Ratio of Molar Heat Capacity of Linear Molecule Solution

STEP 0: Pre-Calculation Summary
Formula Used
Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R])
This formula uses 1 Constants, 2 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324
Variables Used
Ratio of Molar Heat Capacity - The Ratio of Molar Heat Capacity is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume.
Atomicity - The Atomicity is defined as the total number of atoms present in a molecule or element.
STEP 1: Convert Input(s) to Base Unit
Atomicity: 3 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R]) --> ((((3*3)-2.5)*[R])+[R])/(((3*3)-2.5)*[R])
Evaluating ... ...
γ = 1.15384615384615
STEP 3: Convert Result to Output's Unit
1.15384615384615 --> No Conversion Required
FINAL ANSWER
1.15384615384615 1.153846 <-- Ratio of Molar Heat Capacity
(Calculation completed in 00.004 seconds)

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7 Ratio of Molar Heat Capacity Calculators

Ratio of Molar Heat Capacity of Linear Molecule
​ Go Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
Ratio of Molar Heat Capacity given Molar Heat Capacity at Constant Pressure
​ Go Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/(Molar Specific Heat Capacity at Constant Pressure-[R])
Ratio of Molar Heat Capacity given Molar Heat Capacity at Constant Volume
​ Go Ratio of Molar Heat Capacity = (Molar Specific Heat Capacity at Constant Volume+[R])/Molar Specific Heat Capacity at Constant Volume
Ratio of Molar Heat Capacity
​ Go Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume
Ratio Molar Heat Capacity given Compressibility
​ Go Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility
Ratio of Molar Heat Capacity of Non-Linear Molecule
​ Go Ratio of Molar Heat Capacity = (4+((3*Atomicity)-6))/(3+((3*Atomicity)-6))
Ratio of Molar Heat Capacity given Degree of Freedom
​ Go Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)

20 Important Formulae on Equipartition Principle and Heat Capacity Calculators

Internal Molar Energy of Non-Linear Molecule
​ Go Molar Internal Energy = ((3/2)*[R]*Temperature)+((0.5*Moment of Inertia along Y-axis*(Angular Velocity along Y-axis^2))+(0.5*Moment of Inertia along Z-axis*(Angular Velocity along Z-axis^2))+(0.5*Moment of Inertia along X-axis*(Angular Velocity along X-axis^2)))+((3*Atomicity)-6)*([R]*Temperature)
Internal Molar Energy of Linear Molecule
​ Go Molar Internal Energy = ((3/2)*[R]*Temperature)+((0.5*Moment of Inertia along Y-axis*(Angular Velocity along Y-axis^2))+(0.5*Moment of Inertia along Z-axis*(Angular Velocity along Z-axis^2)))+((3*Atomicity)-5)*([R]*Temperature)
Atomicity given Molar Heat Capacity at Constant Pressure and Volume of Linear Molecule
​ Go Atomicity = ((2.5*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-1.5)/((3*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-3)
Translational Energy
​ Go Translational Energy = ((Momentum along X-axis^2)/(2*Mass))+((Momentum along Y-axis^2)/(2*Mass))+((Momentum along Z-axis^2)/(2*Mass))
Molar Heat Capacity at Constant Pressure given Compressibility
​ Go Molar Specific Heat Capacity at Constant Pressure = (Isothermal Compressibility/Isentropic Compressibility)*Molar Specific Heat Capacity at Constant Volume
Ratio of Molar Heat Capacity of Linear Molecule
​ Go Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
Average Thermal Energy of Non-linear polyatomic Gas Molecule given Atomicity
​ Go Thermal Energy given Atomicity = ((6*Atomicity)-6)*(0.5*[BoltZ]*Temperature)
Average Thermal Energy of Linear Polyatomic Gas Molecule given Atomicity
​ Go Thermal Energy given Atomicity = ((6*Atomicity)-5)*(0.5*[BoltZ]*Temperature)
Total Kinetic Energy
​ Go Total Energy = Translational Energy+Rotational Energy+Vibrational Energy
Internal Molar Energy of Non-Linear Molecule given Atomicity
​ Go Molar Internal Energy = ((6*Atomicity)-6)*(0.5*[R]*Temperature)
Internal Molar Energy of Linear Molecule given Atomicity
​ Go Molar Internal Energy = ((6*Atomicity)-5)*(0.5*[R]*Temperature)
Atomicity given Molar Vibrational Energy of Non-Linear Molecule
​ Go Atomicity = ((Molar Vibrational Energy/([R]*Temperature))+6)/3
Molar Vibrational Energy of Non-Linear Molecule
​ Go Vibrational Molar Energy = ((3*Atomicity)-6)*([R]*Temperature)
Molar Vibrational Energy of Linear Molecule
​ Go Vibrational Molar Energy = ((3*Atomicity)-5)*([R]*Temperature)
Atomicity given Ratio of Molar Heat Capacity of Linear Molecule
​ Go Atomicity = ((2.5*Ratio of Molar Heat Capacity)-1.5)/((3*Ratio of Molar Heat Capacity)-3)
Number of Modes in Non-Linear Molecule
​ Go Number of Normal modes for Non Linear = (6*Atomicity)-6
Ratio of Molar Heat Capacity given Degree of Freedom
​ Go Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)
Degree of Freedom given Ratio of Molar Heat Capacity
​ Go Degree of Freedom = 2/(Ratio of Molar Heat Capacity-1)
Vibrational Mode of Linear Molecule
​ Go Number of Normal modes = (3*Atomicity)-5
Atomicity given Vibrational Degree of Freedom in Non-Linear Molecule
​ Go Atomicity = (Degree of Freedom+6)/3

