Power Transmitted using Constant (1-Phase 2-Wire US) Calculator

✖Constant Underground AC is defined as the constant of line of a Overhead supply system.ⓘ Constant Underground AC [K]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted using Constant (1-Phase 2-Wire US) [P]

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Formula

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Power Transmitted using Constant (1-Phase 2-Wire US)

Formula

`"P" = sqrt("K"*"P"_{"loss"}*("V"_{"m"}^2)/(4*"ρ"*("L")^2))`

Example

`"1771.24W"=sqrt("0.87"*"2.67W"*(("230V")^2)/(4*"0.000017Ω*m"*("24m")^2))`

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Power Transmitted using Constant (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2))
P = sqrt(K*P_loss*(V_m^2)/(4*ρ*(L)^2))
This formula uses 1 Functions, 6 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Constant Underground AC - Constant Underground AC is defined as the constant of line of a Overhead supply system.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Constant Underground AC: 0.87 --> No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P = sqrt(K*P_loss*(V_m^2)/(4*ρ*(L)^2)) --> sqrt(0.87*2.67*(230^2)/(4*1.7E-05*(24)^2))

Evaluating ... ...

P = 1771.23993313591

STEP 3: Convert Result to Output's Unit

1771.23993313591 Watt --> No Conversion Required

FINAL ANSWER

1771.23993313591 ≈ 1771.24 Watt <-- Power Transmitted

(Calculation completed in 00.020 seconds)

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Home » Engineering » Electrical » Power System » Underground AC Supply » 1-Φ 2-Wire System » Power & Power Factor » Power Transmitted using Constant (1-Phase 2-Wire US)

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< 12 Power & Power Factor Calculators

Power Transmitted using Area of X-Section (1-Phase 2-Wire US)

Go Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire))

Power Transmitted using Line Losses (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistivity*Length of Underground AC Wire))

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2))

Power Factor using Area of X-Section (1-Phase 2-Wire US)

Go Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)))

Power Factor using Line Losses (1-Phase 2-Wire US)

Go Power Factor = (2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/Line Losses*Area of Underground AC Wire)

Power Transmitted using Constant (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2))

Power Transmitted using Resistance (1-Phase 2-Wire US)

Go Power Transmitted = sqrt(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistance Underground AC))

Power Factor using Resistance (1-Phase 2-Wire US)

Go Power Factor = (2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistance Underground AC/Line Losses)

Power Transmitted using Load Current (1-Phase 2-Wire US)

Go Power Transmitted = Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2))

Power Factor using Load Current (1-Phase 2-Wire US)

Go Power Factor = (sqrt(2)*Power Transmitted)/(Maximum Voltage Underground AC*Current Underground AC)

Power Factor using Volume of Conductor Material (1-Phase 2-Wire US)

Go Power Factor = sqrt((2)*Constant Underground AC/Volume Of Conductor)

Power Factor using Constant (1-Phase 2-Wire US)

Go Power Factor = sqrt(2*Constant Underground AC/Volume Of Conductor)

Power Transmitted using Constant (1-Phase 2-Wire US) Formula

Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2))
P = sqrt(K*P_loss*(V_m^2)/(4*ρ*(L)^2))

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Power Transmitted using Constant (1-Phase 2-Wire US)?

Power Transmitted using Constant (1-Phase 2-Wire US) calculator uses Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2)) to calculate the Power Transmitted, The Power Transmitted using Constant (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations. Power Transmitted is denoted by P symbol.

How to calculate Power Transmitted using Constant (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Power Transmitted using Constant (1-Phase 2-Wire US), enter Constant Underground AC (K), Line Losses (P_loss), Maximum Voltage Underground AC (V_m), Resistivity (ρ) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Power Transmitted using Constant (1-Phase 2-Wire US) calculation can be explained with given input values -> 1771.24 = sqrt(0.87*2.67*(230^2)/(4*1.7E-05*(24)^2)).

FAQ

What is Power Transmitted using Constant (1-Phase 2-Wire US)?

The Power Transmitted using Constant (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations and is represented as P = sqrt(K*P_loss*(V_m^2)/(4*ρ*(L)^2)) or Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2)). Constant Underground AC is defined as the constant of line of a Overhead supply system, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Resistivity is the measure of how strongly a material opposes the flow of current through them & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Power Transmitted using Constant (1-Phase 2-Wire US)?

The Power Transmitted using Constant (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations is calculated using Power Transmitted = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Length of Underground AC Wire)^2)). To calculate Power Transmitted using Constant (1-Phase 2-Wire US), you need Constant Underground AC (K), Line Losses (P_loss), Maximum Voltage Underground AC (V_m), Resistivity (ρ) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Constant Underground AC, Line Losses, Maximum Voltage Underground AC, Resistivity & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Power Transmitted?

In this formula, Power Transmitted uses Constant Underground AC, Line Losses, Maximum Voltage Underground AC, Resistivity & Length of Underground AC Wire. We can use 5 other way(s) to calculate the same, which is/are as follows -

Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire))
Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2))
Power Transmitted = Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2))
Power Transmitted = sqrt(Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistivity*Length of Underground AC Wire))
Power Transmitted = sqrt(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistance Underground AC))

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