Of Solid Circular Shaft using this online calculator? To use this online calculator for Polar Moment Of Inertia Of Solid Circular Shaft, enter Diameter of shaft (d) and hit the calculate button. Here is how the Polar Moment Of Inertia Of Solid Circular Shaft calculation can be explained with given input values -> 9.817E-6 = (pi*(0.1)^4)/32.

FAQ

What is Polar Moment Of Inertia Of Solid Circular Shaft?
The Polar Moment of Inertia of Solid Circular Shaft formula is a quantity used to describe resistance to torsional deformation, in cylindrical objects (or segments of the cylindrical object) with an invariant cross-section and no significant warping or out-of-plane deformation and is represented as J=(pi*(d)^4)/32 or Polar moment of Inertia=(pi*(Diameter of shaft)^4)/32. The Diameter of shaft is defined as the diameter of the hole in the iron laminations that contains the shaft.
How to calculate Polar Moment Of Inertia Of Solid Circular Shaft?
The Polar Moment of Inertia of Solid Circular Shaft formula is a quantity used to describe resistance to torsional deformation, in cylindrical objects (or segments of the cylindrical object) with an invariant cross-section and no significant warping or out-of-plane deformation is calculated using Polar moment of Inertia=(pi*(Diameter of shaft)^4)/32. To calculate Polar Moment Of Inertia Of Solid Circular Shaft, you need Diameter of shaft (d). With our tool, you need to enter the respective value for Diameter of shaft and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Polar moment of Inertia?
In this formula, Polar moment of Inertia uses Diameter of shaft. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Polar moment of Inertia=(pi*Shaft Diameter^(4))/32
  • Polar moment of Inertia=pi*(Outer diameter^(4)-Inner Diameter^(4))/32
  • Polar moment of Inertia=(pi*(Outer Diameter of Shaft^(4)-Inner Diameter of Shaft^(4)))/32
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