Power Transmitted using Area of X-Section (1-Phase 2-Wire US) Calculator

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.ⓘ Phase Difference [Φ]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted using Area of X-Section (1-Phase 2-Wire US) [P]

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Formula

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Power Transmitted using Area of X-Section (1-Phase 2-Wire US)

Formula

`"P" = sqrt(("A"*("V"_{"m"}^2)*"P"_{"loss"}*((cos("Φ"))^2))/(4*"ρ"*"L"))`

Example

`"9115.049W"=sqrt(("1.28m²"*(("230V")^2)*"2.67W"*((cos("30°"))^2))/(4*"0.000017Ω*m"*"24m"))`

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Power Transmitted using Area of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire))
P = sqrt((A*(V_m^2)*P_loss*((cos(Φ))^2))/(4*ρ*L))
This formula uses 2 Functions, 7 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P = sqrt((A*(V_m^2)*P_loss*((cos(Φ))^2))/(4*ρ*L)) --> sqrt((1.28*(230^2)*2.67*((cos(0.5235987755982))^2))/(4*1.7E-05*24))

Evaluating ... ...

P = 9115.04896569727

STEP 3: Convert Result to Output's Unit

9115.04896569727 Watt --> No Conversion Required

FINAL ANSWER

9115.04896569727 ≈ 9115.049 Watt <-- Power Transmitted

(Calculation completed in 00.004 seconds)

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< 12 Power & Power Factor Calculators

Power Transmitted using Area of X-Section (1-Phase 2-Wire US)

Go Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire))

Power Transmitted using Line Losses (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistivity*Length of Underground AC Wire))

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2))

Power Factor using Area of X-Section (1-Phase 2-Wire US)

Go Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)))

Power Factor using Line Losses (1-Phase 2-Wire US)

Go Power Factor = (2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/Line Losses*Area of Underground AC Wire)

Power Transmitted using Constant (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2))

Power Transmitted using Resistance (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistance Underground AC))

Power Factor using Resistance (1-Phase 2-Wire US)

Go Power Factor = (2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistance Underground AC/Line Losses)

Power Transmitted using Load Current (1-Phase 2-Wire US)

Go Power Transmitted = Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2))

Power Factor using Load Current (1-Phase 2-Wire US)

Go Power Factor = (sqrt(2)*Power Transmitted)/(Maximum Voltage Underground AC*Current Underground AC)

Power Factor using Volume of Conductor Material (1-Phase 2-Wire US)

Go Power Factor = sqrt((2)*Constant Underground AC/Volume Of Conductor)

Power Factor using Constant (1-Phase 2-Wire US)

Go Power Factor = sqrt(2*Constant Underground AC/Volume Of Conductor)

Power Transmitted using Area of X-Section (1-Phase 2-Wire US) Formula

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Power Transmitted using Area of X-Section (1-Phase 2-Wire US)?

Power Transmitted using Area of X-Section (1-Phase 2-Wire US) calculator uses Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire)) to calculate the Power Transmitted, The Power Transmitted using Area of X-Section (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations. Power Transmitted is denoted by P symbol.

How to calculate Power Transmitted using Area of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Power Transmitted using Area of X-Section (1-Phase 2-Wire US), enter Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m), Line Losses (P_loss), Phase Difference (Φ), Resistivity (ρ) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Power Transmitted using Area of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 9115.049 = sqrt((1.28*(230^2)*2.67*((cos(0.5235987755982))^2))/(4*1.7E-05*24)).

FAQ

What is Power Transmitted using Area of X-Section (1-Phase 2-Wire US)?

The Power Transmitted using Area of X-Section (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations and is represented as P = sqrt((A*(V_m^2)*P_loss*((cos(Φ))^2))/(4*ρ*L)) or Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire)). Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit, Resistivity is the measure of how strongly a material opposes the flow of current through them & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Power Transmitted using Area of X-Section (1-Phase 2-Wire US)?

The Power Transmitted using Area of X-Section (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations is calculated using Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire)). To calculate Power Transmitted using Area of X-Section (1-Phase 2-Wire US), you need Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m), Line Losses (P_loss), Phase Difference (Φ), Resistivity (ρ) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Area of Underground AC Wire, Maximum Voltage Underground AC, Line Losses, Phase Difference, Resistivity & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Power Transmitted?

In this formula, Power Transmitted uses Area of Underground AC Wire, Maximum Voltage Underground AC, Line Losses, Phase Difference, Resistivity & Length of Underground AC Wire. We can use 5 other way(s) to calculate the same, which is/are as follows -

Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2))
Power Transmitted = Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2))
Power Transmitted = sqrt(Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistivity*Length of Underground AC Wire))
Power Transmitted = sqrt(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistance Underground AC))
Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2))

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