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Rate of effusion for the first gas by Graham's law Solution

STEP 0: Pre-Calculation Summary
Formula Used
rate_of_effusion_of_first_gas = (sqrt(Molar mass of second gas/Molar mass of first gas))*Rate of effusion of second gas
r1 = (sqrt(M2/M1))*r2
This formula uses 1 Functions, 3 Variables
Functions Used
sqrt - Squre root function, sqrt(Number)
Variables Used
Molar mass of second gas - The Molar mass of second gas is defined as the mass of the gas per mole. (Measured in Gram Per Mole)
Molar mass of first gas - The Molar mass of first gas is defined as the mass of the gas per mole. (Measured in Gram Per Mole)
Rate of effusion of second gas - The Rate of effusion of second gas is the special case of diffusion when the second gas allowed to escape through the small hole. (Measured in Meter³ per Second)
STEP 1: Convert Input(s) to Base Unit
Molar mass of second gas: 20.21 Gram Per Mole --> 0.02021 Kilogram Per Mole (Check conversion here)
Molar mass of first gas: 34.56 Gram Per Mole --> 0.03456 Kilogram Per Mole (Check conversion here)
Rate of effusion of second gas: 0.12 Meter³ per Second --> 0.12 Meter³ per Second No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
r1 = (sqrt(M2/M1))*r2 --> (sqrt(0.02021/0.03456))*0.12
Evaluating ... ...
r1 = 0.0917650986668316
STEP 3: Convert Result to Output's Unit
0.0917650986668316 Meter³ per Second --> No Conversion Required
FINAL ANSWER
0.0917650986668316 Meter³ per Second <-- Rate of effusion of first gas
(Calculation completed in 00.016 seconds)

8 Graham's Law Calculators

Rate of effusion for the second gas by Graham's law
rate_of_effusion_of_second_gas = Rate of effusion of first gas/(sqrt(Molar mass of second gas/Molar mass of first gas)) Go
Rate of effusion for the first gas by Graham's law
rate_of_effusion_of_first_gas = (sqrt(Molar mass of second gas/Molar mass of first gas))*Rate of effusion of second gas Go
Rate of effusion for the second gas if densities are given by Graham's law
rate_of_effusion_of_second_gas = Rate of effusion of first gas/(sqrt(Density of second gas/Density of first gas)) Go
Rate of effusion for the first gas if densities are given by Graham's law
rate_of_effusion_of_first_gas = (sqrt(Density of second gas/Density of first gas))*Rate of effusion of second gas Go
Molar mass of second gas by Graham's law
molar_mass_of_second_gas = ((Rate of effusion of first gas/Rate of effusion of second gas)^2)*Molar mass of first gas Go
Molar mass of first gas by Graham's law
molar_mass_of_first_gas = Molar mass of second gas/((Rate of effusion of first gas/Rate of effusion of second gas)^2) Go
Density of second gas by Graham's law
density_of_second_gas = ((Rate of effusion of first gas/Rate of effusion of second gas)^2)*Density of first gas Go
Density of first gas by Graham's law
density_of_first_gas = Density of second gas/((Rate of effusion of first gas/Rate of effusion of second gas)^2) Go

Rate of effusion for the first gas by Graham's law Formula

rate_of_effusion_of_first_gas = (sqrt(Molar mass of second gas/Molar mass of first gas))*Rate of effusion of second gas
r1 = (sqrt(M2/M1))*r2

What is Graham's law?

Graham's law of effusion (also called Graham's law of diffusion) was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles. Graham's law is most accurate for molecular effusion which involves the movement of one gas at a time through a hole. It is only approximate for diffusion of one gas in another or in air, as these processes involve the movement of more than one gas. In the same conditions of temperature and pressure, the molar mass is proportional to the mass density. Therefore, the rates of diffusion of different gases are inversely proportional to the square roots of their mass densities.

How to Calculate Rate of effusion for the first gas by Graham's law?

Rate of effusion for the first gas by Graham's law calculator uses rate_of_effusion_of_first_gas = (sqrt(Molar mass of second gas/Molar mass of first gas))*Rate of effusion of second gas to calculate the Rate of effusion of first gas, The Rate of effusion for the first gas by Graham's law formula is defined as rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. Rate of effusion of first gas and is denoted by r1 symbol.

How to calculate Rate of effusion for the first gas by Graham's law using this online calculator? To use this online calculator for Rate of effusion for the first gas by Graham's law, enter Molar mass of second gas (M2), Molar mass of first gas (M1) and Rate of effusion of second gas (r2) and hit the calculate button. Here is how the Rate of effusion for the first gas by Graham's law calculation can be explained with given input values -> 0.091765 = (sqrt(0.02021/0.03456))*0.12.

FAQ

What is Rate of effusion for the first gas by Graham's law?
The Rate of effusion for the first gas by Graham's law formula is defined as rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight and is represented as r1 = (sqrt(M2/M1))*r2 or rate_of_effusion_of_first_gas = (sqrt(Molar mass of second gas/Molar mass of first gas))*Rate of effusion of second gas. The Molar mass of second gas is defined as the mass of the gas per mole, The Molar mass of first gas is defined as the mass of the gas per mole and The Rate of effusion of second gas is the special case of diffusion when the second gas allowed to escape through the small hole.
How to calculate Rate of effusion for the first gas by Graham's law?
The Rate of effusion for the first gas by Graham's law formula is defined as rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight is calculated using rate_of_effusion_of_first_gas = (sqrt(Molar mass of second gas/Molar mass of first gas))*Rate of effusion of second gas. To calculate Rate of effusion for the first gas by Graham's law, you need Molar mass of second gas (M2), Molar mass of first gas (M1) and Rate of effusion of second gas (r2). With our tool, you need to enter the respective value for Molar mass of second gas, Molar mass of first gas and Rate of effusion of second gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Rate of effusion of first gas?
In this formula, Rate of effusion of first gas uses Molar mass of second gas, Molar mass of first gas and Rate of effusion of second gas. We can use 8 other way(s) to calculate the same, which is/are as follows -
  • rate_of_effusion_of_first_gas = (sqrt(Molar mass of second gas/Molar mass of first gas))*Rate of effusion of second gas
  • rate_of_effusion_of_second_gas = Rate of effusion of first gas/(sqrt(Molar mass of second gas/Molar mass of first gas))
  • molar_mass_of_first_gas = Molar mass of second gas/((Rate of effusion of first gas/Rate of effusion of second gas)^2)
  • molar_mass_of_second_gas = ((Rate of effusion of first gas/Rate of effusion of second gas)^2)*Molar mass of first gas
  • rate_of_effusion_of_first_gas = (sqrt(Density of second gas/Density of first gas))*Rate of effusion of second gas
  • rate_of_effusion_of_second_gas = Rate of effusion of first gas/(sqrt(Density of second gas/Density of first gas))
  • density_of_first_gas = Density of second gas/((Rate of effusion of first gas/Rate of effusion of second gas)^2)
  • density_of_second_gas = ((Rate of effusion of first gas/Rate of effusion of second gas)^2)*Density of first gas
Where is the Rate of effusion for the first gas by Graham's law calculator used?
Among many, Rate of effusion for the first gas by Graham's law calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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