Ratio of Molar Heat Capacity of Linear Molecule Formula

Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R])

What is the statement of Equipartition Theorem?

The original concept of equipartition was that the total kinetic energy of a system is shared equally among all of its independent parts, on the average, once the system has reached thermal equilibrium. Equipartition also makes quantitative predictions for these energies. The key point is that the kinetic energy is quadratic in the velocity. The equipartition theorem shows that in thermal equilibrium, any degree of freedom (such as a component of the position or velocity of a particle) which appears only quadratically in the energy has an average energy of ​1⁄2kBT and therefore contributes ​1⁄2kB to the system's heat capacity.

How to Calculate Ratio of Molar Heat Capacity of Linear Molecule?

Ratio of Molar Heat Capacity of Linear Molecule calculator uses Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R]) to calculate the Ratio of Molar Heat Capacity, The Ratio of Molar Heat Capacity of Linear Molecule is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume. Ratio of Molar Heat Capacity is denoted by γ symbol.

How to calculate Ratio of Molar Heat Capacity of Linear Molecule using this online calculator? To use this online calculator for Ratio of Molar Heat Capacity of Linear Molecule, enter Atomicity (N) and hit the calculate button. Here is how the Ratio of Molar Heat Capacity of Linear Molecule calculation can be explained with given input values -> 1.153846 = ((((3*3)-2.5)*[R])+[R])/(((3*3)-2.5)*[R]).

FAQ

What is Ratio of Molar Heat Capacity of Linear Molecule?
The Ratio of Molar Heat Capacity of Linear Molecule is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume and is represented as γ = ((((3*N)-2.5)*[R])+[R])/(((3*N)-2.5)*[R]) or Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R]). The Atomicity is defined as the total number of atoms present in a molecule or element.
How to calculate Ratio of Molar Heat Capacity of Linear Molecule?
The Ratio of Molar Heat Capacity of Linear Molecule is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume is calculated using Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R]). To calculate Ratio of Molar Heat Capacity of Linear Molecule, you need Atomicity (N). With our tool, you need to enter the respective value for Atomicity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Ratio of Molar Heat Capacity?
In this formula, Ratio of Molar Heat Capacity uses Atomicity. We can use 7 other way(s) to calculate the same, which is/are as follows -
  • Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume
  • Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)
  • Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/(Molar Specific Heat Capacity at Constant Pressure-[R])
  • Ratio of Molar Heat Capacity = (Molar Specific Heat Capacity at Constant Volume+[R])/Molar Specific Heat Capacity at Constant Volume
  • Ratio of Molar Heat Capacity = (4+((3*Atomicity)-6))/(3+((3*Atomicity)-6))
  • Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility
  • Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)
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